如何将此字符串“2016-04-14T10:44:00+0000”转换为NSDate并只保留年、月、日、小时?
中间的T真的让我在处理日期时不习惯。
如何将此字符串“2016-04-14T10:44:00+0000”转换为NSDate并只保留年、月、日、小时?
中间的T真的让我在处理日期时不习惯。
当前回答
那SwiftDate呢?Swift最好的日期和时间解析和操作库。
https://github.com/malcommac/SwiftDate#1-date-parsing
使用可可豆荚安装: https://github.com/malcommac/SwiftDate/blob/master/Documentation/0.Informations.md#installation
然后:
import SwiftDate
// All default datetime formats (15+) are recognized automatically
let _ = "2010-05-20 15:30:00".toDate()
// You can also provide your own format!
let _ = "2010-05-20 15:30".toDate("yyyy-MM-dd HH:mm")
// All ISO8601 variants are supported too with timezone parsing!
let _ = "2017-09-17T11:59:29+02:00".toISODate()
// RSS, Extended, HTTP, SQL, .NET and all the major variants are supported!
let _ = "19 Nov 2015 22:20:40 +0100".toRSS(alt: true)
其他回答
Convert the ISO8601 string to date let isoDate = "2016-04-14T10:44:00+0000" let dateFormatter = DateFormatter() dateFormatter.locale = Locale(identifier: "en_US_POSIX") // set locale to reliable US_POSIX dateFormatter.dateFormat = "yyyy-MM-dd'T'HH:mm:ssZ" let date = dateFormatter.date(from:isoDate)! Get the date components for year, month, day and hour from the date let calendar = Calendar.current let components = calendar.dateComponents([.year, .month, .day, .hour], from: date) Finally create a new Date object and strip minutes and seconds let finalDate = calendar.date(from:components)
还可以考虑iOS 10 / macOS 10.12中引入的方便格式化程序ISO8601DateFormatter:
let isoDate = "2016-04-14T10:44:00+0000"
let dateFormatter = ISO8601DateFormatter()
let date = dateFormatter.date(from:isoDate)!
Swift 3.0 - 4.2
import Foundation
extension String {
func toDate(withFormat format: String = "yyyy-MM-dd HH:mm:ss")-> Date?{
let dateFormatter = DateFormatter()
dateFormatter.timeZone = TimeZone(identifier: "Asia/Tehran")
dateFormatter.locale = Locale(identifier: "fa-IR")
dateFormatter.calendar = Calendar(identifier: .gregorian)
dateFormatter.dateFormat = format
let date = dateFormatter.date(from: self)
return date
}
}
extension Date {
func toString(withFormat format: String = "EEEE ، d MMMM yyyy") -> String {
let dateFormatter = DateFormatter()
dateFormatter.locale = Locale(identifier: "fa-IR")
dateFormatter.timeZone = TimeZone(identifier: "Asia/Tehran")
dateFormatter.calendar = Calendar(identifier: .persian)
dateFormatter.dateFormat = format
let str = dateFormatter.string(from: self)
return str
}
}
就用SwifterSwift吧。
stringDate = "2020-04-26T08:56:17.987Z"
let date = Date(iso8601String: stringDate)
斯威夫特5.6
这是一个简单的方法来获得一个字符串,并将其转换回字符串与日期的结构通过字符串扩展
日期字符串示例"2022-03-15T07:13:49.607+00:00"
如果日期的格式不是“yyyy-MM-dd'T hh:mm:ss”。SSSSSSSZ” 它将返回01-01-70
import Foundation
extension String {
func convertToDate() -> String {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "yyyy-MM-dd'T'HH:mm:ss.SSSSSSSZ"
if let dt = dateFormatter.date(from: self) {
dateFormatter.dateFormat = "MM-dd-yy"
let formatedStringDate = dateFormatter.string(from: dt)
return formatedStringDate
}
return "01-01-70"
}
}
在Swift 4.1你可以做:
func getDate() -> Date? {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "yyyy-MM-dd'T'HH:mm:ss"
dateFormatter.timeZone = TimeZone.current
dateFormatter.locale = Locale.current
return dateFormatter.date(from: "2015-04-01T11:42:00") // replace Date String
}