可以使用Object.defineProperty()来重新定义输入元素的“value”属性，并在其更改期间执行任何操作。

Object.defineProperty()允许我们为属性定义getter和setter，从而控制它。

replaceWithWrapper($("#hid1")[0], "value", function(obj, property, value) { 
  console.log("new value:", value)
});

function replaceWithWrapper(obj, property, callback) {
  Object.defineProperty(obj, property, new function() {
    var _value = obj[property];
    return {
      set: function(value) {
        _value = value;
        callback(obj, property, value)
      },
      get: function() {
        return _value;
      }
    }
  });
}

$("#hid1").val(4);

https://jsfiddle.net/bvvmhvfk/

根据Viktar的回答，这里有一个实现，你可以在给定的隐藏输入元素上调用一次，以确保当输入元素的值发生变化时，后续的更改事件会被触发:

/**
 * Modifies the provided hidden input so value changes to trigger events.
 *
 * After this method is called, any changes to the 'value' property of the
 * specified input will trigger a 'change' event, just like would happen
 * if the input was a text field.
 *
 * As explained in the following SO post, hidden inputs don't normally
 * trigger on-change events because the 'blur' event is responsible for
 * triggering a change event, and hidden inputs aren't focusable by virtue
 * of being hidden elements:
 * https://stackoverflow.com/a/17695525/4342230
 *
 * @param {HTMLInputElement} inputElement
 *   The DOM element for the hidden input element.
 */
function setupHiddenInputChangeListener(inputElement) {
  const propertyName = 'value';

  const {get: originalGetter, set: originalSetter} =
    findPropertyDescriptor(inputElement, propertyName);

  // We wrap this in a function factory to bind the getter and setter values
  // so later callbacks refer to the correct object, in case we use this
  // method on more than one hidden input element.
  const newPropertyDescriptor = ((_originalGetter, _originalSetter) => {
    return {
      set: function(value) {
        const currentValue = originalGetter.call(inputElement);

        // Delegate the call to the original property setter
        _originalSetter.call(inputElement, value);

        // Only fire change if the value actually changed.
        if (currentValue !== value) {
          inputElement.dispatchEvent(new Event('change'));
        }
      },

      get: function() {
        // Delegate the call to the original property getter
        return _originalGetter.call(inputElement);
      }
    }
  })(originalGetter, originalSetter);

  Object.defineProperty(inputElement, propertyName, newPropertyDescriptor);
};

/**
 * Search the inheritance tree of an object for a property descriptor.
 *
 * The property descriptor defined nearest in the inheritance hierarchy to
 * the class of the given object is returned first.
 *
 * Credit for this approach:
 * https://stackoverflow.com/a/38802602/4342230
 *
 * @param {Object} object
 * @param {String} propertyName
 *   The name of the property for which a descriptor is desired.
 *
 * @returns {PropertyDescriptor, null}
 */
function findPropertyDescriptor(object, propertyName) {
  if (object === null) {
    return null;
  }

  if (object.hasOwnProperty(propertyName)) {
    return Object.getOwnPropertyDescriptor(object, propertyName);
  }
  else {
    const parentClass = Object.getPrototypeOf(object);

    return findPropertyDescriptor(parentClass, propertyName);
  }
}

在文档就绪时调用这个，如下所示:

$(document).ready(function() {
  setupHiddenInputChangeListener($('myinput')[0]);
});

所以这已经很晚了，但我已经找到了一个答案，以防它对任何遇到这条线索的人有用。

改变隐藏元素的值不会自动触发.change()事件。所以，无论你在哪里设置这个值，你都必须告诉jQuery去触发它。

function setUserID(myValue) {
     $('#userid').val(myValue)
                 .trigger('change');
}

一旦这样，

$('#userid').change(function(){
      //fire your ajax call  
})

应该按预期工作。

你可以简单地使用下面的函数，你也可以改变类型元素。

 $("input[type=hidden]").bind("change", function() {
       alert($(this).val()); 
 });

改变隐藏元素的值不会自动触发.change()事件。所以，无论你在哪里设置这个值，你都必须告诉jQuery去触发它。

超文本标记语言

 <div id="message"></div>
<input type="hidden" id="testChange" value="0"  />    

JAVASCRIPT

var $message = $('#message');
var $testChange = $('#testChange');
var i = 1;

function updateChange() {
    $message.html($message.html() + '<p>Changed to ' + $testChange.val() + '</p>');
}

$testChange.on('change', updateChange);

setInterval(function() {
    $testChange.val(++i).trigger('change');; 
    console.log("value changed" +$testChange.val());
}, 3000);

updateChange();

应该按预期工作。

http://jsfiddle.net/7CM6k/3/

虽然这个帖子已经有3年了，但下面是我的解决方案:

$(function ()
{
    keep_fields_uptodate();
});

function keep_fields_uptodate()
{
    // Keep all fields up to date!
    var $inputDate = $("input[type='date']");
    $inputDate.blur(function(event)
    {
        $("input").trigger("change");
    });
}

我从Vikars的答案开始，但也注意到当在HTML表单中使用隐藏表单字段时，最后的更改没有被提交。后来我找到了托马斯的答案，所以我把两者结合到下面的解决方案中，这似乎很好地适用于我的隐藏表单字段也在提交:

   function replaceWithWrapper(selector, property, callback) {
      function findDescriptor(obj, prop){
         if (obj != null){
            return Object.hasOwnProperty.call(obj, prop)?
               Object.getOwnPropertyDescriptor(obj, prop):
               findDescriptor(Object.getPrototypeOf(obj), prop);
         }
      }

      jQuery(selector).each(function(idx, obj) {
         var {get, set} = findDescriptor(obj, property);

         Object.defineProperty(obj, property, {
            configurable: true,
            enumerable: true,

            get() { //overwrite getter
               var v = get.call(this);  //call the original getter
               //console.log("get '+property+':", v, this);
               return v;
            },
            
            set(v) { //same for setter
               //console.log("set '+property+':", v, this);
               set.call(this, v);
               callback(obj, property, v)
            }
         });
      });
   }

   replaceWithWrapper('#myhiddenfield', 'value', function() {
      console.log('myhiddenfield value changed!');
   });