这是一个棘手的小问题，我想提出我的解决方案。我发现了一些其他的解决方案(异步。例如IO)看起来很有前途，但也呈现出一些黑盒子。队列/事件循环方法将您与某个实现联系在一起。然而，并发期货的源代码只有大约1000行，很容易理解。它让我很容易地解决了我的问题:创建临时的工作线程，而不需要太多的设置，并且能够在主线程中捕获异常。

我的解决方案使用并发期货API和线程API。它允许你创建一个worker，给你线程和未来。这样，你就可以加入线程来等待结果:

worker = Worker(test)
thread = worker.start()
thread.join()
print(worker.future.result())

.．.或者你可以让worker在完成时发送一个回调:

worker = Worker(test)
thread = worker.start(lambda x: print('callback', x))

.．.或者你可以循环直到事件完成:

worker = Worker(test)
thread = worker.start()

while True:
    print("waiting")
    if worker.future.done():
        exc = worker.future.exception()
        print('exception?', exc)
        result = worker.future.result()
        print('result', result)           
        break
    time.sleep(0.25)

代码如下:

from concurrent.futures import Future
import threading
import time

class Worker(object):
    def __init__(self, fn, args=()):
        self.future = Future()
        self._fn = fn
        self._args = args

    def start(self, cb=None):
        self._cb = cb
        self.future.set_running_or_notify_cancel()
        thread = threading.Thread(target=self.run, args=())
        thread.daemon = True #this will continue thread execution after the main thread runs out of code - you can still ctrl + c or kill the process
        thread.start()
        return thread

    def run(self):
        try:
            self.future.set_result(self._fn(*self._args))
        except BaseException as e:
            self.future.set_exception(e)

        if(self._cb):
            self._cb(self.future.result())

.．.和测试函数:

def test(*args):
    print('args are', args)
    time.sleep(2)
    raise Exception('foo')

在Python 3.8中，我们可以使用线程。Excepthook在所有子线程中钩住未捕获的异常!例如,

threading.excepthook = thread_exception_handler

推荐人:https://stackoverflow.com/a/60002752/5093308

问题是thread_obj.start()立即返回。您所生成的子线程在它自己的上下文中使用自己的堆栈执行。在那里发生的任何异常都在子线程的上下文中，并且在它自己的堆栈中。我现在能想到的一种将此信息传递给父线程的方法是使用某种消息传递，因此您可以研究一下。

试试这个尺寸:

import sys
import threading
import queue


class ExcThread(threading.Thread):

    def __init__(self, bucket):
        threading.Thread.__init__(self)
        self.bucket = bucket

    def run(self):
        try:
            raise Exception('An error occured here.')
        except Exception:
            self.bucket.put(sys.exc_info())


def main():
    bucket = queue.Queue()
    thread_obj = ExcThread(bucket)
    thread_obj.start()

    while True:
        try:
            exc = bucket.get(block=False)
        except queue.Empty:
            pass
        else:
            exc_type, exc_obj, exc_trace = exc
            # deal with the exception
            print exc_type, exc_obj
            print exc_trace

        thread_obj.join(0.1)
        if thread_obj.isAlive():
            continue
        else:
            break


if __name__ == '__main__':
    main()

如果在线程中发生异常，最好的方法是在连接期间在调用线程中重新引发它。您可以使用sys.exc_info()函数获取当前正在处理的异常的信息。此信息可以简单地存储为线程对象的属性，直到调用join，此时可以重新引发它。

注意，队列。队列(在其他回答中建议)在这个简单的情况下是不必要的，因为线程最多抛出1个异常，并且在抛出一个异常后立即完成。我们通过简单地等待线程完成来避免竞争条件。

例如，扩展ExcThread(如下)，覆盖excRun(而不是run)。

Python 2. x:

import threading

class ExcThread(threading.Thread):
  def excRun(self):
    pass

  def run(self):
    self.exc = None
    try:
      # Possibly throws an exception
      self.excRun()
    except:
      import sys
      self.exc = sys.exc_info()
      # Save details of the exception thrown but don't rethrow,
      # just complete the function

  def join(self):
    threading.Thread.join(self)
    if self.exc:
      msg = "Thread '%s' threw an exception: %s" % (self.getName(), self.exc[1])
      new_exc = Exception(msg)
      raise new_exc.__class__, new_exc, self.exc[2]

Python 3. x:

在Python 3中，raise的参数形式为3，因此将最后一行更改为:

raise new_exc.with_traceback(self.exc[2])

我做的是，简单的覆盖连接和运行线程的方法:

class RaisingThread(threading.Thread):
  def run(self):
    self._exc = None
    try:
      super().run()
    except Exception as e:
      self._exc = e

  def join(self, timeout=None):
    super().join(timeout=timeout)
    if self._exc:
      raise self._exc

用途如下:

def foo():
  time.sleep(2)
  print('hi, from foo!')
  raise Exception('exception from foo')    

t = RaisingThread(target=foo)
t.start()
try:
  t.join()
except Exception as e:
  print(e)

结果:

hi, from foo!
exception from foo!

Pygolang提供同步功能。工作组，特别是将异常从派生的工作线程传播到主线程。例如:

#!/usr/bin/env python
"""This program demostrates how with sync.WorkGroup an exception raised in
spawned thread is propagated into main thread which spawned the worker."""

from __future__ import print_function
from golang import sync, context

def T1(ctx, *argv):
    print('T1: run ... %r' % (argv,))
    raise RuntimeError('T1: problem')

def T2(ctx):
    print('T2: ran ok')

def main():
    wg = sync.WorkGroup(context.background())
    wg.go(T1, [1,2,3])
    wg.go(T2)

    try:
        wg.wait()
    except Exception as e:
        print('Tmain: caught exception: %r\n' %e)
        # reraising to see full traceback
        raise

if __name__ == '__main__':
    main()

在运行时给出以下结果:

T1: run ... ([1, 2, 3],)
T2: ran ok
Tmain: caught exception: RuntimeError('T1: problem',)

Traceback (most recent call last):
  File "./x.py", line 28, in <module>
    main()
  File "./x.py", line 21, in main
    wg.wait()
  File "golang/_sync.pyx", line 198, in golang._sync.PyWorkGroup.wait
    pyerr_reraise(pyerr)
  File "golang/_sync.pyx", line 178, in golang._sync.PyWorkGroup.go.pyrunf
    f(pywg._pyctx, *argv, **kw)
  File "./x.py", line 10, in T1
    raise RuntimeError('T1: problem')
RuntimeError: T1: problem

问题的原始代码将是:

    wg = sync.WorkGroup(context.background())

    def _(ctx):
        shul.copytree(sourceFolder, destFolder)
    wg.go(_)

    # waits for spawned worker to complete and, on error, reraises
    # its exception on the main thread.
    wg.wait()