转换为unix时间戳使在php中计算日期更容易:

$startTime = strtotime( '2010-05-01 12:00' );
$endTime = strtotime( '2010-05-10 12:00' );

// Loop between timestamps, 24 hours at a time
for ( $i = $startTime; $i <= $endTime; $i = $i + 86400 ) {
  $thisDate = date( 'Y-m-d', $i ); // 2010-05-01, 2010-05-02, etc
}

当使用带有夏令时的时区时，请确保添加的时间不是23:00、00:00或1:00，以防止跳过或重复日期。

如果你使用的是低于8.2版本的php，并且没有DatePeriod::INCLUDE_END_DATE const。我写了一个返回\DateTimeImmutable数组的方法。

这适用于开始日期在结束日期之前、相同或之后的情况。

    /**
     * @param DateTimeImmutable $start
     * @param DateTimeImmutable $end
     * @return array<\DateTimeImmutable>
     */
    public static function getRangeDays(\DateTimeImmutable $start, \DateTimeImmutable $end): array
    {
        $startDate = $start;
        $endDate = $end;
        $forwards = $endDate >= $startDate;
        $carryDate = $startDate;
        $days = [];
        while (true) {
            if (($forwards && $carryDate > $end) || (!$forwards && $carryDate < $end)) {
                break;
            }
            $days[] = $carryDate;

            if ($forwards) {
                $carryDate = $carryDate->modify('+1 day');
            } else {
                $carryDate = $carryDate->modify('- 1 day');
            }
        }

        return $days;
    }

下面是另一个简单的实现

/**
 * Date range
 *
 * @param $first
 * @param $last
 * @param string $step
 * @param string $format
 * @return array
 */
function dateRange( $first, $last, $step = '+1 day', $format = 'Y-m-d' ) {
    $dates = [];
    $current = strtotime( $first );
    $last = strtotime( $last );

    while( $current <= $last ) {

        $dates[] = date( $format, $current );
        $current = strtotime( $step, $current );
    }

    return $dates;
}

例子:

print_r( dateRange( '2010-07-26', '2010-08-05') );

Array (
    [0] => 2010-07-26
    [1] => 2010-07-27
    [2] => 2010-07-28
    [3] => 2010-07-29
    [4] => 2010-07-30
    [5] => 2010-07-31
    [6] => 2010-08-01
    [7] => 2010-08-02
    [8] => 2010-08-03
    [9] => 2010-08-04
    [10] => 2010-08-05
)

转换为unix时间戳使在php中计算日期更容易:

$startTime = strtotime( '2010-05-01 12:00' );
$endTime = strtotime( '2010-05-10 12:00' );

// Loop between timestamps, 24 hours at a time
for ( $i = $startTime; $i <= $endTime; $i = $i + 86400 ) {
  $thisDate = date( 'Y-m-d', $i ); // 2010-05-01, 2010-05-02, etc
}

当使用带有夏令时的时区时，请确保添加的时间不是23:00、00:00或1:00，以防止跳过或重复日期。

这里有一个方法:

 $date = new Carbon();
 $dtStart = $date->startOfMonth();
 $dtEnd = $dtStart->copy()->endOfMonth();

 $weekendsInMoth = [];
 while ($dtStart->diffInDays($dtEnd)) {

     if($dtStart->isWeekend()) {
            $weekendsInMoth[] = $dtStart->copy();
     }

     $dtStart->addDay();
 }

$weekendsInMoth的结果是周末天数的数组!

这也包括最后的日期

$begin = new DateTime( "2015-07-03" );
$end   = new DateTime( "2015-07-09" );

for($i = $begin; $i <= $end; $i->modify('+1 day')){
    echo $i->format("Y-m-d");
}

如果你不需要最后的日期，只需从条件中删除=。