我以日期2010-05-01开始,以2010-05-10结束。如何在PHP中遍历所有这些日期?


当前回答

如果你使用Laravel并且想要使用Carbon,正确的解决方案如下:

$start_date = Carbon::createFromFormat('Y-m-d', '2020-01-01');
$end_date = Carbon::createFromFormat('Y-m-d', '2020-01-31');

$period = new CarbonPeriod($start_date, '1 day', $end_date);

foreach ($period as $dt) {
 echo $dt->format("l Y-m-d H:i:s\n");
}

记得加上:

使用碳\碳; 使用碳\ CarbonPeriod;

其他回答

用户本功能:-

function dateRange($first, $last, $step = '+1 day', $format = 'Y-m-d' ) {
                $dates = array();
                $current = strtotime($first);
                $last = strtotime($last);

                while( $current <= $last ) {    
                    $dates[] = date($format, $current);
                    $current = strtotime($step, $current);
                }
                return $dates;
        }

使用/函数调用:-

增加一天:-

dateRange($start, $end); //increment is set to 1 day.

按月递增:-

dateRange($start, $end, "+1 month");//increase by one month

如果你想设置日期格式,可以使用第三个参数:-

   dateRange($start, $end, "+1 month", "Y-m-d H:i:s");//increase by one month and format is mysql datetime
$begin = new DateTime('2010-05-01');
$end = new DateTime('2010-05-10');

$interval = DateInterval::createFromDateString('1 day');
$period = new DatePeriod($begin, $interval, $end);

foreach ($period as $dt) {
    echo $dt->format("l Y-m-d H:i:s\n");
}

这将输出在$start和$end之间定义的时间段内的所有天数。如果你想包括10号,将$end设置为11号。你可以根据自己的喜好调整格式。请参阅DatePeriod的PHP手册。它需要PHP 5.3。

复制从php.net样本包括范围:

$begin = new DateTime( '2012-08-01' );
$end = new DateTime( '2012-08-31' );
$end = $end->modify( '+1 day' ); 

$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);

foreach($daterange as $date){
    echo $date->format("Ymd") . "<br>";
}

这里有一个方法:

 $date = new Carbon();
 $dtStart = $date->startOfMonth();
 $dtEnd = $dtStart->copy()->endOfMonth();

 $weekendsInMoth = [];
 while ($dtStart->diffInDays($dtEnd)) {

     if($dtStart->isWeekend()) {
            $weekendsInMoth[] = $dtStart->copy();
     }

     $dtStart->addDay();
 }

$weekendsInMoth的结果是周末天数的数组!

下面是另一个简单的实现

/**
 * Date range
 *
 * @param $first
 * @param $last
 * @param string $step
 * @param string $format
 * @return array
 */
function dateRange( $first, $last, $step = '+1 day', $format = 'Y-m-d' ) {
    $dates = [];
    $current = strtotime( $first );
    $last = strtotime( $last );

    while( $current <= $last ) {

        $dates[] = date( $format, $current );
        $current = strtotime( $step, $current );
    }

    return $dates;
}

例子:

print_r( dateRange( '2010-07-26', '2010-08-05') );

Array (
    [0] => 2010-07-26
    [1] => 2010-07-27
    [2] => 2010-07-28
    [3] => 2010-07-29
    [4] => 2010-07-30
    [5] => 2010-07-31
    [6] => 2010-08-01
    [7] => 2010-08-02
    [8] => 2010-08-03
    [9] => 2010-08-04
    [10] => 2010-08-05
)