另一种方法(credit):

@For /F "tokens=2,3,4 delims=/ " %%A in ('Date /t') do @( 
    Set Month=%%A
    Set Day=%%B
    Set Year=%%C
)

@echo DAY = %Day%
@echo Month = %Month%
@echo Year = %Year%

请注意，我在这里的答案仍然依赖于日期和月份的顺序，由区域设置决定-不知道如何解决这个问题。

不幸的是，这并不是不受区域设置的影响，但它确实是你想要的。

set hour=%time:~0,2%
if "%time:~0,1%"==" " set hour=0%time:~1,1%
set _my_datetime=%date:~10,4%-%date:~4,2%-%date:~7,2%_%hour%%time:~3,2%

你能在维基百科上找到的东西真是太神奇了。

这并不是真的更简短，但可能是一种更灵活的方式(来源):

FOR /F "TOKENS=1* DELIMS= " %%A IN ('DATE/T') DO SET CDATE=%%B
FOR /F "TOKENS=1,2 eol=/ DELIMS=/ " %%A IN ('DATE/T') DO SET mm=%%B
FOR /F "TOKENS=1,2 DELIMS=/ eol=/" %%A IN ('echo %CDATE%') DO SET dd=%%B
FOR /F "TOKENS=2,3 DELIMS=/ " %%A IN ('echo %CDATE%') DO SET yyyy=%%B
SET date=%mm%%dd%%yyyy%

我用这个(同样不是地区独立的(英国))

set bklog=%date:~6,4%-%date:~3,2%-%date:~0,2%_%time:~0,2%%time:~3,2%

我用vMax的批处理文件更改了答案，所以它也适用于荷兰语。 荷兰语(尽管我们是持久性的)在%date%、date/t和date中有一些更改，这些更改破坏了原始的批处理文件。

如果有些人也能检查其他Windows locale，并报告结果，那就太好了。 如果批处理文件在您的位置失败，那么请在命令提示符中包含这两个语句的输出: 回音:^ |日期 日期/ t

这是你应该从批处理文件中得到的输出示例:

C:\temp>set-date-cmd.bat
Today is Year: [2011] Month: [01] Day: [03]
20110103

以下是修改后的代码及其原因:

:: https://stackoverflow.com/questions/203090/how-to-get-current-datetime-on-windows-command-line-in-a-suitable-format-for-usi
:: Works on any NT/2k machine independent of regional date settings
::
:: 20110103 - adapted by jeroen@pluimers.com for Dutch locale
:: Dutch will get jj as year from echo:^|date, so the '%%c' trick does not work as it will fill 'jj', but we want 'yy'
:: luckily, all countries seem to have year at the end: http://en.wikipedia.org/wiki/Calendar_date
::            set '%%c'=%%k
::            set 'yy'=%%k
::
:: In addition, date will display the current date before the input prompt using dashes
:: in Dutch, but using slashes in English, so there will be two occurances of the outer loop in Dutch
:: and one occurence in English.
:: This skips the first iteration:
::        if "%%a" GEQ "A"
::
:: echo:^|date
:: Huidige datum: ma 03-01-2011
:: Voer de nieuwe datum in: (dd-mm-jj)
:: The current date is: Mon 01/03/2011
:: Enter the new date: (mm-dd-yy)
::
:: date/t
:: ma 03-01-2011
:: Mon 01/03/2011
::
:: The assumption in this batch-file is that echo:^|date will return the date format
:: using either mm and dd or dd and mm in the first two valid tokens on the second line, and the year as the last token.
::
:: The outer loop will get the right tokens, the inner loop assigns the variables depending on the tokens.
:: That will resolve the order of the tokens.
::
@ECHO off
    set v_day=
    set v_month=
    set v_year=

    SETLOCAL ENABLEEXTENSIONS
    if "%date%A" LSS "A" (set toks=1-3) else (set toks=2-4)
::DEBUG echo toks=%toks%
      for /f "tokens=2-4 delims=(-)" %%a in ('echo:^|date') do (
::DEBUG echo first token=%%a
        if "%%a" GEQ "A" (
          for /f "tokens=%toks% delims=.-/ " %%i in ('date/t') do (
            set '%%a'=%%i
            set '%%b'=%%j
            set 'yy'=%%k
          )
        )
      )
      if %'yy'% LSS 100 set 'yy'=20%'yy'%
      set Today=%'yy'%-%'mm'%-%'dd'%

    ENDLOCAL & SET v_year=%'yy'%& SET v_month=%'mm'%& SET v_day=%'dd'%

    ECHO Today is Year: [%V_Year%] Month: [%V_Month%] Day: [%V_Day%]
    set datestring=%V_Year%%V_Month%%V_Day%
    echo %datestring%

    :EOF

——基珀斯

我也遇到过类似的问题。我每天都会从FTP服务器上自动下载一个加密文件。我想使用gpg解密文件，将文件重命名为当前日期(YYYYMMDD格式)，并将解密文件放入正确部门的文件夹中。

我根据日期查看了几个重命名文件的建议，直到我偶然发现了这个简单的解决方案。

for /f "tokens=1-5 delims=/ " %%d in ("%date%") do rename "decrypted.txt" %%g-%%e-%%f.txt

它工作得很好(例如，文件名显示为“2011-06-14.txt”)。

(源)