在Swift 4修剪空白

let strFirstName = txtFirstName.text?.trimmingCharacters(in: 
 CharacterSet.whitespaces)

嗨，这可能有点晚，但值得一试。这是一个游乐场的文件。你可以让它成为一个字符串扩展名。

这是在Swift 5.3中编写的

方法1:

var str = "\n \tHello, playground       "
if let regexp = try? NSRegularExpression(pattern: "^\\s+", options: NSRegularExpression.Options.caseInsensitive) {
    let mstr = NSMutableString(string: str)
    regexp.replaceMatches(in: mstr, options: [], range: NSRange(location: 0, length: str.count), withTemplate: "")
    str = mstr as String
}

Result: "Hello, playground       "

方法2:

if let c = (str.first { !($0 == " " || $0 == "\t" || $0 == "\n") }) {
    if let nonWhiteSpaceIndex = str.firstIndex(of: c) {
        str.replaceSubrange(str.startIndex ..< nonWhiteSpaceIndex, with: "")
    }
}

Result: "Hello, playground       "

你也可以使用正则表达式。

let trimmedString = myString.stringByReplacingOccurrencesOfString("\\s", withString: "", options: NSStringCompareOptions.RegularExpressionSearch, range: nil)

Swift 3版本

  //This function trim only white space:
   func trim() -> String
        {
            return self.trimmingCharacters(in: CharacterSet.whitespaces)
        }
    //This function trim whitespeaces and new line that you enter:
     func trimWhiteSpaceAndNewLine() -> String
        {
            return self.trimmingCharacters(in: CharacterSet.whitespacesAndNewlines)
        }

你也可以试试这个

   let updatedString = searchedText?.stringByReplacingOccurrencesOfString(" ", withString: "-")

对于swift 3.0

import Foundation

var str = " Hear me calling"

extension String {
    var stringByRemovingWhitespaces: String {
        return components(separatedBy: .whitespaces).joined()
    }
}

str.stringByRemovingWhitespaces  // Hearmecalling