在Link react-router中传递道具

我正在使用react和react-router。我试图在反应路由器的“链接”中传递属性

var React  = require('react');
var Router = require('react-router');
var CreateIdeaView = require('./components/createIdeaView.jsx');

var Link = Router.Link;
var Route = Router.Route;
var DefaultRoute = Router.DefaultRoute;
var RouteHandler = Router.RouteHandler;
var App = React.createClass({
  render : function(){
    return(
      <div>
        <Link to="ideas" params={{ testvalue: "hello" }}>Create Idea</Link>
        <RouteHandler/>
      </div>
    );
  }
});

var routes = (
  <Route name="app" path="/" handler={App}>
    <Route name="ideas" handler={CreateIdeaView} />
    <DefaultRoute handler={Home} />
  </Route>
);

Router.run(routes, function(Handler) {

  React.render(<Handler />, document.getElementById('main'))
});

“Link”呈现页面，但不将属性传递给新视图。下面是视图代码

var React = require('react');
var Router = require('react-router');

var CreateIdeaView = React.createClass({
  render : function(){
    console.log('props form link',this.props,this)//props not recived
  return(
      <div>
        <h1>Create Post: </h1>
        <input type='text' ref='newIdeaTitle' placeholder='title'></input>
        <input type='text' ref='newIdeaBody' placeholder='body'></input>
      </div>
    );
  }
});

module.exports = CreateIdeaView;

如何使用“链接”传递数据?

当前回答

参考这篇文章

简单来说就是:

<Link to={{
     pathname: `your/location`,
     state: {send anything from here}
}}

现在你想要访问它:

this.props.location.state

2019-10-07 11:28:00

其他回答

至于react-router-dom 4.x。X (https://www.npmjs.com/package/react-router-dom)你可以传递参数给组件路由到via:

<Route path="/ideas/:value" component ={CreateIdeaView} />

通过(考虑testValue道具被传递给相应的组件(例如上面的App组件)来呈现链接)

<Link to={`/ideas/${ this.props.testValue }`}>Create Idea</Link>

将道具传递给组件构造函数，值参数将通过

props.match.params.value

2017-04-26 15:30:53

更新25-11-21 感谢alexadestech。Mx在上面写道。我能够转移整个对象，并从中抽出所有必要的字段在send-component中:

<Button type="submit" component={NavLink} to={{
        pathname: '/basequestion',
        state: {question} }}
        variant="contained"
        size="small">Take test</Button>

在receive-component:

import { useLocation } from "react-router"
const BaseQuestion = () => {
const location = useLocation();
const {description, title, images} = (location.state.question);

2021-11-25 14:25:32

我在显示应用程序中的用户详细信息时遇到了同样的问题。

你可以这样做:

<Link to={'/ideas/'+this.props.testvalue }>Create Idea</Link>

<Link to="ideas/hello">Create Idea</Link>

and

<Route name="ideas/:value" handler={CreateIdeaView} />

在CreateIdeaView类中通过this.props.match.params.value来获取。

你可以看看这个对我帮助很大的视频:https://www.youtube.com/watch?v=ZBxMljq9GSE

2016-06-22 18:19:25

在react-router v6中，它是state和useLocation:

<Link to={`/foo`} state={{title: 'foo'}}>

import {useLocation} from "react-router-dom";

const FooPage = () => {
    const location = useLocation()

    return <>
        <h1>{location.state.title}</h1>
    </>
}
export default FooPage;

2023-01-20 11:15:42

在Link组件中执行状态

<Link to='register' state={{name:'zayne'}}>

现在要访问页面中的项目，导入useLocation

import {useLocation} from 'react-router-dom';

const Register=()=>{

const location = useLocation()

//store the state in a variable if you want 
//location.state then the property or object you want

const Name = location.state.name

return(
  <div>
    hello my name is {Name}
  </div>
)

}

2022-02-10 12:20:05

在Link react-router中传递道具

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