所以我遵循这个教程,但它似乎没有做任何事情。只是没有。它等待几秒钟并关闭程序。这段代码有什么问题?

import cv2
vidcap = cv2.VideoCapture('Compton.mp4')
success,image = vidcap.read()
count = 0
success = True
while success:
  success,image = vidcap.read()
  cv2.imwrite("frame%d.jpg" % count, image)     # save frame as JPEG file
  if cv2.waitKey(10) == 27:                     # exit if Escape is hit
      break
  count += 1

此外,在评论中它说这限制帧到1000?为什么?

编辑: 我试着先做success = True,但没有帮助。它只创建了一个0字节的图像。


当前回答

这个函数以1帧/秒的速度从视频中提取图像,此外,它还识别最后一帧并停止读取:

import cv2
import numpy as np

def extract_image_one_fps(video_source_path):

    vidcap = cv2.VideoCapture(video_source_path)
    count = 0
    success = True
    while success:
      vidcap.set(cv2.CAP_PROP_POS_MSEC,(count*1000))      
      success,image = vidcap.read()

      ## Stop when last frame is identified
      image_last = cv2.imread("frame{}.png".format(count-1))
      if np.array_equal(image,image_last):
          break

      cv2.imwrite("frame%d.png" % count, image)     # save frame as PNG file
      print '{}.sec reading a new frame: {} '.format(count,success)
      count += 1

其他回答

从这里下载这个视频,这样我们就有了相同的测试视频文件。确保mp4文件与python代码位于同一目录。然后确保从相同的目录运行python解释器。

然后修改代码,抛弃浪费时间的waitKey,也没有窗口,它不能捕捉键盘事件。同时,我们打印success值以确保它成功读取帧。

import cv2
vidcap = cv2.VideoCapture('big_buck_bunny_720p_5mb.mp4')
success,image = vidcap.read()
count = 0
while success:
  cv2.imwrite("frame%d.jpg" % count, image)     # save frame as JPEG file      
  success,image = vidcap.read()
  print('Read a new frame: ', success)
  count += 1

这是怎么回事?

在对如何将帧转换为视频进行了大量研究后,我创建了这个函数,希望这能有所帮助。我们需要opencv来实现:

import cv2
import numpy as np
import os

def frames_to_video(inputpath,outputpath,fps):
   image_array = []
   files = [f for f in os.listdir(inputpath) if isfile(join(inputpath, f))]
   files.sort(key = lambda x: int(x[5:-4]))
   for i in range(len(files)):
       img = cv2.imread(inputpath + files[i])
       size =  (img.shape[1],img.shape[0])
       img = cv2.resize(img,size)
       image_array.append(img)
   fourcc = cv2.VideoWriter_fourcc('D', 'I', 'V', 'X')
   out = cv2.VideoWriter(outputpath,fourcc, fps, size)
   for i in range(len(image_array)):
       out.write(image_array[i])
   out.release()


inputpath = 'folder path'
outpath =  'video file path/video.mp4'
fps = 29
frames_to_video(inputpath,outpath,fps)

修改fps(帧/秒)的值,输入文件夹路径和输出文件夹路径根据您自己的本地位置

下面的脚本将提取帧每半秒的所有视频在文件夹。(适用于python 3.7)

import cv2
import os
listing = os.listdir(r'D:/Images/AllVideos')
count=1
for vid in listing:
    vid = r"D:/Images/AllVideos/"+vid
    vidcap = cv2.VideoCapture(vid)
    def getFrame(sec):
        vidcap.set(cv2.CAP_PROP_POS_MSEC,sec*1000)
        hasFrames,image = vidcap.read()
        if hasFrames:
            cv2.imwrite("D:/Images/Frames/image"+str(count)+".jpg", image) # Save frame as JPG file
        return hasFrames
    sec = 0
    frameRate = 0.5 # Change this number to 1 for each 1 second
    
    success = getFrame(sec)
    while success:
        count = count + 1
        sec = sec + frameRate
        sec = round(sec, 2)
        success = getFrame(sec)

之前的答案已经失去了第一帧。把图片存储在文件夹里会很好。

# create a folder to store extracted images
import os
folder = 'test'  
os.mkdir(folder)
# use opencv to do the job
import cv2
print(cv2.__version__)  # my version is 3.1.0
vidcap = cv2.VideoCapture('test_video.mp4')
count = 0
while True:
    success,image = vidcap.read()
    if not success:
        break
    cv2.imwrite(os.path.join(folder,"frame{:d}.jpg".format(count)), image)     # save frame as JPEG file
    count += 1
print("{} images are extacted in {}.".format(count,folder))

顺便说一下,你可以通过VLC检查帧率。进入“windows ->媒体信息->编解码器详细信息”

我通过Anaconda的Spyder软件使用Python。使用@ gshock在这个线程的问题中列出的原始代码,代码不起作用(python不会读取mp4文件)。所以我下载了OpenCV 3.2,从bin文件夹中拷贝了“opencv_ffmpeg320.dll”和“opencv_ffmpeg320_64.dll”。我将这两个dll文件粘贴到Anaconda的“dll”文件夹。

蟒蛇也有一个“pckgs”文件夹…我复制并粘贴了整个“OpenCV 3.2”文件夹,我下载到Anaconda“pckgs”文件夹。

最后,Anaconda有一个“Library”文件夹,其中有一个“bin”子文件夹。我将“opencv_ffmpeg320.dll”和“opencv_ffmpeg320_64.dll”文件粘贴到该文件夹。

关闭并重新启动Spyder后,代码正常工作。我不确定这三种方法中哪一种有效,我也懒得回去研究。但它确实有效,干杯!