我一直在看杰克逊,但似乎我必须将地图转换为JSON,然后将结果JSON转换为POJO。
是否有方法将Map直接转换为POJO?
我一直在看杰克逊,但似乎我必须将地图转换为JSON,然后将结果JSON转换为POJO。
是否有方法将Map直接转换为POJO?
是的,它绝对可以避免到JSON的中间转换。使用像Dozer这样的深度复制工具,你可以直接将地图转换为POJO。下面是一个简单的例子:
示例POJO:
public class MyPojo implements Serializable {
private static final long serialVersionUID = 1L;
private String id;
private String name;
private Integer age;
private Double savings;
public MyPojo() {
super();
}
// Getters/setters
@Override
public String toString() {
return String.format(
"MyPojo[id = %s, name = %s, age = %s, savings = %s]", getId(),
getName(), getAge(), getSavings());
}
}
转换代码示例:
public class CopyTest {
@Test
public void testCopyMapToPOJO() throws Exception {
final Map<String, String> map = new HashMap<String, String>(4);
map.put("id", "5");
map.put("name", "Bob");
map.put("age", "23");
map.put("savings", "2500.39");
map.put("extra", "foo");
final DozerBeanMapper mapper = new DozerBeanMapper();
final MyPojo pojo = mapper.map(map, MyPojo.class);
System.out.println(pojo);
}
}
输出:
MyPojo[id = 5,名字= Bob,年龄= 23,存款= 2500.39]
注意:如果你将源映射更改为map <String, Object>,那么你可以复制任意深度嵌套的属性(使用map <String, String>,你只能得到一层)。
杰克逊也能做到这一点。(而且自从你考虑使用jackson后,它似乎更舒服)。
使用ObjectMapper的convertValue方法:
final ObjectMapper mapper = new ObjectMapper(); // jackson's objectmapper
final MyPojo pojo = mapper.convertValue(map, MyPojo.class);
不需要转换成JSON字符串或其他东西;直接转换要快得多。
与Gson的解决方案:
Gson gson = new Gson();
JsonElement jsonElement = gson.toJsonTree(map);
MyPojo pojo = gson.fromJson(jsonElement, MyPojo.class);
我对Jackson和BeanUtils都进行了测试,发现BeanUtils要快得多。 在我的机器(Windows8.1, JDK1.7)中,我得到了这个结果。
BeanUtils t2-t1 = 286
Jackson t2-t1 = 2203
public class MainMapToPOJO {
public static final int LOOP_MAX_COUNT = 1000;
public static void main(String[] args) {
Map<String, Object> map = new HashMap<>();
map.put("success", true);
map.put("data", "testString");
runBeanUtilsPopulate(map);
runJacksonMapper(map);
}
private static void runBeanUtilsPopulate(Map<String, Object> map) {
long t1 = System.currentTimeMillis();
for (int i = 0; i < LOOP_MAX_COUNT; i++) {
try {
TestClass bean = new TestClass();
BeanUtils.populate(bean, map);
} catch (IllegalAccessException e) {
e.printStackTrace();
} catch (InvocationTargetException e) {
e.printStackTrace();
}
}
long t2 = System.currentTimeMillis();
System.out.println("BeanUtils t2-t1 = " + String.valueOf(t2 - t1));
}
private static void runJacksonMapper(Map<String, Object> map) {
long t1 = System.currentTimeMillis();
for (int i = 0; i < LOOP_MAX_COUNT; i++) {
ObjectMapper mapper = new ObjectMapper();
TestClass testClass = mapper.convertValue(map, TestClass.class);
}
long t2 = System.currentTimeMillis();
System.out.println("Jackson t2-t1 = " + String.valueOf(t2 - t1));
}}
如果你的类中有泛型类型,你应该使用TypeReference和convertValue()。
final ObjectMapper mapper = new ObjectMapper();
final MyPojo<MyGenericType> pojo = mapper.convertValue(map, new TypeReference<MyPojo<MyGenericType>>() {});
你也可以用它把pojo转换回java.util.Map。
final ObjectMapper mapper = new ObjectMapper();
final Map<String, Object> map = mapper.convertValue(pojo, new TypeReference<Map<String, Object>>() {});
将Map转换为POJO的例子。注意Map键包含下划线,字段变量是驼峰。
用户阶层POJO。
import com.fasterxml.jackson.annotation.JsonProperty;
import lombok.Data;
@Data
public class User {
@JsonProperty("user_name")
private String userName;
@JsonProperty("pass_word")
private String passWord;
}
class测试这个例子
import java.util.HashMap;
import java.util.Map;
import com.fasterxml.jackson.databind.ObjectMapper;
public class App {
public static void main(String[] args) {
Map<String, String> info = new HashMap<>();
info.put("user_name", "Q10Viking");
info.put("pass_word", "123456");
ObjectMapper mapper = new ObjectMapper();
User user = mapper.convertValue(info, User.class);
System.out.println("-------------------------------");
System.out.println(user);
}
}
/**output
-------------------------------
User(userName=Q10Viking, passWord=123456)
*/
@Hamedz 如果使用较多的数据,则使用Jackson进行转换 光数据,使用apache… TestCase:
import java.lang.reflect.InvocationTargetException; import java.util.HashMap; import java.util.Map; import org.apache.commons.beanutils.BeanUtils; import com.fasterxml.jackson.databind.ObjectMapper; import lombok.AllArgsConstructor; import lombok.Data; import lombok.NoArgsConstructor; public class TestPerf { public static final int LOOP_MAX_COUNT = 1000; public static void main(String[] args) { Map<String, Object> map = new HashMap<>(); map.put("success", true); map.put("number", 1000); map.put("longer", 1000L); map.put("doubler", 1000D); map.put("data1", "testString"); map.put("data2", "testString"); map.put("data3", "testString"); map.put("data4", "testString"); map.put("data5", "testString"); map.put("data6", "testString"); map.put("data7", "testString"); map.put("data8", "testString"); map.put("data9", "testString"); map.put("data10", "testString"); runBeanUtilsPopulate(map); runJacksonMapper(map); } private static void runBeanUtilsPopulate(Map<String, Object> map) { long t1 = System.currentTimeMillis(); for (int i = 0; i < LOOP_MAX_COUNT; i++) { try { TestClass bean = new TestClass(); BeanUtils.populate(bean, map); } catch (IllegalAccessException e) { e.printStackTrace(); } catch (InvocationTargetException e) { e.printStackTrace(); } } long t2 = System.currentTimeMillis(); System.out.println("BeanUtils t2-t1 = " + String.valueOf(t2 - t1)); } private static void runJacksonMapper(Map<String, Object> map) { long t1 = System.currentTimeMillis(); for (int i = 0; i < LOOP_MAX_COUNT; i++) { ObjectMapper mapper = new ObjectMapper(); TestClass testClass = mapper.convertValue(map, TestClass.class); } long t2 = System.currentTimeMillis(); System.out.println("Jackson t2-t1 = " + String.valueOf(t2 - t1)); } @Data @AllArgsConstructor @NoArgsConstructor public static class TestClass { private Boolean success; private Integer number; private Long longer; private Double doubler; private String data1; private String data2; private String data3; private String data4; private String data5; private String data6; private String data7; private String data8; private String data9; private String data10; } }到目前为止,使用Jackson提供的答案是很好的,但是你仍然可以有一个util函数来帮助你转换不同的pojo,如下所示:
public static <T> T convert(Map<String, Object> aMap, Class<T> t) {
try {
return objectMapper
.convertValue(aMap, objectMapper.getTypeFactory().constructType(t));
} catch (Exception e) {
log.error("converting failed! aMap: {}, class: {}", getJsonString(aMap), t.getClass().getSimpleName(), e);
}
return null;
}
ObjectMapper objectMapper = new ObjectMapper();
// Use this if all properties are not in the class
objectMapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
final MyPojo pojo = objectMapper.convertValue(map, MyPojo.class);
与第一个答案相同,但我得到了一个错误使用,因为我不希望Map的所有属性转换为类。我还找到了objectmap .configure(反序列化特性。FAIL_ON_UNKNOWN_PROPERTIES、假);作为解决方案。