用MySQL计算中位数最简单(希望不会太慢)的方法是什么?我已经使用AVG(x)来寻找平均值,但我很难找到一个简单的方法来计算中位数。现在,我将所有的行返回到PHP,进行排序,然后选择中间的行,但是肯定有一些简单的方法可以在一个MySQL查询中完成它。

示例数据:

id | val
--------
 1    4
 2    7
 3    2
 4    2
 5    9
 6    8
 7    3

对val排序得到2 2 3 4 7 8 9,因此中位数应该是4,而SELECT AVG(val) == 5。


当前回答

MySQL从8.0版本开始支持窗口函数,您可以使用ROW_NUMBER或DENSE_RANK(不要使用RANK,因为它将相同的RANK分配给相同的值,就像在体育排名):

SELECT AVG(t1.val) AS median_val
  FROM (SELECT val, 
               ROW_NUMBER() OVER(ORDER BY val) AS rownum
          FROM data) t1,
       (SELECT COUNT(*) AS num_records FROM data) t2
 WHERE t1.row_num IN
       (FLOOR((t2.num_records + 1) / 2), 
        FLOOR((t2.num_records + 2) / 2));

其他回答

这是我的办法。当然,你可以把它放到一个过程中:-)

SET @median_counter = (SELECT FLOOR(COUNT(*)/2) - 1 AS `median_counter` FROM `data`);

SET @median = CONCAT('SELECT `val` FROM `data` ORDER BY `val` LIMIT ', @median_counter, ', 1');

PREPARE median FROM @median;

EXECUTE median;

你可以避免变量@median_counter,如果你替换它:

SET @median = CONCAT( 'SELECT `val` FROM `data` ORDER BY `val` LIMIT ',
                      (SELECT FLOOR(COUNT(*)/2) - 1 AS `median_counter` FROM `data`),
                      ', 1'
                    );

PREPARE median FROM @median;

EXECUTE median;

关心奇数的计数-给出中间两个值的平均值。

SELECT AVG(val) FROM
  ( SELECT x.id, x.val from data x, data y
      GROUP BY x.id, x.val
      HAVING SUM(SIGN(1-SIGN(IF(y.val-x.val=0 AND x.id != y.id, SIGN(x.id-y.id), y.val-x.val)))) IN (ROUND((COUNT(*))/2), ROUND((COUNT(*)+1)/2))
  ) sq

按维度分组的中位数:

SELECT your_dimension, avg(t1.val) as median_val FROM (
SELECT @rownum:=@rownum+1 AS `row_number`,
   IF(@dim <> d.your_dimension, @rownum := 0, NULL),
   @dim := d.your_dimension AS your_dimension,
   d.val
   FROM data d,  (SELECT @rownum:=0) r, (SELECT @dim := 'something_unreal') d
  WHERE 1
  -- put some where clause here
  ORDER BY d.your_dimension, d.val
) as t1
INNER JOIN  
(
  SELECT d.your_dimension,
    count(*) as total_rows
  FROM data d
  WHERE 1
  -- put same where clause here
  GROUP BY d.your_dimension
) as t2 USING(your_dimension)
WHERE 1
AND t1.row_number in ( floor((total_rows+1)/2), floor((total_rows+2)/2) )

GROUP BY your_dimension;

MariaDB / MySQL:

SELECT AVG(dd.val) as median_val
FROM (
SELECT d.val, @rownum:=@rownum+1 as `row_number`, @total_rows:=@rownum
  FROM data d, (SELECT @rownum:=0) r
  WHERE d.val is NOT NULL
  -- put some where clause here
  ORDER BY d.val
) as dd
WHERE dd.row_number IN ( FLOOR((@total_rows+1)/2), FLOOR((@total_rows+2)/2) );

Steve Cohen指出,在第一次传递之后,@rownum将包含总行数。这可用于确定中值,因此不需要第二次传递或连接。

此外,AVG(dd.val)和dd.row_number IN(…)用于在有偶数条记录时正确地产生中位数。推理:

SELECT FLOOR((3+1)/2),FLOOR((3+2)/2); -- when total_rows is 3, avg rows 2 and 2
SELECT FLOOR((4+1)/2),FLOOR((4+2)/2); -- when total_rows is 4, avg rows 2 and 3

最后,MariaDB 10.3.3+包含一个MEDIAN函数

你也可以选择在存储过程中这样做:

DROP PROCEDURE IF EXISTS median;
DELIMITER //
CREATE PROCEDURE median (table_name VARCHAR(255), column_name VARCHAR(255), where_clause VARCHAR(255))
BEGIN
  -- Set default parameters
  IF where_clause IS NULL OR where_clause = '' THEN
    SET where_clause = 1;
  END IF;

  -- Prepare statement
  SET @sql = CONCAT(
    "SELECT AVG(middle_values) AS 'median' FROM (
      SELECT t1.", column_name, " AS 'middle_values' FROM
        (
          SELECT @row:=@row+1 as `row`, x.", column_name, "
          FROM ", table_name," AS x, (SELECT @row:=0) AS r
          WHERE ", where_clause, " ORDER BY x.", column_name, "
        ) AS t1,
        (
          SELECT COUNT(*) as 'count'
          FROM ", table_name, " x
          WHERE ", where_clause, "
        ) AS t2
        -- the following condition will return 1 record for odd number sets, or 2 records for even number sets.
        WHERE t1.row >= t2.count/2
          AND t1.row <= ((t2.count/2)+1)) AS t3
    ");

  -- Execute statement
  PREPARE stmt FROM @sql;
  EXECUTE stmt;
END//
DELIMITER ;


-- Sample usage:
-- median(table_name, column_name, where_condition);
CALL median('products', 'price', NULL);