('0' * 7 + bin(6)[2:])[-8:]

or

right_side = bin(6)[2:]
'0' * ( 8 - len( right_side )) + right_side

('0' * 7 + bin(6)[2:])[-8:]

or

right_side = bin(6)[2:]
'0' * ( 8 - len( right_side )) + right_side

. .或者如果你不确定它应该总是8位，你可以把它作为一个参数传递:

>>> '%0*d' % (8, int(bin(6)[2:]))
'00000110'

numpy。binary_repr(num, width=None)有一个神奇的width参数

上面链接的文档中的相关示例:

> > > np。binary_repr(宽度= 4) “0011” 当输入数字为负数并且指定width时，返回2的补数: > > > np。binary_repr(宽度= 5) “11101”

走老路总是管用的

def intoBinary(number):
binarynumber=""
if (number!=0):
    while (number>=1):
        if (number %2==0):
            binarynumber=binarynumber+"0"
            number=number/2
        else:
            binarynumber=binarynumber+"1"
            number=(number-1)/2

else:
    binarynumber="0"

return "".join(reversed(binarynumber))

简单的递归代码:

 def bin(n,number=('')):
   if n==0:
     return(number)
   else:
     number=str(n%2)+number
     n=n//2
     return bin(n,number)