函数

CREATE FUNCTION dbo.SplitToRows (@column varchar(100), @separator varchar(10))
RETURNS @rtnTable TABLE
  (
  ID int identity(1,1),
  ColumnA varchar(max)
  )
 AS
BEGIN
    DECLARE @position int = 0;
    DECLARE @endAt int = 0;
    DECLARE @tempString varchar(100);
    
    set @column = ltrim(rtrim(@column));

    WHILE @position<=len(@column)
    BEGIN       
        set @endAt = CHARINDEX(@separator,@column,@position);
            if(@endAt=0)
            begin
            Insert into @rtnTable(ColumnA) Select substring(@column,@position,len(@column)-@position);
            break;
            end;
        set @tempString = substring(ltrim(rtrim(@column)),@position,@endAt-@position);

        Insert into @rtnTable(ColumnA) select @tempString;
        set @position=@endAt+1;
    END;
    return;
END;

用例

select * from dbo.SplitToRows('T14; p226.0001; eee; 3554;', ';');

或者只是一个有多个结果集的选择

DECLARE @column varchar(max)= '1234; 4748;abcde; 324432';
DECLARE @separator varchar(10) = ';';
DECLARE @position int = 0;
DECLARE @endAt int = 0;
DECLARE @tempString varchar(100);

set @column = ltrim(rtrim(@column));

WHILE @position<=len(@column)
BEGIN       
    set @endAt = CHARINDEX(@separator,@column,@position);
        if(@endAt=0)
        begin
        Select substring(@column,@position,len(@column)-@position);
        break;
        end;
    set @tempString = substring(ltrim(rtrim(@column)),@position,@endAt-@position);

    select @tempString;
    set @position=@endAt+1;
END;

很晚了，但是试试这个:

SELECT ColumnID, Column1, value  --Do not change 'value' name. Leave it as it is.
FROM tbl_Sample  
CROSS APPLY STRING_SPLIT(Tags, ','); --'Tags' is the name of column containing comma separated values

所以我们有了这个: tbl_Sample:

ColumnID|   Column1 |   Tags
--------|-----------|-------------
1       |   ABC     |   10,11,12    
2       |   PQR     |   20,21,22

运行此查询后:

ColumnID|   Column1 |   value
--------|-----------|-----------
1       |   ABC     |   10
1       |   ABC     |   11
1       |   ABC     |   12
2       |   PQR     |   20
2       |   PQR     |   21
2       |   PQR     |   22

谢谢!

以下工作在sql server 2008

select *, ROW_NUMBER() OVER(order by items) as row# 
from 
( select 134 myColumn1, 34 myColumn2, 'd,c,k,e,f,g,h,a' comaSeperatedColumn) myTable
    cross apply 
SPLIT (rtrim(comaSeperatedColumn), ',') splitedTable -- gives 'items'  column 

将得到所有的笛卡尔积与原表列加上“项目”的分割表。

可以使用以下函数提取数据

CREATE FUNCTION [dbo].[SplitString]
(    
    @RowData NVARCHAR(MAX),
    @Delimeter NVARCHAR(MAX)
)
RETURNS @RtnValue TABLE 
(
    ID INT IDENTITY(1,1),
    Data NVARCHAR(MAX)
) 
AS
BEGIN 
    DECLARE @Iterator INT;
    SET @Iterator = 1;

    DECLARE @FoundIndex INT;
    SET @FoundIndex = CHARINDEX(@Delimeter,@RowData);

    WHILE (@FoundIndex>0)
    BEGIN
        INSERT INTO @RtnValue (data)
        SELECT 
            Data = LTRIM(RTRIM(SUBSTRING(@RowData, 1, @FoundIndex - 1)));

        SET @RowData = SUBSTRING(@RowData,
                @FoundIndex + DATALENGTH(@Delimeter) / 2,
                LEN(@RowData));

        SET @Iterator = @Iterator + 1;
        SET @FoundIndex = CHARINDEX(@Delimeter, @RowData);
    END;
    
    INSERT INTO @RtnValue (Data)
    SELECT Data = LTRIM(RTRIM(@RowData));

    RETURN;
END;

select t.OtherID,x.Kod
    from testData t
    cross apply (select Code from dbo.Split(t.Data,',') ) x

检查这个

 SELECT A.OtherID,  
     Split.a.value('.', 'VARCHAR(100)') AS Data  
 FROM  
 (
     SELECT OtherID,  
         CAST ('<M>' + REPLACE(Data, ',', '</M><M>') + '</M>' AS XML) AS Data  
     FROM  Table1
 ) AS A CROSS APPLY Data.nodes ('/M') AS Split(a);