假设我有一个类

public class ItemController:Controller
{
    public ActionResult Login(int id)
    {
        return View("Hi", id);
    }
}

在ItemController所在的Item文件夹之外的页面上,我想创建一个指向Login方法的链接。所以是哪种Html。我应该使用ActionLink方法,我应该传递什么参数?

具体来说,我正在寻找替代的方法

Html.ActionLink(article.Title,
    new { controller = "Articles", action = "Details",
          id = article.ArticleID })

在最近的ASP中已经退役。NET MVC的化身。


Html.ActionLink(article.Title, "Login/" + article.ArticleID, 'Item") 

我认为你想要的是:

ASP。净MVC1

Html.ActionLink(article.Title, 
                "Login",  // <-- Controller Name.
                "Item",   // <-- ActionMethod
                new { id = article.ArticleID }, // <-- Route arguments.
                null  // <-- htmlArguments .. which are none. You need this value
                      //     otherwise you call the WRONG method ...
                      //     (refer to comments, below).
                )

这使用了下面的方法ActionLink签名:

public static string ActionLink(this HtmlHelper htmlHelper, 
                                string linkText,
                                string controllerName,
                                string actionName,
                                object values, 
                                object htmlAttributes)

ASP。净MVC2

有两个论点被调换了

Html.ActionLink(article.Title, 
                "Item",   // <-- ActionMethod
                "Login",  // <-- Controller Name.
                new { id = article.ArticleID }, // <-- Route arguments.
                null  // <-- htmlArguments .. which are none. You need this value
                      //     otherwise you call the WRONG method ...
                      //     (refer to comments, below).
                )

这使用了下面的方法ActionLink签名:

public static string ActionLink(this HtmlHelper htmlHelper, 
                                string linkText,
                                string actionName,
                                string controllerName,
                                object values, 
                                object htmlAttributes)

ASP.NET MVC3+

参数的顺序与MVC2相同,但是id值不再是必需的:

Html.ActionLink(article.Title, 
                "Item",   // <-- ActionMethod
                "Login",  // <-- Controller Name.
                new { article.ArticleID }, // <-- Route arguments.
                null  // <-- htmlArguments .. which are none. You need this value
                      //     otherwise you call the WRONG method ...
                      //     (refer to comments, below).
                )

这避免了将任何路由逻辑硬编码到链接中。

 <a href="/Item/Login/5">Title</a> 

这将为您提供以下html输出,假设:

篇文章。标题= "标题" 篇文章。ArticleID = 5 您仍然定义了以下路由

. .

routes.MapRoute(
    "Default",     // Route name
    "{controller}/{action}/{id}",                           // URL with parameters
    new { controller = "Home", action = "Index", id = "" }  // Parameter defaults
);

您可能想看看RouteLink()方法。它允许您通过字典指定所有内容(除了链接文本和路由名称)。


我想补充一下金怒的回答。他提供了解决方案,但一开始我也不能让它工作,并得到了像Adhip Gupta一样的结果。然后我意识到,路由必须首先存在,参数必须与路由完全匹配。所以我有一个id,然后一个文本参数我的路线,这也需要包括在内。

Html.ActionLink(article.Title, "Login", "Item", new { id = article.ArticleID, title = article.Title }, null)

我认为Joseph翻转了控制器和动作。首先是动作,然后是控制器。这个签名看起来有点奇怪。

为了澄清一些事情,这是一个有效的版本(改编自约瑟夫的例子):

Html.ActionLink(article.Title, 
    "Login",  // <-- ActionMethod
    "Item",   // <-- Controller Name
    new { id = article.ArticleID }, // <-- Route arguments.
    null  // <-- htmlArguments .. which are none
    )

这个呢

<%=Html.ActionLink("Get Involved", 
                   "Show", 
                   "Home", 
                   new 
                       { 
                           id = "GetInvolved" 
                       }, 
                   new { 
                           @class = "menuitem", 
                           id = "menu_getinvolved" 
                       }
                   )%>

如果你想要花哨的裤子,下面是你如何扩展它来做到这一点:

@(Html.ActionLink<ArticlesController>(x => x.Details(), article.Title, new { id = article.ArticleID }))

你需要把它放在System.Web.Mvc命名空间中:

public static class MyProjectExtensions
{
    public static MvcHtmlString ActionLink<TController>(this HtmlHelper htmlHelper, Expression<Action<TController>> expression, string linkText)
    {
        var urlHelper = new UrlHelper(htmlHelper.ViewContext.RequestContext, htmlHelper.RouteCollection);

        var link = new TagBuilder("a");

        string actionName = ExpressionHelper.GetExpressionText(expression);
        string controllerName = typeof(TController).Name.Replace("Controller", "");

        link.MergeAttribute("href", urlHelper.Action(actionName, controllerName));
        link.SetInnerText(linkText);

        return new MvcHtmlString(link.ToString());
    }

    public static MvcHtmlString ActionLink<TController, TAction>(this HtmlHelper htmlHelper, Expression<Action<TController, TAction>> expression, string linkText, object routeValues)
    {
        var urlHelper = new UrlHelper(htmlHelper.ViewContext.RequestContext, htmlHelper.RouteCollection);

        var link = new TagBuilder("a");

        string actionName = ExpressionHelper.GetExpressionText(expression);
        string controllerName = typeof(TController).Name.Replace("Controller", "");

        link.MergeAttribute("href", urlHelper.Action(actionName, controllerName, routeValues));
        link.SetInnerText(linkText);

        return new MvcHtmlString(link.ToString());
    }

    public static MvcHtmlString ActionLink<TController>(this HtmlHelper htmlHelper, Expression<Action<TController>> expression, string linkText, object routeValues, object htmlAttributes) where TController : Controller
    {
        var urlHelper = new UrlHelper(htmlHelper.ViewContext.RequestContext, htmlHelper.RouteCollection);

        var attributes = AnonymousObjectToKeyValue(htmlAttributes);

        var link = new TagBuilder("a");

        string actionName = ExpressionHelper.GetExpressionText(expression);
        string controllerName = typeof(TController).Name.Replace("Controller", "");

        link.MergeAttribute("href", urlHelper.Action(actionName, controllerName, routeValues));
        link.MergeAttributes(attributes, true);
        link.SetInnerText(linkText);

        return new MvcHtmlString(link.ToString());
    }

    private static Dictionary<string, object> AnonymousObjectToKeyValue(object anonymousObject)
    {
        var dictionary = new Dictionary<string, object>();

        if (anonymousObject == null) return dictionary;

        foreach (PropertyDescriptor propertyDescriptor in TypeDescriptor.GetProperties(anonymousObject))
        {
            dictionary.Add(propertyDescriptor.Name, propertyDescriptor.GetValue(anonymousObject));
        }

        return dictionary;
    }
}

这包括两个覆盖的路由值和HTML属性,而且,你所有的视图将需要添加:@using YourProject。控制器或者你可以把它添加到你的网页。配置<页> <名称>


与MVC5我已经这样做了,它是100%的工作代码....

@Html.ActionLink(department.Name, "Index", "Employee", new { 
                            departmentId = department.DepartmentID }, null)

你们可以从中得到启发…


为了可读性和避免混淆,使用命名参数。

@Html.ActionLink(
            linkText: "Click Here",
            actionName: "Action",
            controllerName: "Home",
            routeValues: new { Identity = 2577 },
            htmlAttributes: null)

这种类型使用:

@Html.ActionLink(“主页”,“索引”,“主页”)

MainPage:文本的名称 索引:动作视图 Home: homeecontroller

基本使用ActionLink

<html> <head> <meta name="viewport" content="width=device-width" /> <title>_Layout</title> <link href="@Url.Content("~/Content/bootsrap.min.css")" rel="stylesheet" type="text/css" /> </head> <body> <div class="container"> <div class="col-md-12"> <button class="btn btn-default" type="submit">@Html.ActionLink("AnaSayfa","Index","Home")</button> <button class="btn btn-default" type="submit">@Html.ActionLink("Hakkımızda", "Hakkimizda", "Home")</button> <button class="btn btn-default" type="submit">@Html.ActionLink("Iletişim", "Iletisim", "Home")</button> </div> @RenderBody() <div class="col-md-12" style="height:200px;background-image:url(/img/footer.jpg)"> </div> </div> </body> </html>