如何使用NSAttributedString?

在NSString或nsmutablestring中不可能有多种颜色。我听说过一点NSAttributedString，它是在iPad SDK 3.2(或大约3.2)中引入的，并且在iPhone SDK 4.0 beta版中可用。

我想要一根有三种颜色的绳子。

我不使用3个独立的NSString的原因，是因为三个NSAttributedString子字符串的长度经常改变，所以我宁愿，不使用任何计算重新定位3个独立的NSString对象。

如果使用NSAttributedString是可能的，我怎么做以下-(如果不可能使用NSAttributedString，你会怎么做):

编辑: 记住，@"first"， @"second"和@"third"随时会被其他字符串替换。所以使用硬编码的NSRange值是行不通的。

当前回答

我认为，使用正则表达式来查找应用属性的范围是一种非常方便的方法。我是这样做的:

NSMutableAttributedString *goodText = [[NSMutableAttributedString alloc] initWithString:articleText];

NSRange range = [articleText rangeOfString:@"\\[.+?\\]" options:NSRegularExpressionSearch|NSCaseInsensitiveSearch];
if (range.location != NSNotFound) {
    [goodText addAttribute:NSFontAttributeName value:[UIFont fontWithName:@"Georgia" size:16] range:range];
    [goodText addAttribute:NSForegroundColorAttributeName value:[UIColor brownColor] range:range];
}

NSString *regEx = [NSString stringWithFormat:@"%@.+?\\s", [self.article.titleText substringToIndex:0]];
range = [articleText rangeOfString:regEx options:NSRegularExpressionSearch|NSCaseInsensitiveSearch];
if (range.location != NSNotFound) {
    [goodText addAttribute:NSFontAttributeName value:[UIFont fontWithName:@"Georgia-Bold" size:20] range:range];
    [goodText addAttribute:NSForegroundColorAttributeName value:[UIColor blueColor] range:range];
}

[self.textView setAttributedText:goodText];

我正在搜索可用属性的列表，但在这里和类引用的第一页中都没有找到它们。所以我决定在这里发布相关信息。

标准属性

带属性字符串支持以下文本的标准属性。如果键不在字典中，则使用下面描述的默认值。

NSString *NSFontAttributeName;
NSString *NSParagraphStyleAttributeName;
NSString *NSForegroundColorAttributeName;
NSString *NSUnderlineStyleAttributeName;
NSString *NSSuperscriptAttributeName;
NSString *NSBackgroundColorAttributeName;
NSString *NSAttachmentAttributeName;
NSString *NSLigatureAttributeName;
NSString *NSBaselineOffsetAttributeName;
NSString *NSKernAttributeName;
NSString *NSLinkAttributeName;
NSString *NSStrokeWidthAttributeName;
NSString *NSStrokeColorAttributeName;
NSString *NSUnderlineColorAttributeName;
NSString *NSStrikethroughStyleAttributeName;
NSString *NSStrikethroughColorAttributeName;
NSString *NSShadowAttributeName;
NSString *NSObliquenessAttributeName;
NSString *NSExpansionAttributeName;
NSString *NSCursorAttributeName;
NSString *NSToolTipAttributeName;
NSString *NSMarkedClauseSegmentAttributeName;
NSString *NSWritingDirectionAttributeName;
NSString *NSVerticalGlyphFormAttributeName;
NSString *NSTextAlternativesAttributeName;

NSAttributedString编程指南

完整的类参考在这里。

2013-08-16 06:29:38

其他回答

- (void)changeColorWithString:(UILabel *)uilabel stringToReplace:(NSString *) stringToReplace uiColor:(UIColor *) uiColor{
    NSMutableAttributedString *text =
    [[NSMutableAttributedString alloc]
     initWithAttributedString: uilabel.attributedText];

    [text addAttribute: NSForegroundColorAttributeName value:uiColor range:[uilabel.text rangeOfString:stringToReplace]];

    [uilabel setAttributedText: text];

}

2016-01-07 06:57:50

为了解决这类问题，我在swift中创建了一个名为Atributika的库。

let str = "<r>first</r><g>second</g><b>third</b>".style(tags:
        Style("r").foregroundColor(.red),
        Style("g").foregroundColor(.green),
        Style("b").foregroundColor(.blue)).attributedString

label.attributedText = str

你可以在这里找到它https://github.com/psharanda/Atributika

2017-02-22 11:03:21

斯威夫特4

let combination = NSMutableAttributedString()

var part1 = NSMutableAttributedString()
var part2 = NSMutableAttributedString()
var part3 = NSMutableAttributedString()

let attrRegular = [NSAttributedStringKey.font : UIFont(name: "Palatino-Roman", size: 15)]

let attrBold:Dictionary = [NSAttributedStringKey.font : UIFont(name: "Raleway-SemiBold", size: 15)]

let attrBoldWithColor: Dictionary = [NSAttributedStringKey.font : UIFont(name: "Raleway-SemiBold", size: 15),
                                 NSAttributedStringKey.foregroundColor: UIColor.red]

if let regular = attrRegular as? [NSAttributedStringKey : NSObject]{
    part1 = NSMutableAttributedString(string: "first", attributes: regular)

}
if let bold = attrRegular as? [NSAttributedStringKey : NSObject]{
    part2 = NSMutableAttributedString(string: "second", attributes: bold)
}

if let boldWithColor = attrBoldWithColor as? [NSAttributedStringKey : NSObject]{
    part3 = NSMutableAttributedString(string: "third", attributes: boldWithColor)
}

combination.append(part1)
combination.append(part2)
combination.append(part3)

属性列表请参见这里的NSAttributedStringKey在苹果文档

2018-02-09 17:30:51

在构建带属性字符串时，我更喜欢使用可变子类，只是为了让事情更简洁。

话虽如此，下面是如何创建一个三色带属性字符串:

NSMutableAttributedString *string = [[NSMutableAttributedString alloc] initWithString:@"firstsecondthird"];
[string addAttribute:NSForegroundColorAttributeName value:[UIColor redColor] range:NSMakeRange(0,5)];
[string addAttribute:NSForegroundColorAttributeName value:[UIColor greenColor] range:NSMakeRange(5,6)];
[string addAttribute:NSForegroundColorAttributeName value:[UIColor blueColor] range:NSMakeRange(11,5)];

在浏览器中输入。警告实现者

显然你不会像这样硬编码。也许你可以这样做:

NSDictionary *wordToColorMapping = ....;  //an NSDictionary of NSString => UIColor pairs
NSMutableAttributedString *string = [[NSMutableAttributedString alloc] initWithString:@""];
for (NSString *word in wordToColorMapping) {
  UIColor *color = [wordToColorMapping objectForKey:word];
  NSDictionary *attributes = [NSDictionary dictionaryWithObject:color forKey:NSForegroundColorAttributeName];
  NSAttributedString *subString = [[NSAttributedString alloc] initWithString:word attributes:attributes];
  [string appendAttributedString:subString];
  [subString release];
}

//display string

2010-08-14 07:05:23