如何在Python中禁用标准错误流的日志记录?这行不通:
import logging
logger = logging.getLogger()
logger.removeHandler(sys.stderr)
logger.warning('foobar') # emits 'foobar' on sys.stderr
如何在Python中禁用标准错误流的日志记录?这行不通:
import logging
logger = logging.getLogger()
logger.removeHandler(sys.stderr)
logger.warning('foobar') # emits 'foobar' on sys.stderr
当前回答
我使用:
logger = logging.getLogger()
logger.disabled = True
... whatever you want ...
logger.disabled = False
其他回答
这里有一些非常好的答案,但显然没有考虑太多最简单的答案(只从无穷开始)。
root_logger = logging.getLogger()
root_logger.disabled = True
这将禁用根日志记录器,从而禁用所有其他日志记录器。 我还没有真正测试过,但它应该是最快的。
从python 2.7的日志代码中,我看到了这一点
def handle(self, record):
"""
Call the handlers for the specified record.
This method is used for unpickled records received from a socket, as
well as those created locally. Logger-level filtering is applied.
"""
if (not self.disabled) and self.filter(record):
self.callHandlers(record)
这意味着当它被禁用时,不会调用任何处理程序,并且它应该比过滤到一个非常高的值或设置一个no-op处理程序更有效。
你可以使用:
logging.basicConfig(level=your_level)
your_level是其中之一:
'debug': logging.DEBUG,
'info': logging.INFO,
'warning': logging.WARNING,
'error': logging.ERROR,
'critical': logging.CRITICAL
如果你设置your_level为logging。CRITICAL,你只会得到由以下发送的关键消息:
logging.critical('This is a critical error message')
将your_level设置为日志。DEBUG将显示所有级别的日志记录。
要了解更多详细信息,请查看日志示例。
以同样的方式更改每个Handler的级别使用Handler. setlevel()函数。
import logging
import logging.handlers
LOG_FILENAME = '/tmp/logging_rotatingfile_example.out'
# Set up a specific logger with our desired output level
my_logger = logging.getLogger('MyLogger')
my_logger.setLevel(logging.DEBUG)
# Add the log message handler to the logger
handler = logging.handlers.RotatingFileHandler(
LOG_FILENAME, maxBytes=20, backupCount=5)
handler.setLevel(logging.CRITICAL)
my_logger.addHandler(handler)
不需要转移标准输出。这里有一个更好的方法:
import logging
class MyLogHandler(logging.Handler):
def emit(self, record):
pass
logging.getLogger().addHandler(MyLogHandler())
一个更简单的方法是:
logging.getLogger().setLevel(100)
您可以更改特定处理程序的调试模式级别,而不是完全禁用它。
因此,如果你有一个情况,你想停止调试模式的控制台,但你仍然需要保持其他级别,如错误。你可以像下面这样做
# create logger
logger = logging.getLogger(__name__)
def enableConsoleDebug (debug = False):
#Set level to logging.DEBUG to see CRITICAL, ERROR, WARNING, INFO and DEBUG statements
#Set level to logging.ERROR to see the CRITICAL & ERROR statements only
logger.setLevel(logging.DEBUG)
debugLevel = logging.ERROR
if debug:
debugLevel = logging.DEBUG
for handler in logger.handlers:
if type(handler) is logging.StreamHandler:
handler.setLevel (debugLevel)
子类化你想要暂时禁用的处理程序:
class ToggledHandler(logging.StreamHandler):
"""A handler one can turn on and off"""
def __init__(self, args, kwargs):
super(ToggledHandler, self).__init__(*args, **kwargs)
self.enabled = True # enabled by default
def enable(self):
"""enables"""
self.enabled = True
def disable(self):
"""disables"""
self.enabled = False
def emit(self, record):
"""emits, if enabled"""
if self.enabled:
# this is taken from the super's emit, implement your own
try:
msg = self.format(record)
stream = self.stream
stream.write(msg)
stream.write(self.terminator)
self.flush()
except Exception:
self.handleError(record)
通过名称查找处理程序非常简单:
_handler = [x for x in logging.getLogger('').handlers if x.name == your_handler_name]
if len(_handler) == 1:
_handler = _handler[0]
else:
raise Exception('Expected one handler but found {}'.format(len(_handler))
一旦发现:
_handler.disable()
doStuff()
_handler.enable()