我正在寻找一种优雅的方法来更改DataFrame中指定的列名。
播放数据…
import pandas as pd
d = {
'one': [1, 2, 3, 4, 5],
'two': [9, 8, 7, 6, 5],
'three': ['a', 'b', 'c', 'd', 'e']
}
df = pd.DataFrame(d)
到目前为止,我找到的最优雅的解决方案……
names = df.columns.tolist()
names[names.index('two')] = 'new_name'
df.columns = names
我本想说一句简单的俏皮话…这次尝试失败了……
df.columns[df.columns.tolist().index('one')] = 'another_name'
感激地接受任何提示。
一行代码确实存在:
In [27]: df=df.rename(columns = {'two':'new_name'})
In [28]: df
Out[28]:
one three new_name
0 1 a 9
1 2 b 8
2 3 c 7
3 4 d 6
4 5 e 5
下面是重命名方法的文档字符串。
Definition: df.rename(self, index=None, columns=None, copy=True, inplace=False)
Docstring:
Alter index and / or columns using input function or
functions. Function / dict values must be unique (1-to-1). Labels not
contained in a dict / Series will be left as-is.
Parameters
----------
index : dict-like or function, optional
Transformation to apply to index values
columns : dict-like or function, optional
Transformation to apply to column values
copy : boolean, default True
Also copy underlying data
inplace : boolean, default False
Whether to return a new DataFrame. If True then value of copy is
ignored.
See also
--------
Series.rename
Returns
-------
renamed : DataFrame (new object)
一行代码确实存在:
In [27]: df=df.rename(columns = {'two':'new_name'})
In [28]: df
Out[28]:
one three new_name
0 1 a 9
1 2 b 8
2 3 c 7
3 4 d 6
4 5 e 5
下面是重命名方法的文档字符串。
Definition: df.rename(self, index=None, columns=None, copy=True, inplace=False)
Docstring:
Alter index and / or columns using input function or
functions. Function / dict values must be unique (1-to-1). Labels not
contained in a dict / Series will be left as-is.
Parameters
----------
index : dict-like or function, optional
Transformation to apply to index values
columns : dict-like or function, optional
Transformation to apply to column values
copy : boolean, default True
Also copy underlying data
inplace : boolean, default False
Whether to return a new DataFrame. If True then value of copy is
ignored.
See also
--------
Series.rename
Returns
-------
renamed : DataFrame (new object)