从技术上讲，这不是对原始问题的回答，但由于这里的许多帖子都给出了删除所有空白的答案，这里是一个更新的、更简洁的版本:

let stringWithouTAnyWhitespace = string.filter {!$0.isWhitespace}

羽毛球猫的答案的Swift 3版本

extension String {
    func replace(_ string:String, replacement:String) -> String {
        return self.replacingOccurrences(of: string, with: replacement, options: NSString.CompareOptions.literal, range: nil)
    }

    func removeWhitespace() -> String {
        return self.replace(" ", replacement: "")
    }
}

你也可以试试这个

   let updatedString = searchedText?.stringByReplacingOccurrencesOfString(" ", withString: "-")

这在swift 5中很管用

var myString = " Kwame Ch ef "
myString = myString.replacingOccurrences(of: " ", with: "")
print(myString)

output: Kwame Chef

extension String {

    var removingWhitespaceAndNewLines: String {
        return removing(.whitespacesAndNewlines)
    }

    func removing(_ forbiddenCharacters: CharacterSet) -> String {
        return String(unicodeScalars.filter({ !forbiddenCharacters.contains($0) }))
    }
}

你也可以使用正则表达式。

let trimmedString = myString.stringByReplacingOccurrencesOfString("\\s", withString: "", options: NSStringCompareOptions.RegularExpressionSearch, range: nil)