let page,limit,skip,lastPage, query;
 page = req.params.page *1 || 1;  //This is the page,fetch from the server
 limit = req.params.limit * 1 || 1; //  This is the limit ,it also fetch from the server
 skip = (page - 1) * limit;   // Number of skip document
 lastPage = page * limit;   //last index 
 counts = await userModel.countDocuments() //Number of document in the collection

query = query.skip(skip).limit(limit) //current page

const paginate = {}

//For previous page
if(skip > 0) {
   paginate.prev = {
       page: page - 1,
       limit: limit
} 
//For next page
 if(lastPage < counts) {
  paginate.next = {
     page: page + 1,
     limit: limit
}
results = await query //Here is the final results of the query.

您可以使用skip()和limit()，但效率非常低。更好的解决方案是对索引字段加上limit()进行排序。 我们在Wunderflats发布了一个小库:https://github.com/wunderflats/goosepage 它用了第一种方法。

使用猫鼬，快递和翡翠的分页-这里有一个链接到我的博客与更多的细节

var perPage = 10
  , page = Math.max(0, req.params.page)

Event.find()
    .select('name')
    .limit(perPage)
    .skip(perPage * page)
    .sort({
        name: 'asc'
    })
    .exec(function(err, events) {
        Event.count().exec(function(err, count) {
            res.render('events', {
                events: events,
                page: page,
                pages: count / perPage
            })
        })
    })

下面的代码是为我工作良好。 你也可以在countDocs查询中添加查找过滤器和user same来获得准确的结果。

export const yourController = async (req, res) => {
  const { body } = req;

  var perPage = body.limit,
  var page = Math.max(0, body.page);

  yourModel
    .find() // You Can Add Your Filters inside
    .limit(perPage)
    .skip(perPage * (page - 1))
    .exec(function (err, dbRes) {
      yourModel.count().exec(function (err, count) { // You Can Add Your Filters inside
        res.send(
          JSON.stringify({
            Articles: dbRes,
            page: page,
            pages: count / perPage,
          })
        );
      });
    });
};

简单而强大的分页解决方案

async getNextDocs(no_of_docs_required: number = 5, last_doc_id?: string) {
    let docs

    if (!last_doc_id) {
        // get first 5 docs
        docs = await MySchema.find().sort({ _id: -1 }).limit(no_of_docs_required)
    }
    else {
        // get next 5 docs according to that last document id
        docs = await MySchema.find({_id: {$lt: last_doc_id}})
                                    .sort({ _id: -1 }).limit(no_of_docs_required)
    }
    return docs
}

Last_doc_id:您获得的最后一个文档id

No_of_docs_required:你想要获取的文档数量，例如5、10、50等。

如果你不提供last_doc_id给方法，你会得到5个最新的文档 如果你提供了last_doc_id，那么你会得到下一个，即5个文档。

const ITEMS_PER_PAGE = 2;

exports.getProducts = (req, res, next) => {
  // + will turn the string to a number
  const page = +req.query.page || 1;
  let totalItems;
  //Product model
  Product.find()
    .countDocuments()
    .then((numProducts) => {
      totalItems = numProducts;
      return Product.find()
         //If query param is 3, since ITEMS_PER_PAGE = 2, we skip 2*2 items   
         // we show only 5th and 6th item
        .skip((page - 1) * ITEMS_PER_PAGE)
        .limit(ITEMS_PER_PAGE);
    })
    .then((products) => {
      res.render("shop/products", {
        // maybe sending the products object to templating engine
      });
    })
    .catch((err) => {
      const error = new Error(err);
      error.httpStatusCode = 500;
      // if you are set express error handler, use this
      // when we call next() with an argument passed in, we let express know, we skip all other middlewares, we move to error handling middleware

      return next(error);
    });
};