我对Python和多线程编程非常陌生。基本上,我有一个脚本,将文件复制到另一个位置。我想把这个放在另一个线程,这样我就可以输出....表示脚本仍在运行。

我遇到的问题是,如果文件不能复制,它将抛出异常。如果在主线程中运行,这是可以的;但是,使用以下代码是无效的:

try:
    threadClass = TheThread(param1, param2, etc.)
    threadClass.start()   ##### **Exception takes place here**
except:
    print "Caught an exception"

在线程类本身中,我试图重新抛出异常,但它不起作用。我在这里看到有人问类似的问题,但他们似乎都在做一些比我试图做的更具体的事情(我不太理解所提供的解决方案)。我看到有人提到sys.exc_info()的用法,但我不知道在哪里或如何使用它。

编辑:线程类的代码如下:

class TheThread(threading.Thread):
    def __init__(self, sourceFolder, destFolder):
        threading.Thread.__init__(self)
        self.sourceFolder = sourceFolder
        self.destFolder = destFolder
    
    def run(self):
        try:
           shul.copytree(self.sourceFolder, self.destFolder)
        except:
           raise

当前回答

捕获线程异常并与调用方方法通信的一个简单方法是将字典或列表传递给worker方法。

示例(将字典传递给工作方法):

import threading

def my_method(throw_me):
    raise Exception(throw_me)

def worker(shared_obj, *args, **kwargs):
    try:
        shared_obj['target'](*args, **kwargs)
    except Exception as err:
        shared_obj['err'] = err

shared_obj = {'err':'', 'target': my_method}
throw_me = "Test"

th = threading.Thread(target=worker, args=(shared_obj, throw_me), kwargs={})
th.start()
th.join()

if shared_obj['err']:
    print(">>%s" % shared_obj['err'])

其他回答

类似于RickardSjogren的方法,没有Queue, sys等,但也没有一些信号监听器:直接执行一个异常处理程序,对应于一个异常块。

#!/usr/bin/env python3

import threading

class ExceptionThread(threading.Thread):

    def __init__(self, callback=None, *args, **kwargs):
        """
        Redirect exceptions of thread to an exception handler.

        :param callback: function to handle occured exception
        :type callback: function(thread, exception)
        :param args: arguments for threading.Thread()
        :type args: tuple
        :param kwargs: keyword arguments for threading.Thread()
        :type kwargs: dict
        """
        self._callback = callback
        super().__init__(*args, **kwargs)

    def run(self):
        try:
            if self._target:
                self._target(*self._args, **self._kwargs)
        except BaseException as e:
            if self._callback is None:
                raise e
            else:
                self._callback(self, e)
        finally:
            # Avoid a refcycle if the thread is running a function with
            # an argument that has a member that points to the thread.
            del self._target, self._args, self._kwargs, self._callback

只有自我。_callback和run()中的except块是普通threading.Thread之外的。

使用异常存储包装线程。

import threading
import sys
class ExcThread(threading.Thread):

    def __init__(self, target, args = None):
        self.args = args if args else []
        self.target = target
        self.exc = None
        threading.Thread.__init__(self)

    def run(self):
        try:
            self.target(*self.args)
            raise Exception('An error occured here.')
        except Exception:
            self.exc=sys.exc_info()

def main():
    def hello(name):
        print(!"Hello, {name}!")
    thread_obj = ExcThread(target=hello, args=("Jack"))
    thread_obj.start()

    thread_obj.join()
    exc = thread_obj.exc
    if exc:
        exc_type, exc_obj, exc_trace = exc
        print(exc_type, ':',exc_obj, ":", exc_trace)

main()

我使用这个版本,它是最小的,它工作得很好。

class SafeThread(threading.Thread):
    def __init__(self, *args, **kwargs):
        super(SafeThread, self).__init__(*args, **kwargs)
        self.exception = None

    def run(self) -> None:
        try:
            super(SafeThread, self).run()
        except Exception as ex:
            self.exception = ex
            traceback.print_exc()

    def join(self, *args, **kwargs) -> None:
        super(SafeThread, self).join(*args, **kwargs)
        if self.exception:
            raise self.exception

要使用它,只需替换线程。带安全线程的线程

t = SafeThread(target = some_function, args = (some, args,))
t.start()
# do something else here if you want as the thread runs in the background
t.join()

如果在线程中发生异常,最好的方法是在连接期间在调用线程中重新引发它。您可以使用sys.exc_info()函数获取当前正在处理的异常的信息。此信息可以简单地存储为线程对象的属性,直到调用join,此时可以重新引发它。

注意,队列。队列(在其他回答中建议)在这个简单的情况下是不必要的,因为线程最多抛出1个异常,并且在抛出一个异常后立即完成。我们通过简单地等待线程完成来避免竞争条件。

例如,扩展ExcThread(如下),覆盖excRun(而不是run)。

Python 2. x:

import threading

class ExcThread(threading.Thread):
  def excRun(self):
    pass

  def run(self):
    self.exc = None
    try:
      # Possibly throws an exception
      self.excRun()
    except:
      import sys
      self.exc = sys.exc_info()
      # Save details of the exception thrown but don't rethrow,
      # just complete the function

  def join(self):
    threading.Thread.join(self)
    if self.exc:
      msg = "Thread '%s' threw an exception: %s" % (self.getName(), self.exc[1])
      new_exc = Exception(msg)
      raise new_exc.__class__, new_exc, self.exc[2]

Python 3. x:

在Python 3中,raise的参数形式为3,因此将最后一行更改为:

raise new_exc.with_traceback(self.exc[2])

我喜欢的一种方法是基于观察者模式。我定义了一个信号类,线程用它向侦听器发出异常。它还可以用于从线程返回值。例子:

import threading

class Signal:
    def __init__(self):
        self._subscribers = list()

    def emit(self, *args, **kwargs):
        for func in self._subscribers:
            func(*args, **kwargs)

    def connect(self, func):
        self._subscribers.append(func)

    def disconnect(self, func):
        try:
            self._subscribers.remove(func)
        except ValueError:
            raise ValueError('Function {0} not removed from {1}'.format(func, self))


class WorkerThread(threading.Thread):

    def __init__(self, *args, **kwargs):
        super(WorkerThread, self).__init__(*args, **kwargs)
        self.Exception = Signal()
        self.Result = Signal()

    def run(self):
        if self._Thread__target is not None:
            try:
                self._return_value = self._Thread__target(*self._Thread__args, **self._Thread__kwargs)
            except Exception as e:
                self.Exception.emit(e)
            else:
                self.Result.emit(self._return_value)

if __name__ == '__main__':
    import time

    def handle_exception(exc):
        print exc.message

    def handle_result(res):
        print res

    def a():
        time.sleep(1)
        raise IOError('a failed')

    def b():
        time.sleep(2)
        return 'b returns'

    t = WorkerThread(target=a)
    t2 = WorkerThread(target=b)
    t.Exception.connect(handle_exception)
    t2.Result.connect(handle_result)
    t.start()
    t2.start()

    print 'Threads started'

    t.join()
    t2.join()
    print 'Done'

我没有足够的使用线程的经验来断言这是一种完全安全的方法。但这对我来说很管用,我喜欢这种灵活性。