我在看Pluralsight关于React的课程,老师说道具不应该被改变。我现在正在读一篇关于道具vs.国家的文章(uberVU/react-guide),它说

道具和状态更改都会触发呈现更新。

文章后面说:

Props(属性的缩写)是组件的配置,如果可以的话,是它的选项。它们是从上面接收的,是不可变的。

所以道具可以改变,但它们应该是不可变的? 什么时候应该使用道具,什么时候应该使用状态? 如果你有一个React组件需要的数据,它应该通过道具或设置在React组件通过getInitialState?


当前回答

主要的区别是状态只能在组件内部处理,而道具则在组件外部处理。如果我们从外部获取数据并进行处理,在这种情况下,我们应该使用状态。

其他回答

简而言之。

道具值不能改变[不可变] 使用setState方法[mutable]可以改变状态值

在React中,道具和状态之间有一些关键的区别。道具是不可变的——一旦设置好,就不能更改。另一方面,状态可以在任何时候改变。道具也从父组件传递给子组件,而状态是单个组件的局部状态。

你可以通过将它与Plain联系起来来更好地理解它 JS函数。

简单地说,

State是组件的本地状态,不能在组件外部访问和修改。它相当于函数中的局部变量。

普通JS函数

const DummyFunction = () => {
  let name = 'Manoj';
  console.log(`Hey ${name}`)
}

反应组件

class DummyComponent extends React.Component {
  state = {
    name: 'Manoj'
  }
  render() {
    return <div>Hello {this.state.name}</div>;
  }

另一方面,通过赋予组件以道具形式从父组件接收数据的能力,道具可以使组件可重用。它们等价于函数参数。

普通JS函数

const DummyFunction = (name) => {
  console.log(`Hey ${name}`)
}

// when using the function
DummyFunction('Manoj');
DummyFunction('Ajay');

反应组件

class DummyComponent extends React.Component {
  render() {
    return <div>Hello {this.props.name}</div>;
  }

}

// when using the component
<DummyComponent name="Manoj" />
<DummyComponent name="Ajay" />

工作人员:Manoj Singh Negi

文章链接:解释了反应状态与道具

Basically, props and state are two ways the component can know what and how to render. Which part of the application state belongs to state and which to some top-level store, is more related to your app design, than to how React works. The simplest way to decide, IMO, is to think, whether this particular piece of data is useful for application as a whole, or it's some local information. Also, it's important to not duplicate state, so if some piece of data can be calculated from props - it should calculated from props.

For example, let's say you have some dropdown control (which wraps standart HTML select for custom styling), which can a) select some value from list, and b) be opened or closed (i.e., the options list displayed or hidden). Now, let's say your app displays a list of items of some sort and your dropdown controls filter for list entries. Then, it would be best to pass active filter value as a prop, and keep opened/closed state local. Also, to make it functional, you would pass an onChange handler from parent component, which would be called inside dropdown element and send updated information (new selected filter) to the store immediately. On the other hand, opened/closed state can be kept inside dropdown component, because the rest of the application doesn't really care if the control is opened, until user actually changes it value.

下面的代码是不完全工作,它需要css和处理下拉单击/模糊/改变事件,但我想保持示例最小。希望这有助于理解其中的区别。

const _store = {
    items: [
    { id: 1, label: 'One' },
    { id: 2, label: 'Two' },
    { id: 3, label: 'Three', new: true },
    { id: 4, label: 'Four', new: true },
    { id: 5, label: 'Five', important: true },
    { id: 6, label: 'Six' },
    { id: 7, label: 'Seven', important: true },
    ],
  activeFilter: 'important',
  possibleFilters: [
    { key: 'all', label: 'All' },
    { key: 'new', label: 'New' },
    { key: 'important', label: 'Important' }
  ]
}

function getFilteredItems(items, filter) {
    switch (filter) {
    case 'all':
        return items;

    case 'new':
        return items.filter(function(item) { return Boolean(item.new); });

    case 'important':
        return items.filter(function(item) { return Boolean(item.important); });

    default:
        return items;
  }
}

const App = React.createClass({
  render: function() {
    return (
            <div>
            My list:

            <ItemList   items={this.props.listItems} />
          <div>
            <Dropdown 
              onFilterChange={function(e) {
                _store.activeFilter = e.currentTarget.value;
                console.log(_store); // in real life, some action would be dispatched here
              }}
              filterOptions={this.props.filterOptions}
              value={this.props.activeFilter}
              />
          </div>
        </div>
      );
  }
});

const ItemList = React.createClass({
  render: function() {
    return (
      <div>
        {this.props.items.map(function(item) {
          return <div key={item.id}>{item.id}: {item.label}</div>;
        })}
      </div>
    );
  }
});

const Dropdown = React.createClass({
    getInitialState: function() {
    return {
        isOpen: false
    };
  },

  render: function() {
    return (
        <div>
            <select 
            className="hidden-select" 
          onChange={this.props.onFilterChange}
          value={this.props.value}>
            {this.props.filterOptions.map(function(option) {
            return <option value={option.key} key={option.key}>{option.label}</option>
          })}
        </select>

        <div className={'custom-select' + (this.state.isOpen ? ' open' : '')} onClick={this.onClick}>
            <div className="selected-value">{this.props.activeFilter}</div>
          {this.props.filterOptions.map(function(option) {
            return <div data-value={option.key} key={option.key}>{option.label}</div>
          })}
        </div>
      </div>
    );
  },

  onClick: function(e) {
    this.setState({
        isOpen: !this.state.isOpen
    });
  }
});

ReactDOM.render(
  <App 
    listItems={getFilteredItems(_store.items, _store.activeFilter)} 
    filterOptions={_store.possibleFilters}
    activeFilter={_store.activeFilter}
    />,
  document.getElementById('root')
);

react中的state和props都用于将数据控制到组件中,通常props由父组件设置并传递给子组件,并且它们在整个组件中都是固定的。对于将要改变的数据,我们必须使用状态。道具是不可变的,而状态是可变的,如果你想改变道具,你可以从父组件做,然后传递给子组件。