我有一个这样的数据结构:
var someObject = {
'part1' : {
'name': 'Part 1',
'size': '20',
'qty' : '50'
},
'part2' : {
'name': 'Part 2',
'size': '15',
'qty' : '60'
},
'part3' : [
{
'name': 'Part 3A',
'size': '10',
'qty' : '20'
}, {
'name': 'Part 3B',
'size': '5',
'qty' : '20'
}, {
'name': 'Part 3C',
'size': '7.5',
'qty' : '20'
}
]
};
我想使用这些变量访问数据:
var part1name = "part1.name";
var part2quantity = "part2.qty";
var part3name1 = "part3[0].name";
part1name应该用someObject.part1.name的值填充,即“Part 1”。part2quantity也是一样,它的容量是60。
有没有办法实现这与纯javascript或JQuery?
我还没有找到一个包来使用字符串路径执行所有操作,所以我最终编写了自己的快速小包,它支持insert(), get()(默认返回),set()和remove()操作。
您可以使用点表示法、括号、数字索引、字符串数字属性以及非单词字符的键。简单用法如下:
> var jsocrud = require('jsocrud');
...
// Get (Read) ---
> var obj = {
> foo: [
> {
> 'key w/ non-word chars': 'bar'
> }
> ]
> };
undefined
> jsocrud.get(obj, '.foo[0]["key w/ non-word chars"]');
'bar'
https://www.npmjs.com/package/jsocrud
https://github.com/vertical-knowledge/jsocrud
这是我使用的解决方案:
function resolve(path, obj=self, separator='.') {
var properties = Array.isArray(path) ? path : path.split(separator)
return properties.reduce((prev, curr) => prev?.[curr], obj)
}
使用示例:
// accessing property path on global scope
resolve("document.body.style.width")
// or
resolve("style.width", document.body)
// accessing array indexes
// (someObject has been defined in the question)
resolve("part3.0.size", someObject) // returns '10'
// accessing non-existent properties
// returns undefined when intermediate properties are not defined:
resolve('properties.that.do.not.exist', {hello:'world'})
// accessing properties with unusual keys by changing the separator
var obj = { object: { 'a.property.name.with.periods': 42 } }
resolve('object->a.property.name.with.periods', obj, '->') // returns 42
// accessing properties with unusual keys by passing a property name array
resolve(['object', 'a.property.name.with.periods'], obj) // returns 42
限制:
不能将方括号([])用于数组下标-尽管在分隔符令牌之间指定数组下标(例如,.)可以正常工作,如上所示。
基于前面的回答,我创建了一个也可以处理括号的函数。但由于裂开,里面没有点。
function get(obj, str) {
return str.split(/\.|\[/g).map(function(crumb) {
return crumb.replace(/\]$/, '').trim().replace(/^(["'])((?:(?!\1)[^\\]|\\.)*?)\1$/, (match, quote, str) => str.replace(/\\(\\)?/g, "$1"));
}).reduce(function(obj, prop) {
return obj ? obj[prop] : undefined;
}, obj);
}
使用对象扫描,这就变成了一行。然而,更重要的是,这个解决方案考虑性能:
在搜索期间遍历一次输入(即使查询了多个键)
解析只在init上发生一次(如果查询多个对象)
允许使用*进行扩展语法
// const objectScan = require('object-scan');
const someObject = { part1: { name: 'Part 1', size: '20', qty: '50' }, part2: { name: 'Part 2', size: '15', qty: '60' }, part3: [{ name: 'Part 3A', size: '10', qty: '20' }, { name: 'Part 3B', size: '5', qty: '20' }, { name: 'Part 3C', size: '7.5', qty: '20' }] };
const get = (haystack, needle) => objectScan([needle], { rtn: 'value', abort: true })(haystack);
console.log(get(someObject, 'part1.name'));
// => Part 1
console.log(get(someObject, 'part2.qty'));
// => 60
console.log(get(someObject, 'part3[0].name'));
// => Part 3A
const getAll = (haystack, ...needles) => objectScan(needles, { reverse: false, rtn: 'entry', joined: true })(haystack);
console.log(getAll(someObject, 'part1.name', 'part2.qty', 'part3[0].name'));
/* =>
[ [ 'part1.name', 'Part 1' ],
[ 'part2.qty', '60' ],
[ 'part3[0].name', 'Part 3A' ] ]
*/
console.log(getAll(someObject, 'part1.*'));
/* =>
[ [ 'part1.name', 'Part 1' ],
[ 'part1.size', '20' ],
[ 'part1.qty', '50' ] ]
*/
.as-console-wrapper {max-height: 100% !important; top: 0}
<script src="https://bundle.run/object-scan@13.8.0"></script>
声明:我是object-scan的作者