eumiro的答案更好，但我只是为了多样化而发布这个:

>>> "%08d" % int(bin(6)[2:])
00000110

走老路总是管用的

def intoBinary(number):
binarynumber=""
if (number!=0):
    while (number>=1):
        if (number %2==0):
            binarynumber=binarynumber+"0"
            number=number/2
        else:
            binarynumber=binarynumber+"1"
            number=(number-1)/2

else:
    binarynumber="0"

return "".join(reversed(binarynumber))

更简单的方法

my_num = 6
print(f'{my_num:b}')

简单的递归代码:

 def bin(n,number=('')):
   if n==0:
     return(number)
   else:
     number=str(n%2)+number
     n=n//2
     return bin(n,number)

有点糊弄的方法…

>>> bin8 = lambda x : ''.join(reversed( [str((x >> i) & 1) for i in range(8)] ) )
>>> bin8(6)
'00000110'
>>> bin8(-3)
'11111101'

只需使用format函数

format(6, "08b")

一般形式是

format(<the_integer>, "<0><width_of_string><format_specifier>")