xml中的简单方式：

android:maxLength="4"

如果您需要在xml编辑文本中设置4个字符，请使用

<EditText
    android:id="@+id/edtUserCode"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:maxLength="4"
    android:hint="Enter user code" />

xml中的简单方式：

android:maxLength="@{length}"

要以编程方式设置它，可以使用以下函数

public static void setMaxLengthOfEditText(EditText editText, int length) {
    InputFilter[] filters = editText.getFilters();
    List arrayList = new ArrayList();
    int i2 = 0;
    if (filters != null && filters.length > 0) {
        int filtersSize = filters.length;
        int i3 = 0;
        while (i2 < filtersSize) {
            Object obj = filters[i2];
            if (obj instanceof LengthFilter) {
                arrayList.add(new LengthFilter(length));
                i3 = 1;
            } else {
                arrayList.add(obj);
            }
            i2++;
        }
        i2 = i3;
    }
    if (i2 == 0) {
        arrayList.add(new LengthFilter(length));
    }
    if (!arrayList.isEmpty()) {
        editText.setFilters((InputFilter[]) arrayList.toArray(new InputFilter[arrayList.size()]));
    }
}

对于其他想知道如何实现这一点的人，这里是我的扩展EditText类EditTextNumeric。

.setMaxLength（int）-设置最大位数

.setMaxValue（int）-限制最大整数值

.setMin（int）-限制最小整数值

.getValue（）-获取整数值

import android.content.Context;
import android.text.InputFilter;
import android.text.InputType;
import android.widget.EditText;

public class EditTextNumeric extends EditText {
    protected int max_value = Integer.MAX_VALUE;
    protected int min_value = Integer.MIN_VALUE;

    // constructor
    public EditTextNumeric(Context context) {
        super(context);
        this.setInputType(InputType.TYPE_CLASS_NUMBER);
    }

    // checks whether the limits are set and corrects them if not within limits
    @Override
    protected void onTextChanged(CharSequence text, int start, int before, int after) {
        if (max_value != Integer.MAX_VALUE) {
            try {
                if (Integer.parseInt(this.getText().toString()) > max_value) {
                    // change value and keep cursor position
                    int selection = this.getSelectionStart();
                    this.setText(String.valueOf(max_value));
                    if (selection >= this.getText().toString().length()) {
                        selection = this.getText().toString().length();
                    }
                    this.setSelection(selection);
                }
            } catch (NumberFormatException exception) {
                super.onTextChanged(text, start, before, after);
            }
        }
        if (min_value != Integer.MIN_VALUE) {
            try {
                if (Integer.parseInt(this.getText().toString()) < min_value) {
                    // change value and keep cursor position
                    int selection = this.getSelectionStart();
                    this.setText(String.valueOf(min_value));
                    if (selection >= this.getText().toString().length()) {
                        selection = this.getText().toString().length();
                    }
                    this.setSelection(selection);
                }
            } catch (NumberFormatException exception) {
                super.onTextChanged(text, start, before, after);
            }
        }
        super.onTextChanged(text, start, before, after);
    }

    // set the max number of digits the user can enter
    public void setMaxLength(int length) {
        InputFilter[] FilterArray = new InputFilter[1];
        FilterArray[0] = new InputFilter.LengthFilter(length);
        this.setFilters(FilterArray);
    }

    // set the maximum integer value the user can enter.
    // if exeeded, input value will become equal to the set limit
    public void setMaxValue(int value) {
        max_value = value;
    }
    // set the minimum integer value the user can enter.
    // if entered value is inferior, input value will become equal to the set limit
    public void setMinValue(int value) {
        min_value = value;
    }

    // returns integer value or 0 if errorous value
    public int getValue() {
        try {
            return Integer.parseInt(this.getText().toString());
        } catch (NumberFormatException exception) {
            return 0;
        }
    }
}

示例用法：

final EditTextNumeric input = new EditTextNumeric(this);
input.setMaxLength(5);
input.setMaxValue(total_pages);
input.setMinValue(1);

当然，适用于EditText的所有其他方法和属性也都有效。

我使用的是“maxLength”，但它对我不起作用。因此，根据我的经验，我尝试了一些方法。我发现了问题。我必须申报身份证。然后：

android:id="@+id/editTextTest"
android:maxLength="10"

由于goto10的观察，我将以下代码组合在一起，通过设置最大长度来防止丢失其他过滤器：

/**
 * This sets the maximum length in characters of an EditText view. Since the
 * max length must be done with a filter, this method gets the current
 * filters. If there is already a length filter in the view, it will replace
 * it, otherwise, it will add the max length filter preserving the other
 * 
 * @param view
 * @param length
 */
public static void setMaxLength(EditText view, int length) {
    InputFilter curFilters[];
    InputFilter.LengthFilter lengthFilter;
    int idx;

    lengthFilter = new InputFilter.LengthFilter(length);

    curFilters = view.getFilters();
    if (curFilters != null) {
        for (idx = 0; idx < curFilters.length; idx++) {
            if (curFilters[idx] instanceof InputFilter.LengthFilter) {
                curFilters[idx] = lengthFilter;
                return;
            }
        }

        // since the length filter was not part of the list, but
        // there are filters, then add the length filter
        InputFilter newFilters[] = new InputFilter[curFilters.length + 1];
        System.arraycopy(curFilters, 0, newFilters, 0, curFilters.length);
        newFilters[curFilters.length] = lengthFilter;
        view.setFilters(newFilters);
    } else {
        view.setFilters(new InputFilter[] { lengthFilter });
    }
}

我看到了很多好的解决方案，但我想给出一个我认为更完整、更人性化的解决方案：

1、限制长度。2、如果输入更多，则发出回调以触发吐司。3、光标可以在中间或尾部。4、用户可以通过粘贴字符串进行输入。5、始终丢弃溢出输入并保留原点。

public class LimitTextWatcher implements TextWatcher {

    public interface IF_callback{
        void callback(int left);
    }

    public IF_callback if_callback;

    EditText editText;
    int maxLength;

    int cursorPositionLast;
    String textLast;
    boolean bypass;

    public LimitTextWatcher(EditText editText, int maxLength, IF_callback if_callback) {

        this.editText = editText;
        this.maxLength = maxLength;
        this.if_callback = if_callback;
    }

    @Override
    public void beforeTextChanged(CharSequence s, int start, int count, int after) {

        if (bypass) {

            bypass = false;

        } else {

            StringBuilder stringBuilder = new StringBuilder();
            stringBuilder.append(s);
            textLast = stringBuilder.toString();

            this.cursorPositionLast = editText.getSelectionStart();
        }
    }

    @Override
    public void onTextChanged(CharSequence s, int start, int before, int count) {

    }

    @Override
    public void afterTextChanged(Editable s) {
        if (s.toString().length() > maxLength) {

            int left = maxLength - s.toString().length();

            bypass = true;
            s.clear();

            bypass = true;
            s.append(textLast);

            editText.setSelection(this.cursorPositionLast);

            if (if_callback != null) {
                if_callback.callback(left);
            }
        }

    }

}


edit_text.addTextChangedListener(new LimitTextWatcher(edit_text, MAX_LENGTH, new LimitTextWatcher.IF_callback() {
    @Override
    public void callback(int left) {
        if(left <= 0) {
            Toast.makeText(MainActivity.this, "input is full", Toast.LENGTH_SHORT).show();
        }
    }
}));

我没能做到的是，如果用户高亮显示当前输入的一部分并试图粘贴一个很长的字符串，我不知道如何恢复高亮显示。

例如，最大长度设置为10，用户输入“12345678”，并将“345”标记为突出显示，然后尝试粘贴一个超过限制的字符串“0000”。

当我尝试使用edit_text.setSelection（start=2，end=4）恢复原点状态时，结果是，它只插入2个空格作为“12 345 678”，而不是原点高亮显示。我希望有人解决这个问题。