下面是Patrick Desjardins（别名Daok）代码，添加了一些注释和一些小改动：

/*
decimal_sep: character used as decimal separator, it defaults to '.' when omitted
thousands_sep: char used as thousands separator, it defaults to ',' when omitted
*/
Number.prototype.toMoney = function(decimals, decimal_sep, thousands_sep)
{
   var n = this,
   c = isNaN(decimals) ? 2 : Math.abs(decimals), // If decimal is zero we must take it. It means the user does not want to show any decimal
   d = decimal_sep || '.', // If no decimal separator is passed, we use the dot as default decimal separator (we MUST use a decimal separator)

   /*
   According to [https://stackoverflow.com/questions/411352/how-best-to-determine-if-an-argument-is-not-sent-to-the-javascript-function]
   the fastest way to check for not defined parameter is to use typeof value === 'undefined'
   rather than doing value === undefined.
   */
   t = (typeof thousands_sep === 'undefined') ? ',' : thousands_sep, // If you don't want to use a thousands separator you can pass empty string as thousands_sep value

   sign = (n < 0) ? '-' : '',

   // Extracting the absolute value of the integer part of the number and converting to string
   i = parseInt(n = Math.abs(n).toFixed(c)) + '',

   j = ((j = i.length) > 3) ? j % 3 : 0;
   return sign + (j ? i.substr(0, j) + t : '') + i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + t) + (c ? d + Math.abs(n - i).toFixed(c).slice(2) : '');
}

这里有一些测试：

// Some tests (do not forget parenthesis when using negative numbers and number with no decimals)
alert(123456789.67392.toMoney() + '\n' + 123456789.67392.toMoney(3) + '\n' + 123456789.67392.toMoney(0) + '\n' + (123456).toMoney() + '\n' + (123456).toMoney(0) + '\n' + 89.67392.toMoney() + '\n' + (89).toMoney());

// Some tests (do not forget parenthesis when using negative numbers and number with no decimals)
alert((-123456789.67392).toMoney() + '\n' + (-123456789.67392).toMoney(-3));

次要变化包括：

移动了一点Math.abs（小数），只有当不是NaN时才能执行。decimal_sep不能再是空字符串（必须使用某种十进制分隔符）我们使用typeof thousand_sep===“undefined”，如How best to determine if a argument is not send to JavaScript function中所建议的不需要（+n||0），因为这是Number对象

JSFiddle公司

已经有好的答案了。这里有一个简单的乐趣尝试：

function currencyFormat(no) {
  var ar = (+no).toFixed(2).split('.');
  return [
      numberFormat(ar[0] | 0),
      '.',
      ar[1]
  ].join('');
}


function numberFormat(no) {
  var str = no + '';
  var ar = [];
  var i  = str.length -1;

  while(i >= 0) {
    ar.push((str[i-2] || '') + (str[i-1] || '') + (str[i] || ''));
    i = i-3;
  }
  return ar.reverse().join(',');
}

然后运行一些示例：

console.log(
  currencyFormat(1),
  currencyFormat(1200),
  currencyFormat(123),
  currencyFormat(9870000),
  currencyFormat(12345),
  currencyFormat(123456.232)
)

使用正则表达式的较短方法（用于插入空格、逗号或点）：

    Number.prototype.toCurrencyString = function(){
        return this.toFixed(2).replace(/(\d)(?=(\d{3})+\b)/g, '$1 ');
    }

    n = 12345678.9;
    alert(n.toCurrencyString());

JavaScript中有一个内置函数toFixed：

var num = new Number(349);
document.write("$" + num.toFixed(2));

主要部分是插入千个分隔符，可以这样做：

<script type="text/javascript">
  function ins1000Sep(val) {
    val = val.split(".");
    val[0] = val[0].split("").reverse().join("");
    val[0] = val[0].replace(/(\d{3})/g, "$1,");
    val[0] = val[0].split("").reverse().join("");
    val[0] = val[0].indexOf(",") == 0 ? val[0].substring(1) : val[0];
    return val.join(".");
  }

  function rem1000Sep(val) {
    return val.replace(/,/g, "");
  }

  function formatNum(val) {
    val = Math.round(val*100)/100;
    val = ("" + val).indexOf(".") > -1 ? val + "00" : val + ".00";
    var dec = val.indexOf(".");
    return dec == val.length-3 || dec == 0 ? val : val.substring(0, dec+3);
  }
</script>

<button onclick="alert(ins1000Sep(formatNum(12313231)));">

PatrickDesjardins的回答看起来不错，但我更喜欢简单的JavaScript代码。下面是我刚刚编写的一个函数，用于输入一个数字并以货币格式返回（减去美元符号）：

// Format numbers to two decimals with commas
function formatDollar(num) {
    var p = num.toFixed(2).split(".");
    var chars = p[0].split("").reverse();
    var newstr = '';
    var count = 0;
    for (x in chars) {
        count++;
        if(count%3 == 1 && count != 1) {
            newstr = chars[x] + ',' + newstr;
        } else {
            newstr = chars[x] + newstr;
        }
    }
    return newstr + "." + p[1];
}