我以日期2010-05-01开始,以2010-05-10结束。如何在PHP中遍历所有这些日期?
当前回答
下面是另一个简单的实现
/**
* Date range
*
* @param $first
* @param $last
* @param string $step
* @param string $format
* @return array
*/
function dateRange( $first, $last, $step = '+1 day', $format = 'Y-m-d' ) {
$dates = [];
$current = strtotime( $first );
$last = strtotime( $last );
while( $current <= $last ) {
$dates[] = date( $format, $current );
$current = strtotime( $step, $current );
}
return $dates;
}
例子:
print_r( dateRange( '2010-07-26', '2010-08-05') );
Array (
[0] => 2010-07-26
[1] => 2010-07-27
[2] => 2010-07-28
[3] => 2010-07-29
[4] => 2010-07-30
[5] => 2010-07-31
[6] => 2010-08-01
[7] => 2010-08-02
[8] => 2010-08-03
[9] => 2010-08-04
[10] => 2010-08-05
)
其他回答
用户本功能:-
function dateRange($first, $last, $step = '+1 day', $format = 'Y-m-d' ) {
$dates = array();
$current = strtotime($first);
$last = strtotime($last);
while( $current <= $last ) {
$dates[] = date($format, $current);
$current = strtotime($step, $current);
}
return $dates;
}
使用/函数调用:-
增加一天:-
dateRange($start, $end); //increment is set to 1 day.
按月递增:-
dateRange($start, $end, "+1 month");//increase by one month
如果你想设置日期格式,可以使用第三个参数:-
dateRange($start, $end, "+1 month", "Y-m-d H:i:s");//increase by one month and format is mysql datetime
下面是另一个简单的实现
/**
* Date range
*
* @param $first
* @param $last
* @param string $step
* @param string $format
* @return array
*/
function dateRange( $first, $last, $step = '+1 day', $format = 'Y-m-d' ) {
$dates = [];
$current = strtotime( $first );
$last = strtotime( $last );
while( $current <= $last ) {
$dates[] = date( $format, $current );
$current = strtotime( $step, $current );
}
return $dates;
}
例子:
print_r( dateRange( '2010-07-26', '2010-08-05') );
Array (
[0] => 2010-07-26
[1] => 2010-07-27
[2] => 2010-07-28
[3] => 2010-07-29
[4] => 2010-07-30
[5] => 2010-07-31
[6] => 2010-08-01
[7] => 2010-08-02
[8] => 2010-08-03
[9] => 2010-08-04
[10] => 2010-08-05
)
复制从php.net样本包括范围:
$begin = new DateTime( '2012-08-01' );
$end = new DateTime( '2012-08-31' );
$end = $end->modify( '+1 day' );
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
foreach($daterange as $date){
echo $date->format("Ymd") . "<br>";
}
$begin = new DateTime('2010-05-01');
$end = new DateTime('2010-05-10');
$interval = DateInterval::createFromDateString('1 day');
$period = new DatePeriod($begin, $interval, $end);
foreach ($period as $dt) {
echo $dt->format("l Y-m-d H:i:s\n");
}
这将输出在$start和$end之间定义的时间段内的所有天数。如果你想包括10号,将$end设置为11号。你可以根据自己的喜好调整格式。请参阅DatePeriod的PHP手册。它需要PHP 5.3。
这里有一个方法:
$date = new Carbon();
$dtStart = $date->startOfMonth();
$dtEnd = $dtStart->copy()->endOfMonth();
$weekendsInMoth = [];
while ($dtStart->diffInDays($dtEnd)) {
if($dtStart->isWeekend()) {
$weekendsInMoth[] = $dtStart->copy();
}
$dtStart->addDay();
}
$weekendsInMoth的结果是周末天数的数组!
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