我有一个用PHP编写的代码片段,它从数据库中提取一个文本块,并将其发送到网页上的一个小部件。原文可以是一篇很长的文章,也可以是一两个短句;但是对于这个小部件,我不能显示超过200个字符。我可以使用substr()在200个字符处切断文本,但结果将在单词中间切断——我真正想要的是在200个字符前的最后一个单词的末尾切断文本。


当前回答

我以前用过这个

<?php
    $your_desired_width = 200;
    $string = $var->content;
    if (strlen($string) > $your_desired_width) {
        $string = wordwrap($string, $your_desired_width);
        $string = substr($string, 0, strpos($string, "\n")) . " More...";
    }
    echo $string;
?>

其他回答

好吧,所以我得到了另一个版本的这个基于上面的答案,但考虑到更多的东西(utf-8, \n和&nbsp;),如果与wp一起使用,也是剥离wordpress shortcodes注释的行。

function neatest_trim($content, $chars) 
  if (strlen($content) > $chars) 
  {
    $content = str_replace('&nbsp;', ' ', $content);
    $content = str_replace("\n", '', $content);
    // use with wordpress    
    //$content = strip_tags(strip_shortcodes(trim($content)));
    $content = strip_tags(trim($content));
    $content = preg_replace('/\s+?(\S+)?$/', '', mb_substr($content, 0, $chars));

    $content = trim($content) . '...';
    return $content;
  }

我创建了一个更类似于substr的函数,并使用了@Dave的思想。

function substr_full_word($str, $start, $end){
    $pos_ini = ($start == 0) ? $start : stripos(substr($str, $start, $end), ' ') + $start;
    if(strlen($str) > $end){ $pos_end = strrpos(substr($str, 0, ($end + 1)), ' '); } // IF STRING SIZE IS LESSER THAN END
    if(empty($pos_end)){ $pos_end = $end; } // FALLBACK
    return substr($str, $pos_ini, $pos_end);
}

注:全长切割可能小于substr。

Keep in mind whenever you're splitting by "word" anywhere that some languages such as Chinese and Japanese do not use a space character to split words. Also, a malicious user could simply enter text without any spaces, or using some Unicode look-alike to the standard space character, in which case any solution you use may end up displaying the entire text anyway. A way around this may be to check the string length after splitting it on spaces as normal, then, if the string is still above an abnormal limit - maybe 225 characters in this case - going ahead and splitting it dumbly at that limit.

当涉及到非ascii字符时,还有一个类似的警告;包含它们的字符串可能会被PHP的标准strlen()解释为比实际更长,因为单个字符可能占用两个或更多字节,而不是一个字节。如果你只是使用strlen()/substr()函数来分割字符串,你可能会在字符中间分割字符串!如果有疑问,mb_strlen()/mb_substr()更简单一些。

你可以用这个:

function word_shortener($text, $words=10, $sp='...'){

  $all = explode(' ', $text);
  $str = '';
  $count = 1;

  foreach($all as $key){
    $str .= $key . ($count >= $words ? '' : ' ');
    $count++;
    if($count > $words){
      break;
    }
  }

  return $str . (count($all) <= $words ? '' : $sp);

}

例子:

word_shortener("Hello world, this is a text", 3); // Hello world, this...
word_shortener("Hello world, this is a text", 3, ''); // Hello world, this
word_shortener("Hello world, this is a text", 3, '[read more]'); // Hello world, this[read more]

Edit

工作原理:

1. 从输入文本中打开空格:

$all = explode(' ', $text);

例如,如果$text将是"Hello world",那么$all是一个带有爆炸值的数组:

“你好”,“世界”)

2. 对于每个单词:

选择展开文本中的每个元素:

foreach($all as $key){...

将当前单词($key)附加到$str,如果它是最后一个单词,则添加空格:

$str .= $key . ($count >= $words ? '' : ' ');

然后给$count加上1,检查它是否大于max limit($words)打破循环:

if($count > $words){
   break;
}

只有当最终文本小于输入文本时,才返回$str和分隔符($sp):

return $str . (count($all) <= $words ? '' : $sp);

这是一个小修复mattmac的答案:

preg_replace('/\s+?(\S+)?$/', '', substr($string . ' ', 0, 201));

唯一的区别是在$string的末尾添加一个空格。这确保了最后一个词不会像ReX357的注释那样被切断。

我没有足够的代表点添加这作为一个评论。