如何在Python中禁用标准错误流的日志记录?这行不通:
import logging
logger = logging.getLogger()
logger.removeHandler(sys.stderr)
logger.warning('foobar') # emits 'foobar' on sys.stderr
如何在Python中禁用标准错误流的日志记录?这行不通:
import logging
logger = logging.getLogger()
logger.removeHandler(sys.stderr)
logger.warning('foobar') # emits 'foobar' on sys.stderr
当前回答
我使用:
logger = logging.getLogger()
logger.disabled = True
... whatever you want ...
logger.disabled = False
其他回答
你还可以:
handlers = app.logger.handlers
# detach console handler
app.logger.handlers = []
# attach
app.logger.handlers = handlers
我不是很了解日志模块,但是我使用它的方式是我通常只希望禁用调试(或信息)消息。您可以使用Handler.setLevel()将日志级别设置为CRITICAL或更高。
此外,您还可以替换sys。Stderr和sys。打开用于写入的文件的标准输出。见http://docs.python.org/library/sys.html # sys.stdout。但我不建议这样做。
使用上下文管理器-[最简单]
import logging
class DisableLogger():
def __enter__(self):
logging.disable(logging.CRITICAL)
def __exit__(self, exit_type, exit_value, exit_traceback):
logging.disable(logging.NOTSET)
使用示例:
with DisableLogger():
do_something()
如果你需要[更复杂的]细粒度的解决方案,你可以看看AdvancedLogger
AdvancedLogger can be used for fine grained logging temporary modifications
How it works:
Modifications will be enabled when context_manager/decorator starts working and be reverted after
Usage:
AdvancedLogger can be used
- as decorator `@AdvancedLogger()`
- as context manager `with AdvancedLogger():`
It has three main functions/features:
- disable loggers and it's handlers by using disable_logger= argument
- enable/change loggers and it's handlers by using enable_logger= argument
- disable specific handlers for all loggers, by using disable_handler= argument
All features they can be used together
AdvancedLogger的用例
# Disable specific logger handler, for example for stripe logger disable console
AdvancedLogger(disable_logger={"stripe": "console"})
AdvancedLogger(disable_logger={"stripe": ["console", "console2"]})
# Enable/Set loggers
# Set level for "stripe" logger to 50
AdvancedLogger(enable_logger={"stripe": 50})
AdvancedLogger(enable_logger={"stripe": {"level": 50, "propagate": True}})
# Adjust already registered handlers
AdvancedLogger(enable_logger={"stripe": {"handlers": "console"}
不需要转移标准输出。这里有一个更好的方法:
import logging
class MyLogHandler(logging.Handler):
def emit(self, record):
pass
logging.getLogger().addHandler(MyLogHandler())
一个更简单的方法是:
logging.getLogger().setLevel(100)
(早就死了的问题,但对未来的搜索者来说)
更接近最初海报的代码/意图,这适用于我在python 2.6下
#!/usr/bin/python
import logging
logger = logging.getLogger() # this gets the root logger
lhStdout = logger.handlers[0] # stdout is the only handler initially
# ... here I add my own handlers
f = open("/tmp/debug","w") # example handler
lh = logging.StreamHandler(f)
logger.addHandler(lh)
logger.removeHandler(lhStdout)
logger.debug("bla bla")
我必须解决的问题是在添加一个新的stdout处理程序后删除它;如果没有处理程序,记录器代码将自动重新添加标准输出。
IndexOutOfBound修复:如果你得到一个IndexOutOfBound错误,而实例化lhStdout,移动实例化后添加你的文件处理程序,即。
...
logger.addHandler(lh)
lhStdout = logger.handlers[0]
logger.removeHandler(lhStdout)