我以日期2010-05-01开始,以2010-05-10结束。如何在PHP中遍历所有这些日期?


当前回答

$date = new DateTime($_POST['date']);
$endDate = date_add(new DateTime($_POST['date']),date_interval_create_from_date_string("7 days"));

while ($date <= $endDate) {
    print date_format($date,'d-m-Y')." AND END DATE IS : ".date_format($endDate,'d-m-Y')."\n";
    date_add($date,date_interval_create_from_date_string("1 days"));
}

你也可以这样迭代,$_POST['date']可以从你的应用程序或网站凹痕 而不是$_POST['date']你也可以把你的字符串放在这里"21-12-2019"。两者都可以。

其他回答

$startTime = strtotime('2010-05-01'); 
$endTime = strtotime('2010-05-10'); 

// Loop between timestamps, 1 day at a time 
$i = 1;
do {
   $newTime = strtotime('+'.$i++.' days',$startTime); 
   echo $newTime;
} while ($newTime < $endTime);

or

$startTime = strtotime('2010-05-01'); 
$endTime = strtotime('2010-05-10'); 

// Loop between timestamps, 1 day at a time 
do {
   $startTime = strtotime('+1 day',$startTime); 
   echo $startTime;
} while ($startTime < $endTime);

复制从php.net样本包括范围:

$begin = new DateTime( '2012-08-01' );
$end = new DateTime( '2012-08-31' );
$end = $end->modify( '+1 day' ); 

$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);

foreach($daterange as $date){
    echo $date->format("Ymd") . "<br>";
}

转换为unix时间戳使在php中计算日期更容易:

$startTime = strtotime( '2010-05-01 12:00' );
$endTime = strtotime( '2010-05-10 12:00' );

// Loop between timestamps, 24 hours at a time
for ( $i = $startTime; $i <= $endTime; $i = $i + 86400 ) {
  $thisDate = date( 'Y-m-d', $i ); // 2010-05-01, 2010-05-02, etc
}

当使用带有夏令时的时区时,请确保添加的时间不是23:00、00:00或1:00,以防止跳过或重复日期。

这里有一个方法:

 $date = new Carbon();
 $dtStart = $date->startOfMonth();
 $dtEnd = $dtStart->copy()->endOfMonth();

 $weekendsInMoth = [];
 while ($dtStart->diffInDays($dtEnd)) {

     if($dtStart->isWeekend()) {
            $weekendsInMoth[] = $dtStart->copy();
     }

     $dtStart->addDay();
 }

$weekendsInMoth的结果是周末天数的数组!

$date = new DateTime($_POST['date']);
$endDate = date_add(new DateTime($_POST['date']),date_interval_create_from_date_string("7 days"));

while ($date <= $endDate) {
    print date_format($date,'d-m-Y')." AND END DATE IS : ".date_format($endDate,'d-m-Y')."\n";
    date_add($date,date_interval_create_from_date_string("1 days"));
}

你也可以这样迭代,$_POST['date']可以从你的应用程序或网站凹痕 而不是$_POST['date']你也可以把你的字符串放在这里"21-12-2019"。两者都可以。