我如何添加一个触摸事件到一个UIView? 我试一试:
UIView *headerView = [[[UIView alloc] initWithFrame:CGRectMake(0, 0, tableView.bounds.size.width, nextY)] autorelease];
[headerView addTarget:self action:@selector(myEvent:) forControlEvents:UIControlEventTouchDown];
// ERROR MESSAGE: UIView may not respond to '-addTarget:action:forControlEvents:'
我不想创建一个子类然后重写
- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
当前回答
你可以通过在代码中添加手势识别器来实现这一点。
步骤1:ViewController.m:
// Declare the Gesture.
UITapGestureRecognizer *gesRecognizer = [[UITapGestureRecognizer alloc]
initWithTarget:self
action:@selector(handleTap:)];
gesRecognizer.delegate = self;
// Add Gesture to your view.
[yourView addGestureRecognizer:gesRecognizer];
步骤2:ViewController.m:
// Declare the Gesture Recogniser handler method.
- (void)handleTap:(UITapGestureRecognizer *)gestureRecognizer{
NSLog(@"Tapped");
}
注意:这里的yourView在我的情况是@property(强，非原子)IBOutlet UIView *localView;
编辑:*localView是Main中的白色框。下面的故事板
其他回答
基于已接受的答案，你可以定义一个宏:
#define handle_tap(view, delegate, selector) do {\
view.userInteractionEnabled = YES;\
[view addGestureRecognizer: [[UITapGestureRecognizer alloc] initWithTarget:delegate action:selector]];\
} while(0)
这个宏使用ARC，所以没有发布调用。
宏使用示例:
handle_tap(userpic, self, @selector(onTapUserpic:));
这是ios tapgesture; 首先，你需要为GestureRecognizer创建动作，在动作下面写如下所示的代码
- (IBAction)tapgesture:(id)sender
{
[_password resignFirstResponder];
[_username resignFirstResponder];
NSLog(@" TapGestureRecognizer tapped");
}
objective - c:
UIControl *headerView = [[UIControl alloc] initWithFrame:CGRectMake(0, 0, tableView.bounds.size.width, nextY)];
[headerView addTarget:self action:@selector(myEvent:) forControlEvents:UIControlEventTouchDown];
迅速:
let headerView = UIControl(frame: CGRect(x: 0, y: 0, width: tableView.bounds.size.width, height: nextY))
headerView.addTarget(self, action: #selector(myEvent(_:)), for: .touchDown)
问题是:
我如何添加一个触摸事件到一个UIView?
它并不是在请求一个点击事件。
特别是OP想要实现UIControlEventTouchDown
切换UIView到UIControl是正确的答案，因为手势识别器不知道。touchdown。touchupinside，。touchupoutside等等。
此外，UIControl继承自UIView，所以你不会失去任何功能。
如果你想要的只是轻敲一下，那么你可以使用手势识别器。但如果你想要更好的控制，就像这个问题要求的，你需要UIControl。
https://developer.apple.com/documentation/uikit/uicontrol?language=objc https://developer.apple.com/documentation/uikit/uigesturerecognizer?language=objc
你可以通过在代码中添加手势识别器来实现这一点。
步骤1:ViewController.m:
// Declare the Gesture.
UITapGestureRecognizer *gesRecognizer = [[UITapGestureRecognizer alloc]
initWithTarget:self
action:@selector(handleTap:)];
gesRecognizer.delegate = self;
// Add Gesture to your view.
[yourView addGestureRecognizer:gesRecognizer];
步骤2:ViewController.m:
// Declare the Gesture Recogniser handler method.
- (void)handleTap:(UITapGestureRecognizer *)gestureRecognizer{
NSLog(@"Tapped");
}
注意:这里的yourView在我的情况是@property(强，非原子)IBOutlet UIView *localView;
编辑:*localView是Main中的白色框。下面的故事板
另一种方法是向视图添加一个透明按钮
UIButton *b = [UIButton buttonWithType:UIButtonTypeCustom];
b.frame = CGRectMake(0, 0, headerView.width, headerView.height);
[headerView addSubview:b];
[b addTarget:self action:@selector(buttonClicked:) forControlEvents:UIControlEventTouchDown];
然后，handle click:
- (void)buttonClicked:(id)sender
{}
