你也可以使用自己编写的mixin，就像这样:

var DebounceMixin = {
  debounce: function(func, time, immediate) {
    var timeout = this.debouncedTimeout;
    if (!timeout) {
      if (immediate) func();
      this.debouncedTimeout = setTimeout(function() {
        if (!immediate) func();
        this.debouncedTimeout = void 0;
      }.bind(this), time);
    }
  }
};

然后像这样在你的组件中使用它:

var MyComponent = React.createClass({
  mixins: [DebounceMixin],
  handleClick: function(e) {
    this.debounce(function() {
      this.setState({
        buttonClicked: true
      });
    }.bind(this), 500, true);
  },
  render: function() {
    return (
      <button onClick={this.handleClick}></button>
    );
  }
});

这里有一个工作的TypeScript示例，供那些使用TS并想要debounce async函数的人使用。

function debounce<T extends (...args: any[]) => any>(time: number, func: T): (...funcArgs: Parameters<T>) => Promise<ReturnType<T>> {
     let timeout: Timeout;

     return (...args: Parameters<T>): Promise<ReturnType<T>> => new Promise((resolve) => {
         clearTimeout(timeout);
         timeout = setTimeout(() => {
             resolve(func(...args));
         }, time)
     });
 }

如果你正在使用redux，你可以通过中间件以一种非常优雅的方式做到这一点。你可以这样定义Debounce中间件:

var timeout;
export default store => next => action => {
  const { meta = {} } = action;
  if(meta.debounce){
    clearTimeout(timeout);
    timeout = setTimeout(() => {
      next(action)
    }, meta.debounce)
  }else{
    next(action)
  }
}

然后你可以添加debounging到动作创建者，比如:

export default debouncedAction = (payload) => ({
  type : 'DEBOUNCED_ACTION',
  payload : payload,
  meta : {debounce : 300}
}

实际上已经有中间件你可以脱离npm来为你做这件事。

/**
 * Returns a function with the same signature of input `callback` (but without an output) that if called, smartly
 * executes the `callback` in a debounced way.<br>
 * There is no `delay` (to execute the `callback`) in the self-delayed tries (try = calling debounced callback). It
 * will defer **only** subsequent tries (that are earlier than a minimum timeout (`delay` ms) after the latest
 * execution). It also **cancels stale tries** (that have been obsoleted because of creation of newer tries during the
 * same timeout).<br>
 * The timeout won't be expanded! So **the subsequent execution won't be deferred more than `delay`**, at all.
 * @param {Function} callback
 * @param {number} [delay=167] Defaults to `167` that is equal to "10 frames at 60 Hz" (`10 * (1000 / 60) ~= 167 ms`)
 * @return {Function}
 */
export function smartDebounce (callback, delay = 167) {
  let minNextExecTime = 0
  let timeoutId

  function debounced (...args) {
    const now = new Date().getTime()
    if (now > minNextExecTime) { // execute immediately
      minNextExecTime = now + delay // there would be at least `delay` ms between ...
      callback.apply(this, args) // ... two consecutive executions
      return
    }
    // schedule the execution:
    clearTimeout(timeoutId) // unset possible previous scheduling
    timeoutId = setTimeout( // set new scheduling
      () => {
        minNextExecTime = now + delay // there would be at least `delay` ms between ...
        callback.apply(this, args) // ... two consecutive executions
      },
      minNextExecTime - now, // 0 <= timeout <= `delay` ... (`minNextExecTime` <= `now` + `delay`)
    )
  }

  debounced.clear = clearTimeout.bind(null, timeoutId)

  return debounced
}

/**
 * Like React's `useCallback`, but will {@link smartDebounce smartly debounce} future executions.
 * @param {Function} callback
 * @param {[]} deps
 * @param {number} [delay=167] - Defaults to `167` that is equal to "10 frames at 60 Hz" (`10 * (1000 / 60) ~= 167 ms`)
 */
export const useDebounced = (callback, deps, delay = 167) =>
  useMemo(() => smartDebounce(callback, delay), [...deps, delay])

您可以使用Lodash debounce https://lodash.com/docs/4.17.5#debounce方法。它简单有效。

import * as lodash from lodash;

const update = (input) => {
    // Update the input here.
    console.log(`Input ${input}`);     
}

const debounceHandleUpdate = lodash.debounce((input) => update(input), 200, {maxWait: 200});

doHandleChange() {
   debounceHandleUpdate(input);
}

您还可以使用下面的方法取消debounce方法。

this.debounceHandleUpdate.cancel();

希望对你有所帮助。干杯! !

你试过吗?

function debounce(fn, delay) {
  var timer = null;
  return function() {
    var context = this,
      args = arguments;
    clearTimeout(timer);
    timer = setTimeout(function() {
      fn.apply(context, args);
    }, delay);
  };
}

var SearchBox = React.createClass({
  render: function() {
    return <input type="search" name="p" onChange={this.handleOnChange} />;
  },

  handleOnChange: function(event) {
    debounce(\\ Your handleChange code , 200);
  }
});