我想用JavaScript格式化价格。我想要一个函数,它将浮点作为参数,并返回如下格式的字符串:
"$ 2,500.00"
我该怎么做?
我想用JavaScript格式化价格。我想要一个函数,它将浮点作为参数,并返回如下格式的字符串:
"$ 2,500.00"
我该怎么做?
当前回答
这里是我见过的最好的JavaScript货币格式化程序:
Number.prototype.formatMoney = function(decPlaces, thouSeparator, decSeparator) {
var n = this,
decPlaces = isNaN(decPlaces = Math.abs(decPlaces)) ? 2 : decPlaces,
decSeparator = decSeparator == undefined ? "." : decSeparator,
thouSeparator = thouSeparator == undefined ? "," : thouSeparator,
sign = n < 0 ? "-" : "",
i = parseInt(n = Math.abs(+n || 0).toFixed(decPlaces)) + "",
j = (j = i.length) > 3 ? j % 3 : 0;
return sign + (j ? i.substr(0, j) + thouSeparator : "") + i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + thouSeparator) + (decPlaces ? decSeparator + Math.abs(n - i).toFixed(decPlaces).slice(2) : "");
};
它被重新格式化并从这里借用:如何将数字格式化为货币字符串
您必须提供您自己的货币代号(您使用了$以上)。
这样调用它(尽管注意,参数默认为2、逗号和句点,因此如果这是您的首选,则不需要提供任何参数):
var myMoney = 3543.75873;
var formattedMoney = '$' + myMoney.formatMoney(2, ',', '.'); // "$3,543.76"
其他回答
PHP函数“number_format”有一个JavaScript端口。
我发现它非常有用,因为它易于使用,并且对PHP开发人员来说是可识别的。
function number_format (number, decimals, dec_point, thousands_sep) {
var n = number, prec = decimals;
var toFixedFix = function (n,prec) {
var k = Math.pow(10,prec);
return (Math.round(n*k)/k).toString();
};
n = !isFinite(+n) ? 0 : +n;
prec = !isFinite(+prec) ? 0 : Math.abs(prec);
var sep = (typeof thousands_sep === 'undefined') ? ',' : thousands_sep;
var dec = (typeof dec_point === 'undefined') ? '.' : dec_point;
var s = (prec > 0) ? toFixedFix(n, prec) : toFixedFix(Math.round(n), prec);
// Fix for Internet Explorer parseFloat(0.55).toFixed(0) = 0;
var abs = toFixedFix(Math.abs(n), prec);
var _, i;
if (abs >= 1000) {
_ = abs.split(/\D/);
i = _[0].length % 3 || 3;
_[0] = s.slice(0,i + (n < 0)) +
_[0].slice(i).replace(/(\d{3})/g, sep+'$1');
s = _.join(dec);
} else {
s = s.replace('.', dec);
}
var decPos = s.indexOf(dec);
if (prec >= 1 && decPos !== -1 && (s.length-decPos-1) < prec) {
s += new Array(prec-(s.length-decPos-1)).join(0)+'0';
}
else if (prec >= 1 && decPos === -1) {
s += dec+new Array(prec).join(0)+'0';
}
return s;
}
(原文注释栏,包括以下示例和到期信用)
// Formats a number with grouped thousands
//
// version: 906.1806
// discuss at: http://phpjs.org/functions/number_format
// + original by: Jonas Raoni Soares Silva (http://www.jsfromhell.com)
// + improved by: Kevin van Zonneveld (http://kevin.vanzonneveld.net)
// + bugfix by: Michael White (http://getsprink.com)
// + bugfix by: Benjamin Lupton
// + bugfix by: Allan Jensen (http://www.winternet.no)
// + revised by: Jonas Raoni Soares Silva (http://www.jsfromhell.com)
// + bugfix by: Howard Yeend
// + revised by: Luke Smith (http://lucassmith.name)
// + bugfix by: Diogo Resende
// + bugfix by: Rival
// + input by: Kheang Hok Chin (http://www.distantia.ca/)
// + improved by: davook
// + improved by: Brett Zamir (http://brett-zamir.me)
// + input by: Jay Klehr
// + improved by: Brett Zamir (http://brett-zamir.me)
// + input by: Amir Habibi (http://www.residence-mixte.com/)
// + bugfix by: Brett Zamir (http://brett-zamir.me)
// * example 1: number_format(1234.56);
// * returns 1: '1,235'
// * example 2: number_format(1234.56, 2, ',', ' ');
// * returns 2: '1 234,56'
// * example 3: number_format(1234.5678, 2, '.', '');
// * returns 3: '1234.57'
// * example 4: number_format(67, 2, ',', '.');
// * returns 4: '67,00'
// * example 5: number_format(1000);
// * returns 5: '1,000'
// * example 6: number_format(67.311, 2);
// * returns 6: '67.31'
// * example 7: number_format(1000.55, 1);
// * returns 7: '1,000.6'
// * example 8: number_format(67000, 5, ',', '.');
// * returns 8: '67.000,00000'
// * example 9: number_format(0.9, 0);
// * returns 9: '1'
// * example 10: number_format('1.20', 2);
// * returns 10: '1.20'
// * example 11: number_format('1.20', 4);
// * returns 11: '1.2000'
// * example 12: number_format('1.2000', 3);
// * returns 12: '1.200'
我选择了一些最好的答案,组合并制作了一个通过ESLint的ECMAScript 2015(ES6)函数。
export const formatMoney = (
amount,
decimalCount = 2,
decimal = '.',
thousands = ',',
currencySymbol = '$',
) => {
if (typeof Intl === 'object') {
return new Intl.NumberFormat('en-AU', {
style: 'currency',
currency: 'AUD',
}).format(amount);
}
// Fallback if Intl is not present.
try {
const negativeSign = amount < 0 ? '-' : '';
const amountNumber = Math.abs(Number(amount) || 0).toFixed(decimalCount);
const i = parseInt(amountNumber, 10).toString();
const j = i.length > 3 ? i.length % 3 : 0;
return (
currencySymbol +
negativeSign +
(j ? i.substr(0, j) + thousands : '') +
i.substr(j).replace(/(\d{3})(?=\d)/g, `$1${thousands}`) +
(decimalCount
? decimal +
Math.abs(amountNumber - i)
.toFixed(decimalCount)
.slice(2)
: '')
);
} catch (e) {
// eslint-disable-next-line no-console
console.error(e);
}
return amount;
};
好的,根据你说的,我用这个:
var DecimalSeparator = Number("1.2").toLocaleString().substr(1,1);
var AmountWithCommas = Amount.toLocaleString();
var arParts = String(AmountWithCommas).split(DecimalSeparator);
var intPart = arParts[0];
var decPart = (arParts.length > 1 ? arParts[1] : '');
decPart = (decPart + '00').substr(0,2);
return '£ ' + intPart + DecimalSeparator + decPart;
我对改进建议持开放态度(我不希望仅仅为了做到这一点而加入YUI:-)
我已经知道我应该检测“.”而不是仅仅将其用作小数分隔符。。。
Patrick热门答案的CoffeeScript:
Number::formatMoney = (decimalPlaces, decimalChar, thousandsChar) ->
n = this
c = decimalPlaces
d = decimalChar
t = thousandsChar
c = (if isNaN(c = Math.abs(c)) then 2 else c)
d = (if d is undefined then "." else d)
t = (if t is undefined then "," else t)
s = (if n < 0 then "-" else "")
i = parseInt(n = Math.abs(+n or 0).toFixed(c)) + ""
j = (if (j = i.length) > 3 then j % 3 else 0)
s + (if j then i.substr(0, j) + t else "") + i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + t) + (if c then d + Math.abs(n - i).toFixed(c).slice(2) else "")
使用regexp的更快方法:
Number.prototype.toMonetaryString = function() {
var n = this.toFixed(2), m;
//var = this.toFixed(2).replace(/\./, ','); For comma separator
// with a space for thousands separator
while ((m = n.replace(/(\d)(\d\d\d)\b/g, '$1 $2')) != n)
n = m;
return m;
}
String.prototype.fromMonetaryToNumber = function(s) {
return this.replace(/[^\d-]+/g, '')/100;
}