这是我的一句话:

cat /proc/*/status | grep -E 'VmSwap:|Name:' | grep VmSwap -B1 | cut -d':' -f2 | grep -v '\-\-' | grep -o -E '[a-zA-Z0-9]+.*$' | cut -d' ' -f1 | xargs -n2 echo | sort -k2 -n

这一行的步骤是:

Get all the data in /proc/process/status for all processes Select the fields VmSwap and Name for each Remove the processes that don't have the VmSwap field Remove the names of the fields (VmSwap: and Name:) Remove lines with -- that were added by the previous step Remove the spaces at the start of the lines Remove the second part of each process name and " kB" after the swap usage number Take name and number (process name and swap usage) and put them in one line, one after the other Sort the lines by the swap usage

我不知道如何确切地找到哪个进程正在使用交换空间的直接答案，但是，这个链接可能会有帮助。另一个好例子在这里

另外，使用像htop这样的好工具来查看哪些进程使用了大量内存，以及总体上使用了多少交换空间。

我找到的最好的脚本在这个页面上:http://northernmost.org/blog/find-out-what-is-using-your-swap/

这里是脚本的一个变体，不需要根:

#!/bin/bash 
# Get current swap usage for all running processes
# Erik Ljungstrom 27/05/2011
# Modified by Mikko Rantalainen 2012-08-09
# Pipe the output to "sort -nk3" to get sorted output
# Modified by Marc Methot 2014-09-18
# removed the need for sudo

SUM=0
OVERALL=0
for DIR in `find /proc/ -maxdepth 1 -type d -regex "^/proc/[0-9]+"`
do
    PID=`echo $DIR | cut -d / -f 3`
    PROGNAME=`ps -p $PID -o comm --no-headers`
    for SWAP in `grep VmSwap $DIR/status 2>/dev/null | awk '{ print $2 }'`
    do
        let SUM=$SUM+$SWAP
    done
    if (( $SUM > 0 )); then
        echo "PID=$PID swapped $SUM KB ($PROGNAME)"
    fi
    let OVERALL=$OVERALL+$SUM
    SUM=0
done
echo "Overall swap used: $OVERALL KB"

运行top，然后按OpEnter。现在进程应该根据它们的交换使用情况进行排序。

这是一个更新，因为我原来的答案没有提供一个确切的答案，在评论中指出的问题。从htop常见问题:

It is not possible to get the exact size of used swap space of a process. Top fakes this information by making SWAP = VIRT - RES, but that is not a good metric, because other stuff such as video memory counts on VIRT as well (for example: top says my X process is using 81M of swap, but it also reports my system as a whole is using only 2M of swap. Therefore, I will not add a similar Swap column to htop because I don't know a reliable way to get this information (actually, I don't think it's possible to get an exact number, because of shared pages).

这是我的一句话:

cat /proc/*/status | grep -E 'VmSwap:|Name:' | grep VmSwap -B1 | cut -d':' -f2 | grep -v '\-\-' | grep -o -E '[a-zA-Z0-9]+.*$' | cut -d' ' -f1 | xargs -n2 echo | sort -k2 -n

这一行的步骤是:

Get all the data in /proc/process/status for all processes Select the fields VmSwap and Name for each Remove the processes that don't have the VmSwap field Remove the names of the fields (VmSwap: and Name:) Remove lines with -- that were added by the previous step Remove the spaces at the start of the lines Remove the second part of each process name and " kB" after the swap usage number Take name and number (process name and swap usage) and put them in one line, one after the other Sort the lines by the swap usage

我在网上改编了一个不同的脚本来写这句长单句:

 { date;for f in /proc/[0-9]*/status; do 
   awk '{k[$1]=$2} END { if (k["VmSwap:"]) print k["Pid:"],k["Name:"],k["VmSwap:"];}' $f 2>/dev/null; 
   done | sort -n ; }

然后我将其扔进cronjob并将输出重定向到日志文件。这里的信息与在smaps文件中积累Swap:条目相同，但如果你想确定，你可以使用:

{ date;for m in /proc/*/smaps;do 
  awk '/^Swap/ {s+=$2} END { if (s) print FILENAME,s }' $m 2>/dev/null;
  done | tr -dc ' [0-9]\n' |sort -k 1n; }

这个版本的输出有两列:pid，交换量。在上面的版本中，tr删除非数值组件。在这两种情况下，输出都是按照pid数值排序的。