如果你想存储你从响应中得到的整个对象，它可以通过这样做来实现，

首先，在util类中创建一个将JSON转换为字符串的方法，如下所示。

 public static <T> T fromJson(String jsonString, Class<T> theClass) {
    return new Gson().fromJson(jsonString, theClass);
}

然后在共享偏好类中执行如下操作，

 public void storeLoginResponse(yourResponseClass objName) {

    String loginJSON = UtilClass.toJson(customer);
    if (!TextUtils.isEmpty(customerJSON)) {
        editor.putString(AppConst.PREF_CUSTOMER, customerJSON);
        editor.commit();
    }
}

然后为getPreferences创建一个方法

public Customer getCustomerDetails() {
    String customerDetail = pref.getString(AppConst.PREF_CUSTOMER, null);
    if (!TextUtils.isEmpty(customerDetail)) {
        return GSONConverter.fromJson(customerDetail, Customer.class);
    } else {
        return new Customer();
    }
}

然后只是调用第一个方法时，你得到的响应和 其次，当你需要从分享偏好中获取数据时

String token = SharedPrefHelper.get().getCustomerDetails().getAccessToken();

这是所有。

希望对你有所帮助。

快乐的编码();

你可以保存对象在首选项不使用任何库，首先你的对象类必须实现Serializable:

public class callModel implements Serializable {

private long pointTime;
private boolean callisConnected;

public callModel(boolean callisConnected,  long pointTime) {
    this.callisConnected = callisConnected;
    this.pointTime = pointTime;
}
public boolean isCallisConnected() {
    return callisConnected;
}
public long getPointTime() {
    return pointTime;
}

}

然后你可以很容易地使用这两个方法来转换对象到字符串和字符串到对象:

 public static <T extends Serializable> T stringToObjectS(String string) {
    byte[] bytes = Base64.decode(string, 0);
    T object = null;
    try {
        ObjectInputStream objectInputStream = new ObjectInputStream(new ByteArrayInputStream(bytes));
        object = (T) objectInputStream.readObject();
    } catch (Exception e) {
        e.printStackTrace();
    }
    return object;
}

 public static String objectToString(Parcelable object) {
    String encoded = null;
    try {
        ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
        ObjectOutputStream objectOutputStream = new ObjectOutputStream(byteArrayOutputStream);
        objectOutputStream.writeObject(object);
        objectOutputStream.close();
        encoded = new String(Base64.encodeToString(byteArrayOutputStream.toByteArray(), 0));
    } catch (IOException e) {
        e.printStackTrace();
    }
    return encoded;
}

保存:

SharedPreferences  mPrefs = getPreferences(MODE_PRIVATE);
Editor prefsEditor = mPrefs.edit();
prefsEditor.putString("MyObject", objectToString(callModelObject));
prefsEditor.commit();

阅读

String value= mPrefs.getString("MyObject", "");
MyObject obj = stringToObjectS(value);

如果你的对象很复杂，我建议序列化/XML/JSON，并将这些内容保存到SD卡。你可以在这里找到关于如何保存到外部存储的其他信息: http://developer.android.com/guide/topics/data/data-storage.html#filesExternal

有两个文件解决了共享首选项的所有问题

1)AppPersistence.java

    public class AppPersistence {
    public enum keys {
        USER_NAME, USER_ID, USER_NUMBER, USER_EMAIL, USER_ADDRESS, CITY, USER_IMAGE,
        DOB, MRG_Anniversary, COMPANY, USER_TYPE, support_phone
    }

    private static AppPersistence mAppPersistance;
    private SharedPreferences sharedPreferences;

    public static AppPersistence start(Context context) {
        if (mAppPersistance == null) {
            mAppPersistance = new AppPersistence(context);
        }
        return mAppPersistance;
    }

    private AppPersistence(Context context) {
        sharedPreferences = context.getSharedPreferences(context.getString(R.string.prefrence_file_name),
                Context.MODE_PRIVATE);
    }

    public Object get(Enum key) {
        Map<String, ?> all = sharedPreferences.getAll();
        return all.get(key.toString());
    }

    void save(Enum key, Object val) {
        SharedPreferences.Editor editor = sharedPreferences.edit();
        if (val instanceof Integer) {
            editor.putInt(key.toString(), (Integer) val);
        } else if (val instanceof String) {
            editor.putString(key.toString(), String.valueOf(val));
        } else if (val instanceof Float) {
            editor.putFloat(key.toString(), (Float) val);
        } else if (val instanceof Long) {
            editor.putLong(key.toString(), (Long) val);
        } else if (val instanceof Boolean) {
            editor.putBoolean(key.toString(), (Boolean) val);
        }
        editor.apply();
    }

    void remove(Enum key) {
        SharedPreferences.Editor editor = sharedPreferences.edit();
        editor.remove(key.toString());
        editor.apply();
    }

    public void removeAll() {
        SharedPreferences.Editor editor = sharedPreferences.edit();
        editor.clear();
        editor.apply();
    }
}

2)AppPreference.java

public static void setPreference(Context context, Enum Name, String Value) {
        AppPersistence.start(context).save(Name, Value);
    }

    public static String getPreference(Context context, Enum Name) {
        return (String) AppPersistence.start(context).get(Name);
    }

    public static void removePreference(Context context, Enum Name) {
        AppPersistence.start(context).remove(Name);
    }
}

现在你可以保存，删除或者获取，

保存

AppPreference.setPreference(context, AppPersistence.keys.USER_ID, userID);

删除

AppPreference.removePreference(context, AppPersistence.keys.USER_ID);

-get

 AppPreference.getPreference(context, AppPersistence.keys.USER_ID);

我知道这个帖子有点旧了。 但我还是要把这个贴出来，希望它能帮助到一些人。 通过将对象序列化为String，可以将任何Object的字段存储为共享首选项。 这里我使用GSON存储共享首选项的任何对象。

保存对象到首选项:

public static void saveObjectToSharedPreference(Context context, String preferenceFileName, String serializedObjectKey, Object object) {
    SharedPreferences sharedPreferences = context.getSharedPreferences(preferenceFileName, 0);
    SharedPreferences.Editor sharedPreferencesEditor = sharedPreferences.edit();
    final Gson gson = new Gson();
    String serializedObject = gson.toJson(object);
    sharedPreferencesEditor.putString(serializedObjectKey, serializedObject);
    sharedPreferencesEditor.apply();
}

从首选项检索对象:

public static <GenericClass> GenericClass getSavedObjectFromPreference(Context context, String preferenceFileName, String preferenceKey, Class<GenericClass> classType) {
    SharedPreferences sharedPreferences = context.getSharedPreferences(preferenceFileName, 0);
    if (sharedPreferences.contains(preferenceKey)) {
        final Gson gson = new Gson();
        return gson.fromJson(sharedPreferences.getString(preferenceKey, ""), classType);
    }
    return null;
}

注意:

记得在gradle的dependencies中添加compile 'com.google.code.gson:gson:2.6.2'。

例子:

//assume SampleClass exists
SampleClass mObject = new SampleObject();

//to store an object
saveObjectToSharedPreference(context, "mPreference", "mObjectKey", mObject);

//to retrive object stored in preference
mObject = getSavedObjectFromPreference(context, "mPreference", "mObjectKey", SampleClass.class);

更新:

正如@Sharp_Edge在评论中指出的那样，上述解决方案不适用于List。

稍微修改一下getSavedObjectFromPreference()的签名——从Class<GenericClass> classType到Type classType将使这个解决方案一般化。修改后的函数签名

public static <GenericClass> GenericClass getSavedObjectFromPreference(Context context, String preferenceFileName, String preferenceKey, Type classType)

用于调用,

getSavedObjectFromPreference(context, "mPreference", "mObjectKey", (Type) SampleClass.class)

编码快乐!

我已经使用jackson来存储我的对象(jackson)。

添加杰克逊库到gradle:

api 'com.fasterxml.jackson.core:jackson-core:2.9.4'
api 'com.fasterxml.jackson.core:jackson-annotations:2.9.4'
api 'com.fasterxml.jackson.core:jackson-databind:2.9.4'

我的测试类:

public class Car {
    private String color;
    private String type;
    // standard getters setters
}

Java对象转换为JSON:

ObjectMapper objectMapper = new ObjectMapper();
String carAsString = objectMapper.writeValueAsString(car);

存储在共享首选项中:

preferences.edit().car().put(carAsString).apply();

从共享首选项中恢复:

ObjectMapper objectMapper = new ObjectMapper();
Car car = objectMapper.readValue(preferences.car().get(), Car.class);