如何在c#中找到一个月的最后一天?

例如,如果我有日期03/08/1980,我如何得到第8个月的最后一天(在本例中是31)?


当前回答

要获得特定日历中一个月的最后一天-并在扩展方法中-:

public static int DaysInMonthBy(this DateTime src, Calendar calendar)
{
    var year = calendar.GetYear(src);                   // year of src in your calendar
    var month = calendar.GetMonth(src);                 // month of src in your calendar
    var lastDay = calendar.GetDaysInMonth(year, month); // days in month means last day of that month in your calendar
    return lastDay;
}

其他回答

var lastDayOfMonth = DateTime.DaysInMonth(date.Year, date.Month);

您可以按以下方式扩展DateTime;

public static class DateTimeMethods
{
    public static DateTime StartOfMonth(this DateTime date)
    {
        return new DateTime(date.Year, date.Month, 1, 0, 0, 0);
    }

    public static DateTime EndOfMonth(this DateTime date)
    {
        return date.StartOfMonth().AddMonths(1).AddSeconds(-1);
    }
}

像这样使用它;

DateTime today = DateTime.Now;

DateTime startOfMonth = today.StartOfMonth();
DateTime endOfMonth = today.EndOfMonth();
// Use any date you want, for the purpose of this example we use 1980-08-03.
var myDate = new DateTime(1980,8,3);
var lastDayOfMonth = new DateTime(myDate.Year, myDate.Month, DateTime.DaysInMonth(myDate.Year, myDate.Month));

我不懂c#,但是,如果没有一个方便的API方法来获得它,其中一种方法是遵循以下逻辑:

today -> +1 month -> set day of month to 1 -> -1 day

当然,前提是你有这种类型的约会数学。

你可以通过下面的代码找到任何月份的最后一天:

var now = DateTime.Now;
var startOfMonth = new DateTime(now.Year, now.Month, 1);
var DaysInMonth = DateTime.DaysInMonth(now.Year, now.Month);
var lastDay = new DateTime(now.Year, now.Month, DaysInMonth);