我想用JavaScript格式化价格。我想要一个函数,它将浮点作为参数,并返回如下格式的字符串:

"$ 2,500.00"

我该怎么做?


当前回答

Patrick Desjardins(前Daok)的例子对我很有用。如果有人感兴趣,我将其移植到CoffeeScript。

Number.prototype.toMoney = (decimals = 2, decimal_separator = ".", thousands_separator = ",") ->
    n = this
    c = if isNaN(decimals) then 2 else Math.abs decimals
    sign = if n < 0 then "-" else ""
    i = parseInt(n = Math.abs(n).toFixed(c)) + ''
    j = if (j = i.length) > 3 then j % 3 else 0
    x = if j then i.substr(0, j) + thousands_separator else ''
    y = i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + thousands_separator)
    z = if c then decimal_separator + Math.abs(n - i).toFixed(c).slice(2) else ''
    sign + x + y + z

其他回答

我选择了一些最好的答案,组合并制作了一个通过ESLint的ECMAScript 2015(ES6)函数。

export const formatMoney = (
  amount,
  decimalCount = 2,
  decimal = '.',
  thousands = ',',
  currencySymbol = '$',
) => {
  if (typeof Intl === 'object') {
    return new Intl.NumberFormat('en-AU', {
      style: 'currency',
      currency: 'AUD',
    }).format(amount);
  }
  // Fallback if Intl is not present.
  try {
    const negativeSign = amount < 0 ? '-' : '';
    const amountNumber = Math.abs(Number(amount) || 0).toFixed(decimalCount);
    const i = parseInt(amountNumber, 10).toString();
    const j = i.length > 3 ? i.length % 3 : 0;
    return (
      currencySymbol +
      negativeSign +
      (j ? i.substr(0, j) + thousands : '') +
      i.substr(j).replace(/(\d{3})(?=\d)/g, `$1${thousands}`) +
      (decimalCount
        ? decimal +
          Math.abs(amountNumber - i)
            .toFixed(decimalCount)
            .slice(2)
        : '')
    );
  } catch (e) {
    // eslint-disable-next-line no-console
    console.error(e);
  }
  return amount;
};

看看JavaScriptNumber对象,看看它是否可以帮助您。

toLocaleString()将使用位置特定的千位分隔符格式化数字。toFixed()将数字舍入到特定的小数位数。

要同时使用这些值,必须将其类型改回数字,因为它们都输出字符串。

例子:

Number((someNumber).toFixed(1)).toLocaleString()

EDIT

您可以直接使用toLocaleString,而不必重新转换为数字:

someNumber.toLocaleString(undefined, {minimumFractionDigits: 2, maximumFractionDigits: 2});

多个数字

如果需要经常以类似的方式格式化数字,可以创建一个特定的对象以供重用。德语(瑞士):

const money = new Intl.NumberFormat('de-CH',
  { style:'currency', currency: 'CHF' });
const percent = new Intl.NumberFormat('de-CH',
  { style:'percent', maximumFractionDigits: 1, signDisplay: "always"});

其可以用作:

money.format(1234.50); // output CHF 1'234.50
percent.format(0.083);  // output +8.3%

非常漂亮。

http://code.google.com/p/javascript-number-formatter/:

短、快、灵活但独立。只有75行,包括MIT许可证信息、空白行和注释。接受标准数字格式,如#、##0.00或带否定的-000.####。接受任何国家/地区格式,如###0,00,#,###.##,#‘###.##或任何类型的非编号符号。接受任意数字分组。#、##、#0.000或#、####0.##均有效。接受任何冗余/防傻瓜格式。##、###、##。#或0#、#00####0#都正常。自动数字舍入。简单的界面,只需提供如下掩码和值:格式(“0.0000”,3.141592)

UPDATE这是我自己开发的应用程序,用于最常见的任务:

var NumUtil = {};

/**
  Petty print 'num' wth exactly 'signif' digits.
  pp(123.45, 2) == "120"
  pp(0.012343, 3) == "0.0123"
  pp(1.2, 3) == "1.20"
*/
NumUtil.pp = function(num, signif) {
    if (typeof(num) !== "number")
        throw 'NumUtil.pp: num is not a number!';
    if (isNaN(num))
        throw 'NumUtil.pp: num is NaN!';
    if (num < 1e-15 || num > 1e15)
        return num;
    var r = Math.log(num)/Math.LN10;
    var dot = Math.floor(r) - (signif-1);
    r = r - Math.floor(r) + (signif-1);
    r = Math.round(Math.exp(r * Math.LN10)).toString();
    if (dot >= 0) {
        for (; dot > 0; dot -= 1)
            r += "0";
        return r;
    } else if (-dot >= r.length) {
        var p = "0.";
        for (; -dot > r.length; dot += 1) {
            p += "0";
        }
        return p+r;
    } else {
        return r.substring(0, r.length + dot) + "." + r.substring(r.length + dot);
    }
}

/** Append leading zeros up to 2 digits. */
NumUtil.align2 = function(v) {
    if (v < 10)
        return "0"+v;
    return ""+v;
}
/** Append leading zeros up to 3 digits. */
NumUtil.align3 = function(v) {
    if (v < 10)
        return "00"+v;
    else if (v < 100)
        return "0"+v;
    return ""+v;
}

NumUtil.integer = {};

/** Round to integer and group by 3 digits. */
NumUtil.integer.pp = function(num) {
    if (typeof(num) !== "number") {
        console.log("%s", new Error().stack);
        throw 'NumUtil.integer.pp: num is not a number!';
    }
    if (isNaN(num))
        throw 'NumUtil.integer.pp: num is NaN!';
    if (num > 1e15)
        return num;
    if (num < 0)
        throw 'Negative num!';
    num = Math.round(num);
    var group = num % 1000;
    var integ = Math.floor(num / 1000);
    if (integ === 0) {
        return group;
    }
    num = NumUtil.align3(group);
    while (true) {
        group = integ % 1000;
        integ = Math.floor(integ / 1000);
        if (integ === 0)
            return group + " " + num;
        num = NumUtil.align3(group) + " " + num;
    }
    return num;
}

NumUtil.currency = {};

/** Round to coins and group by 3 digits. */
NumUtil.currency.pp = function(amount) {
    if (typeof(amount) !== "number")
        throw 'NumUtil.currency.pp: amount is not a number!';
    if (isNaN(amount))
        throw 'NumUtil.currency.pp: amount is NaN!';
    if (amount > 1e15)
        return amount;
    if (amount < 0)
        throw 'Negative amount!';
    if (amount < 1e-2)
        return 0;
    var v = Math.round(amount*100);
    var integ = Math.floor(v / 100);
    var frac = NumUtil.align2(v % 100);
    var group = integ % 1000;
    integ = Math.floor(integ / 1000);
    if (integ === 0) {
        return group + "." + frac;
    }
    amount = NumUtil.align3(group);
    while (true) {
        group = integ % 1000;
        integ = Math.floor(integ / 1000);
        if (integ === 0)
            return group + " " + amount + "." + frac;
        amount = NumUtil.align3(group) + " " + amount;
    }
    return amount;
}

JavaScript中没有“formatNumber”的等价物。你可以自己写,也可以找一个已经这样做的库。

function CurrencyFormatted(amount)
{
    var i = parseFloat(amount);
    if(isNaN(i)) { i = 0.00; }
    var minus = '';
    if(i < 0) { minus = '-'; }
    i = Math.abs(i);
    i = parseInt((i + .005) * 100);
    i = i / 100;
    s = new String(i);
    if(s.indexOf('.') < 0) { s += '.00'; }
    if(s.indexOf('.') == (s.length - 2)) { s += '0'; }
    s = minus + s;
    return s;
}

来自WillMaster。