我想你想要：

f.nettotal.value = "$" + showValue.toFixed(2);

function CurrencyFormatted(amount)
{
    var i = parseFloat(amount);
    if(isNaN(i)) { i = 0.00; }
    var minus = '';
    if(i < 0) { minus = '-'; }
    i = Math.abs(i);
    i = parseInt((i + .005) * 100);
    i = i / 100;
    s = new String(i);
    if(s.indexOf('.') < 0) { s += '.00'; }
    if(s.indexOf('.') == (s.length - 2)) { s += '0'; }
    s = minus + s;
    return s;
}

来自WillMaster。

通常，有多种方法可以执行相同的操作，但我会避免使用Number.prototype.toLocaleString，因为它可以根据用户设置返回不同的值。

我也不建议扩展Number.prototype-扩展原生对象原型是一种糟糕的做法，因为它可能会与其他人的代码（例如库/框架/插件）发生冲突，并且可能与未来的JavaScript实现/版本不兼容。

我认为正则表达式是解决这个问题的最佳方法，下面是我的实现：

/**
 * Converts number into currency format
 * @param {number} number    Number that should be converted.
 * @param {string} [decimalSeparator]    Decimal separator, defaults to '.'.
 * @param {string} [thousandsSeparator]    Thousands separator, defaults to ','.
 * @param {int} [nDecimalDigits]    Number of decimal digits, defaults to `2`.
 * @return {string} Formatted string (e.g. numberToCurrency(12345.67) returns '12,345.67')
 */
function numberToCurrency(number, decimalSeparator, thousandsSeparator, nDecimalDigits){
    //default values
    decimalSeparator = decimalSeparator || '.';
    thousandsSeparator = thousandsSeparator || ',';
    nDecimalDigits = nDecimalDigits == null? 2 : nDecimalDigits;

    var fixed = number.toFixed(nDecimalDigits), //limit/add decimal digits
        parts = new RegExp('^(-?\\d{1,3})((?:\\d{3})+)(\\.(\\d{'+ nDecimalDigits +'}))?$').exec( fixed ); //separate begin [$1], middle [$2] and decimal digits [$4]

    if(parts){ //number >= 1000 || number <= -1000
        return parts[1] + parts[2].replace(/\d{3}/g, thousandsSeparator + '$&') + (parts[4] ? decimalSeparator + parts[4] : '');
    }else{
        return fixed.replace('.', decimalSeparator);
    }
}

这里是XMLilley提供的代码的mootools1.2实现。。。

Number.implement('format', function(decPlaces, thouSeparator, decSeparator){
decPlaces = isNaN(decPlaces = Math.abs(decPlaces)) ? 2 : decPlaces;
decSeparator = decSeparator === undefined ? '.' : decSeparator;
thouSeparator = thouSeparator === undefined ? ',' : thouSeparator;

var num = this,
    sign = num < 0 ? '-' : '',
    i = parseInt(num = Math.abs(+num || 0).toFixed(decPlaces)) + '',
    j = (j = i.length) > 3 ? j % 3 : 0;

return sign + (j ? i.substr(0, j) + thouSeparator : '') + i.substr(j).replace(/(\d{3})(?=\d)/g, '$1' + thouSeparator) + (decPlaces ? decSeparator + Math.abs(num - i).toFixed(decPlaces).slice(2) : '');
});

我选择了一些最好的答案，组合并制作了一个通过ESLint的ECMAScript 2015（ES6）函数。

export const formatMoney = (
  amount,
  decimalCount = 2,
  decimal = '.',
  thousands = ',',
  currencySymbol = '$',
) => {
  if (typeof Intl === 'object') {
    return new Intl.NumberFormat('en-AU', {
      style: 'currency',
      currency: 'AUD',
    }).format(amount);
  }
  // Fallback if Intl is not present.
  try {
    const negativeSign = amount < 0 ? '-' : '';
    const amountNumber = Math.abs(Number(amount) || 0).toFixed(decimalCount);
    const i = parseInt(amountNumber, 10).toString();
    const j = i.length > 3 ? i.length % 3 : 0;
    return (
      currencySymbol +
      negativeSign +
      (j ? i.substr(0, j) + thousands : '') +
      i.substr(j).replace(/(\d{3})(?=\d)/g, `$1${thousands}`) +
      (decimalCount
        ? decimal +
          Math.abs(amountNumber - i)
            .toFixed(decimalCount)
            .slice(2)
        : '')
    );
  } catch (e) {
    // eslint-disable-next-line no-console
    console.error(e);
  }
  return amount;
};

Intl.NumberFormat（国际数字格式）

var number = 3500;
alert(new Intl.NumberFormat().format(number));
// → "3,500" if in US English locale

或者JavaScript中的PHP的number_format。