在Android中限制EditText文本长度的最佳方法是什么?

有没有通过xml实现这一点的方法?


当前回答

TextView tv = new TextView(this);
tv.setFilters(new InputFilter[]{ new InputFilter.LengthFilter(250) });

其他回答

由于goto10的观察,我将以下代码组合在一起,通过设置最大长度来防止丢失其他过滤器:

/**
 * This sets the maximum length in characters of an EditText view. Since the
 * max length must be done with a filter, this method gets the current
 * filters. If there is already a length filter in the view, it will replace
 * it, otherwise, it will add the max length filter preserving the other
 * 
 * @param view
 * @param length
 */
public static void setMaxLength(EditText view, int length) {
    InputFilter curFilters[];
    InputFilter.LengthFilter lengthFilter;
    int idx;

    lengthFilter = new InputFilter.LengthFilter(length);

    curFilters = view.getFilters();
    if (curFilters != null) {
        for (idx = 0; idx < curFilters.length; idx++) {
            if (curFilters[idx] instanceof InputFilter.LengthFilter) {
                curFilters[idx] = lengthFilter;
                return;
            }
        }

        // since the length filter was not part of the list, but
        // there are filters, then add the length filter
        InputFilter newFilters[] = new InputFilter[curFilters.length + 1];
        System.arraycopy(curFilters, 0, newFilters, 0, curFilters.length);
        newFilters[curFilters.length] = lengthFilter;
        view.setFilters(newFilters);
    } else {
        view.setFilters(new InputFilter[] { lengthFilter });
    }
}
EditText editText = new EditText(this);
int maxLength = 3;    
editText.setFilters(new InputFilter[] {new InputFilter.LengthFilter(maxLength)});

xml中的简单方式:

android:maxLength="4"

如果您需要在xml编辑文本中设置4个字符,请使用

<EditText
    android:id="@+id/edtUserCode"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:maxLength="4"
    android:hint="Enter user code" />

科特林:

edit_text.filters += InputFilter.LengthFilter(10)

中兴刀片A520具有奇怪的效果。当您键入超过10个符号(例如15个)时,EditText将显示前10个符号,但其他5个符号不可见且不可访问。但当您使用Backspace删除符号时,它会先删除右边的5个符号,然后删除剩下的10个符号。要克服这种行为,请使用以下解决方案:

android:inputType="textNoSuggestions|textVisiblePassword"
android:maxLength="10"

或者:

android:inputType="textNoSuggestions"

或者,如果您想获得建议:

private class EditTextWatcher(private val view: EditText) : TextWatcher {
    private var position = 0
    private var oldText = ""

    override fun afterTextChanged(s: Editable?) = Unit

    override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) {
        oldText = s?.toString() ?: ""
        position = view.selectionStart
    }

    override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) {
        val newText = s?.toString() ?: ""
        if (newText.length > 10) {
            with(view) {
                setText(oldText)
                position = if (start > 0 && count > 2) {
                    // Text paste in nonempty field.
                    start
                } else {
                    if (position in 1..10 + 1) {
                        // Symbol paste in the beginning or middle of the field.
                        position - 1
                    } else {
                        if (start > 0) {
                            // Adding symbol to the end of the field.
                            start - 1
                        } else {
                            // Text paste in the empty field.
                            0
                        }
                    }
                }
                setSelection(position)
            }
        }
    }
}

// Usage:
editTextWatcher = EditTextWatcher(view.edit_text)
view.edit_text.addTextChangedListener(editTextWatcher)

以编程方式为Java尝试以下操作:

myEditText(new InputFilter[] {new InputFilter.LengthFilter(CUSTOM_MAX_LEN)});