如何在UITableView中改变section头的颜色?

编辑:DJ-S提供的答案应该适用于iOS 6及以上版本。公认的答案已经过时了。


当前回答

Swift使它变得非常简单。只需将其添加到类中,并根据需要设置颜色。

override func tableView(_ tableView: UITableView, willDisplayHeaderView view: UIView, forSection section: Int) {
        view.backgroundColor = UIColor(red: 0.094, green: 0.239, blue: 0.424, alpha: 1.0)
    }

或者是简单的颜色

override func tableView(_ tableView: UITableView, willDisplayHeaderView view: UIView, forSection section: Int) {
        view.backgroundColor = UIColor.white
    }

Swift 5更新

override func tableView(_ tableView: UITableView, willDisplayHeaderView view: UIView, forSection section: Int) {
        view.tintColor = UIColor(red: 0.094, green: 0.239, blue: 0.424, alpha: 1.0)
    }

或者是简单的颜色

override func tableView(_ tableView: UITableView, willDisplayHeaderView view: UIView, forSection section: Int) {
        view.tintColor = UIColor.white
    }

其他回答

你可以这样做,如果你想头部自定义颜色。自iOS 6.0以来,这个解决方案工作得很好。

Objective - C:

[[UITableViewHeaderFooterView appearance] setTintColor:[UIColor redColor]];

迅速:

UITableViewHeaderFooterView.appearance().tintColor = .white

在我的例子中,它是这样工作的:

let headerIdentifier = "HeaderIdentifier"
let header = self.tableView.dequeueReusableHeaderFooterView(withIdentifier: headerIdentifier)
header.contentView.backgroundColor = UIColor.white
 -(void) tableView:(UITableView *)tableView willDisplayHeaderView:(UIView *)view
  forSection:(NSInteger)section
  {
        if ([view isKindOfClass: [UITableViewHeaderFooterView class]])
        {
             UITableViewHeaderFooterView *castView = (UITableViewHeaderFooterView *) view;
             UIView *content = castView.contentView;
             UIColor *color = [UIColor whiteColor]; // substitute your color here
             content.backgroundColor = color;
             [castView.textLabel setTextColor:[UIColor blackColor]];
        }
 }

iOS 13> swift 5

func tableView(_ tableView: UITableView, willDisplayHeaderView view: UIView, forSection section: Int){视图。tintColor = UIColor。红}

In iOS 7.0.4 I created a custom header with it's own XIB. Nothing mentioned here before worked. It had to be the subclass of the UITableViewHeaderFooterView to work with the dequeueReusableHeaderFooterViewWithIdentifier: and it seems that class is very stubborn regarding the background color. So finally I added an UIView (you could do it either with code or IB) with name customBackgroudView, and then set it's backgroundColor property. In layoutSubviews: I set that view's frame to bounds. It work with iOS 7 and gives no glitches.

// in MyTableHeaderView.xib drop an UIView at top of the first child of the owner
// first child becomes contentView

// in MyTableHeaderView.h
@property (nonatomic, weak) IBOutlet UIView * customBackgroundView;

// in MyTableHeaderView.m
-(void)layoutSubviews;
{
    [super layoutSubviews];

    self.customBackgroundView.frame = self.bounds;
}
// if you don't have XIB / use IB, put in the initializer:
-(id)initWithReuseIdentifier:(NSString *)reuseIdentifier
{
    ...
    UIView * customBackgroundView = [[UIView alloc] init];
    [self.contentView addSubview:customBackgroundView];
    _customBackgroundView = customBackgroundView;
    ...
}


// in MyTableViewController.m
-(UIView *)tableView:(UITableView *)tableView viewForHeaderInSection:(NSInteger)section
{
    MyTableHeaderView * header = [self.tableView
                                          dequeueReusableHeaderFooterViewWithIdentifier:@"MyTableHeaderView"];
    header.customBackgroundView.backgroundColor = [UIColor redColor];
    return header;
}