我有一个用例来生成cURL命令(我可以在终端使用)从httpServletRequest实例。我创建了一个这样的方法。您可以直接在终端中复制粘贴此方法的输出

private StringBuilder generateCURL(final HttpServletRequest httpServletRequest) {
    final StringBuilder curlCommand = new StringBuilder();
    curlCommand.append("curl ");

    // iterating over headers.
    for (Enumeration<?> e = httpServletRequest.getHeaderNames(); e.hasMoreElements();) {
        String headerName = (String) e.nextElement();
        String headerValue = httpServletRequest.getHeader(headerName);
        // skipping cookies, as we're appending cookies separately.
        if (Objects.equals(headerName, "cookie")) {
            continue;
        }
        if (headerName != null && headerValue != null) {
            curlCommand.append(String.format(" -H \"%s:%s\" ", headerName, headerValue));
        }
    }

    // iterating over cookies.
    final Cookie[] cookieArray = httpServletRequest.getCookies();
    final StringBuilder cookies = new StringBuilder();
    for (Cookie cookie : cookieArray) {
        if (cookie.getName() != null && cookie.getValue() != null) {
            cookies.append(cookie.getName());
            cookies.append('=');
            cookies.append(cookie.getValue());
            cookies.append("; ");
        }
    }
    curlCommand.append(" --cookie \"" + cookies.toString() + "\"");

    // appending request url.
    curlCommand.append(" \"" + httpServletRequest.getRequestURL().toString() + "\"");
    return curlCommand;
}

你可以使用滤镜。

@Override
public void doFilter(ServletRequest arg0, ServletResponse arg1, FilterChain arg2) throws IOException, ServletException {
        HttpServletRequest test1=    (HttpServletRequest) arg0;
       
     test1.getRequestURL()); it gives  http://localhost:8081/applicationName/menu/index.action
     test1.getRequestURI()); it gives applicationName/menu/index.action
     String pathname = test1.getServletPath()); it gives //menu/index.action
      
  
    if(pathname.equals("//menu/index.action")){ 
        arg2.doFilter(arg0, arg1); // call to urs servlet or frameowrk managed controller method


       // in resposne 
       HttpServletResponse httpResp = (HttpServletResponse) arg1;
       RequestDispatcher rd = arg0.getRequestDispatcher("another.jsp");     
       rd.forward(arg0, arg1);
}

不要忘记在web.xml的filter mapping中放入<dispatcher>FORWARD</dispatcher>

// http://hostname.com/mywebapp/servlet/MyServlet/a/b;c=123?d=789

public static String getUrl(HttpServletRequest req) {
    String reqUrl = req.getRequestURL().toString();
    String queryString = req.getQueryString();   // d=789
    if (queryString != null) {
        reqUrl += "?"+queryString;
    }
    return reqUrl;
}

我有一个用例来生成cURL命令(我可以在终端使用)从httpServletRequest实例。我创建了一个这样的方法。您可以直接在终端中复制粘贴此方法的输出

private StringBuilder generateCURL(final HttpServletRequest httpServletRequest) {
    final StringBuilder curlCommand = new StringBuilder();
    curlCommand.append("curl ");

    // iterating over headers.
    for (Enumeration<?> e = httpServletRequest.getHeaderNames(); e.hasMoreElements();) {
        String headerName = (String) e.nextElement();
        String headerValue = httpServletRequest.getHeader(headerName);
        // skipping cookies, as we're appending cookies separately.
        if (Objects.equals(headerName, "cookie")) {
            continue;
        }
        if (headerName != null && headerValue != null) {
            curlCommand.append(String.format(" -H \"%s:%s\" ", headerName, headerValue));
        }
    }

    // iterating over cookies.
    final Cookie[] cookieArray = httpServletRequest.getCookies();
    final StringBuilder cookies = new StringBuilder();
    for (Cookie cookie : cookieArray) {
        if (cookie.getName() != null && cookie.getValue() != null) {
            cookies.append(cookie.getName());
            cookies.append('=');
            cookies.append(cookie.getValue());
            cookies.append("; ");
        }
    }
    curlCommand.append(" --cookie \"" + cookies.toString() + "\"");

    // appending request url.
    curlCommand.append(" \"" + httpServletRequest.getRequestURL().toString() + "\"");
    return curlCommand;
}

我使用这个方法:

public static String getURL(HttpServletRequest req) {

    String scheme = req.getScheme();             // http
    String serverName = req.getServerName();     // hostname.com
    int serverPort = req.getServerPort();        // 80
    String contextPath = req.getContextPath();   // /mywebapp
    String servletPath = req.getServletPath();   // /servlet/MyServlet
    String pathInfo = req.getPathInfo();         // /a/b;c=123
    String queryString = req.getQueryString();          // d=789

    // Reconstruct original requesting URL
    StringBuilder url = new StringBuilder();
    url.append(scheme).append("://").append(serverName);

    if (serverPort != 80 && serverPort != 443) {
        url.append(":").append(serverPort);
    }

    url.append(contextPath).append(servletPath);

    if (pathInfo != null) {
        url.append(pathInfo);
    }
    if (queryString != null) {
        url.append("?").append(queryString);
    }
    return url.toString();
}

HttpUtil已弃用，这是正确的方法

StringBuffer url = req.getRequestURL();
String queryString = req.getQueryString();
if (queryString != null) {
    url.append('?');
    url.append(queryString);
}
String requestURL = url.toString();