我想用JavaScript格式化价格。我想要一个函数,它将浮点作为参数,并返回如下格式的字符串:
"$ 2,500.00"
我该怎么做?
我想用JavaScript格式化价格。我想要一个函数,它将浮点作为参数,并返回如下格式的字符串:
"$ 2,500.00"
我该怎么做?
当前回答
在将PHP number_format()转换为javascript之后,这对我很有用
function number_format(number, decimals = 0, dec_point = ".",thousands_sep = ",") {
number = (number + '').replace(/[^0-9+\-Ee.]/g, '');
var n = !isFinite(+number) ? 0 : +number,
prec = !isFinite(+decimals) ? 0 : Math.abs(decimals),
s = '',
toFixedFix = function(n, prec)
{
var k = Math.pow(10, prec);
return '' + (Math.round(n * k) / k).toFixed(prec);
};
// Fix for IE parseFloat(0.55).toFixed(0) = 0;
s = (prec ? toFixedFix(n, prec) : '' +
Math.round(n)).split('.');
if (s[0].length > 3)
{
s[0] = s[0].replace(/\B(?=(?:\d{3})+(?!\d))/g,
thousands_sep);
}
if ((s[1] || '').length < prec)
{
s[1] = s[1] || '';
s[1] += new Array(prec - s[1].length + 1).join('0');
}
return s.join(dec_point);
}
其他回答
String.prototype.toPrice = function () {
var v;
if (/^\d+(,\d+)$/.test(this))
v = this.replace(/,/, '.');
else if (/^\d+((,\d{3})*(\.\d+)?)?$/.test(this))
v = this.replace(/,/g, "");
else if (/^\d+((.\d{3})*(,\d+)?)?$/.test(this))
v = this.replace(/\./g, "").replace(/,/, ".");
var x = parseFloat(v).toFixed(2).toString().split("."),
x1 = x[0],
x2 = ((x.length == 2) ? "." + x[1] : ".00"),
exp = /^([0-9]+)(\d{3})/;
while (exp.test(x1))
x1 = x1.replace(exp, "$1" + "," + "$2");
return x1 + x2;
}
alert("123123".toPrice()); //123,123.00
alert("123123,316".toPrice()); //123,123.32
alert("12,312,313.33213".toPrice()); //12,312,313.33
alert("123.312.321,32132".toPrice()); //123,312,321.32
我们也可以使用numeraljs
数字的格式可以像货币、百分比、时间,甚至是带有小数位数、千位和缩写的普通数字。您可以始终创建自定义格式。
var string = numeral(1000).format('0,0');
// '1,000'
Patrick Desjardins(前Daok)的例子对我很有用。如果有人感兴趣,我将其移植到CoffeeScript。
Number.prototype.toMoney = (decimals = 2, decimal_separator = ".", thousands_separator = ",") ->
n = this
c = if isNaN(decimals) then 2 else Math.abs decimals
sign = if n < 0 then "-" else ""
i = parseInt(n = Math.abs(n).toFixed(c)) + ''
j = if (j = i.length) > 3 then j % 3 else 0
x = if j then i.substr(0, j) + thousands_separator else ''
y = i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + thousands_separator)
z = if c then decimal_separator + Math.abs(n - i).toFixed(c).slice(2) else ''
sign + x + y + z
http://code.google.com/p/javascript-number-formatter/:
短、快、灵活但独立。只有75行,包括MIT许可证信息、空白行和注释。接受标准数字格式,如#、##0.00或带否定的-000.####。接受任何国家/地区格式,如###0,00,#,###.##,#‘###.##或任何类型的非编号符号。接受任意数字分组。#、##、#0.000或#、####0.##均有效。接受任何冗余/防傻瓜格式。##、###、##。#或0#、#00####0#都正常。自动数字舍入。简单的界面,只需提供如下掩码和值:格式(“0.0000”,3.141592)
UPDATE这是我自己开发的应用程序,用于最常见的任务:
var NumUtil = {};
/**
Petty print 'num' wth exactly 'signif' digits.
pp(123.45, 2) == "120"
pp(0.012343, 3) == "0.0123"
pp(1.2, 3) == "1.20"
*/
NumUtil.pp = function(num, signif) {
if (typeof(num) !== "number")
throw 'NumUtil.pp: num is not a number!';
if (isNaN(num))
throw 'NumUtil.pp: num is NaN!';
if (num < 1e-15 || num > 1e15)
return num;
var r = Math.log(num)/Math.LN10;
var dot = Math.floor(r) - (signif-1);
r = r - Math.floor(r) + (signif-1);
r = Math.round(Math.exp(r * Math.LN10)).toString();
if (dot >= 0) {
for (; dot > 0; dot -= 1)
r += "0";
return r;
} else if (-dot >= r.length) {
var p = "0.";
for (; -dot > r.length; dot += 1) {
p += "0";
}
return p+r;
} else {
return r.substring(0, r.length + dot) + "." + r.substring(r.length + dot);
}
}
/** Append leading zeros up to 2 digits. */
NumUtil.align2 = function(v) {
if (v < 10)
return "0"+v;
return ""+v;
}
/** Append leading zeros up to 3 digits. */
NumUtil.align3 = function(v) {
if (v < 10)
return "00"+v;
else if (v < 100)
return "0"+v;
return ""+v;
}
NumUtil.integer = {};
/** Round to integer and group by 3 digits. */
NumUtil.integer.pp = function(num) {
if (typeof(num) !== "number") {
console.log("%s", new Error().stack);
throw 'NumUtil.integer.pp: num is not a number!';
}
if (isNaN(num))
throw 'NumUtil.integer.pp: num is NaN!';
if (num > 1e15)
return num;
if (num < 0)
throw 'Negative num!';
num = Math.round(num);
var group = num % 1000;
var integ = Math.floor(num / 1000);
if (integ === 0) {
return group;
}
num = NumUtil.align3(group);
while (true) {
group = integ % 1000;
integ = Math.floor(integ / 1000);
if (integ === 0)
return group + " " + num;
num = NumUtil.align3(group) + " " + num;
}
return num;
}
NumUtil.currency = {};
/** Round to coins and group by 3 digits. */
NumUtil.currency.pp = function(amount) {
if (typeof(amount) !== "number")
throw 'NumUtil.currency.pp: amount is not a number!';
if (isNaN(amount))
throw 'NumUtil.currency.pp: amount is NaN!';
if (amount > 1e15)
return amount;
if (amount < 0)
throw 'Negative amount!';
if (amount < 1e-2)
return 0;
var v = Math.round(amount*100);
var integ = Math.floor(v / 100);
var frac = NumUtil.align2(v % 100);
var group = integ % 1000;
integ = Math.floor(integ / 1000);
if (integ === 0) {
return group + "." + frac;
}
amount = NumUtil.align3(group);
while (true) {
group = integ % 1000;
integ = Math.floor(integ / 1000);
if (integ === 0)
return group + " " + amount + "." + frac;
amount = NumUtil.align3(group) + " " + amount;
}
return amount;
}
一种仅满足原始要求的极简方法:
function formatMoney(n) {
return "$ " + (Math.round(n * 100) / 100).toLocaleString();
}
@丹尼尔·马格廖拉:你说得对。以上是一个仓促而不完整的实施。以下是正确的实施方式:
function formatMoney(n) {
return "$ " + n.toLocaleString().split(".")[0] + "."
+ n.toFixed(2).split(".")[1];
}