Spring引导——不是托管类型

我使用Spring boot+JPA，在启动服务时遇到了一个问题。

Caused by: java.lang.IllegalArgumentException: Not an managed type: class com.nervytech.dialer.domain.PhoneSettings
    at org.hibernate.jpa.internal.metamodel.MetamodelImpl.managedType(MetamodelImpl.java:219)
    at org.springframework.data.jpa.repository.support.JpaMetamodelEntityInformation.<init>(JpaMetamodelEntityInformation.java:68)
    at org.springframework.data.jpa.repository.support.JpaEntityInformationSupport.getMetadata(JpaEntityInformationSupport.java:65)
    at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getEntityInformation(JpaRepositoryFactory.java:145)
    at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getTargetRepository(JpaRepositoryFactory.java:89)
    at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getTargetRepository(JpaRepositoryFactory.java:69)
    at org.springframework.data.repository.core.support.RepositoryFactorySupport.getRepository(RepositoryFactorySupport.java:177)
    at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.initAndReturn(RepositoryFactoryBeanSupport.java:239)
    at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.afterPropertiesSet(RepositoryFactoryBeanSupport.java:225)
    at org.springframework.data.jpa.repository.support.JpaRepositoryFactoryBean.afterPropertiesSet(JpaRepositoryFactoryBean.java:92)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1625)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1562)

这是Application.java文件，

@Configuration
@ComponentScan
@EnableAutoConfiguration(exclude = { DataSourceAutoConfiguration.class })
@SpringBootApplication
public class DialerApplication {

    public static void main(String[] args) {
        SpringApplication.run(DialerApplication.class, args);
    }
}

我使用UCp进行连接池，数据源配置如下:

@Configuration
@ComponentScan
@EnableTransactionManagement
@EnableAutoConfiguration
@EnableJpaRepositories(entityManagerFactoryRef = "dialerEntityManagerFactory", transactionManagerRef = "dialerTransactionManager", basePackages = { "com.nervy.dialer.spring.jpa.repository" })
public class ApplicationDataSource {

    /** The Constant LOGGER. */
    private static final Logger LOGGER = LoggerFactory
            .getLogger(ApplicationDataSource.class);

    /** The Constant TEST_SQL. */
    private static final String TEST_SQL = "select 1 from dual";

    /** The pooled data source. */
    private PoolDataSource pooledDataSource;

UserDetailsService实现,

@Service("userDetailsService")
@SessionAttributes("user")
public class UserDetailsServiceImpl implements UserDetailsService {

    @Autowired
    private UserService userService;

服务层实现，

@Service
public class PhoneSettingsServiceImpl implements PhoneSettingsService {

}

存储库类，

@Repository
public interface PhoneSettingsRepository extends JpaRepository<PhoneSettings, Long> {

}

实体类,

@Entity
@Table(name = "phone_settings", catalog = "dialer")
public class PhoneSettings implements java.io.Serializable {

WebSecurityConfig类,

@Configuration
@EnableWebMvcSecurity
@ComponentScan
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    private UserDetailsServiceImpl userDetailsService;

    /**
     * Instantiates a new web security config.
     */
    public WebSecurityConfig() {

        super();
    }

    /**
     * {@inheritDoc}
     * @see org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter#configure(org.springframework.security.config.annotation.web.builders.HttpSecurity)
     */
    @Override
    protected void configure(HttpSecurity http) throws Exception {

        http.authorizeRequests()
            .antMatchers("/login", "/logoffUser", "/sessionExpired", "/error", "/unauth", "/redirect", "*support*").permitAll()
            .anyRequest().authenticated().and().rememberMe().and().httpBasic()
            .and()
            .csrf()
            .disable().logout().deleteCookies("JSESSIONID").logoutSuccessUrl("/logoff").invalidateHttpSession(true);
    }


    @Autowired
    public void configAuthentication(AuthenticationManagerBuilder auth) throws Exception {

      auth.userDetailsService(userDetailsService).passwordEncoder(new BCryptPasswordEncoder());
    }

}

包装如下:

应用程序类在- com. nerve .dialer中数据源类在- com. nerver .dialer.common中实体类在- com. nerver .dialer.domain 服务类在- com.nervy.dialer.domain.service.impl 控制器在- com.nervy.dialer.spring.controller 存储库类在- com.nervy.dialer.spring.jpa.repository中 WebSecurityConfig在- com.nervy.dialer.spring.security

谢谢

当前回答

您可以使用@EntityScan注释，并提供用于扫描所有jpa实体的实体包。您可以在使用@SpringBootApplication注释的基应用程序类上使用此注释。

如。 @EntityScan(“com.test.springboot.demo.entity”)

2017-09-06 11:06:43

其他回答

我正在使用spring boot 2.0，我通过用@EntityScan替换@ComponentScan来修复这个问题

2018-03-14 14:42:46

另一种解决这个问题的方法是……包含@SpringBootApplication的类的包应该是根包，所有其他包应该是子包。例如:

package com.home

@SpringBootApplication
public class TestApplication{
  springapplication.run....
}
 
package com.home.repo

@Repository
public interface StudentRepo implements JpaRepository<Student, int>{
 ..........
}

package com.home.entity

@Entity
@Table(name = "student")
public class Student{
 ..........
}

2022-01-28 04:23:48

尝试添加以下所有内容，在我的应用程序中，它与tomcat一起工作很好

 @EnableJpaRepositories("my.package.base.*")
 @ComponentScan(basePackages = { "my.package.base.*" })
 @EntityScan("my.package.base.*")

我正在使用spring引导，当我使用嵌入式tomcat时，它可以很好地使用@EntityScan(“my.package.base.*”)，但当我试图将应用程序部署到外部tomcat时，我没有得到我的实体的托管类型错误。

额外的阅读:

@ComponentScan用于扫描所有标记为@控制器、@服务、@存储库、@组件等的组件。

其中@ entitscan用于扫描所有您的实体，这些被标记为@Entity的任何配置JPA在您的应用程序。

2016-01-19 18:59:55

我得到这个错误是因为我愚蠢地写了

公共接口FooBarRepository扩展CrudRepository<FooBarRepository, Long>{…

A brief explanation: One typically creates a FooBarRepository class to manage FooBar objects (often representing data in a table called something like foo_bar.) When extending the CrudRepository to create the specialized repository class, one needs to specify the type that's being managed -- in this case, FooBar. What I mistakenly typed, though, was FooBarRepository rather than FooBar. FooBarRepository is not the type (the class) I'm trying to manage with the FooBarRepository. Therefore, the compiler issues this error.

我用粗体突出显示了输入错误的地方。在我的示例中删除突出显示的单词Repository，代码将被编译。

2019-09-25 18:32:25

下面对我有用。

import static org.springframework.test.web.servlet.request.MockMvcRequestBuilders.get;
import static org.springframework.test.web.servlet.result.MockMvcResultHandlers.print;
import static org.springframework.test.web.servlet.result.MockMvcResultMatchers.status;

import org.apache.catalina.security.SecurityConfig;
import org.junit.Before;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.boot.autoconfigure.domain.EntityScan;
import org.springframework.boot.test.context.SpringBootTest;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.data.jpa.repository.config.EnableJpaRepositories;
import org.springframework.test.context.junit4.SpringRunner;
import org.springframework.test.context.web.WebAppConfiguration;
import org.springframework.test.web.servlet.MockMvc;
import org.springframework.test.web.servlet.setup.MockMvcBuilders;
import org.springframework.web.context.WebApplicationContext;

import com.something.configuration.SomethingConfig;

@RunWith(SpringRunner.class)
@SpringBootTest(classes = { SomethingConfig.class, SecurityConfig.class }) //All your configuration classes
@EnableAutoConfiguration
@WebAppConfiguration // for MVC configuration
@EnableJpaRepositories("com.something.persistence.dataaccess")  //JPA repositories
@EntityScan("com.something.domain.entity.*")  //JPA entities
@ComponentScan("com.something.persistence.fixture") //any component classes you have
public class SomethingApplicationTest {

    @Autowired
    private WebApplicationContext ctx;
    private MockMvc mockMvc;

    @Before
    public void setUp() {
        this.mockMvc = MockMvcBuilders.webAppContextSetup(ctx).build();
    }

    @Test
    public void loginTest() throws Exception {
        this.mockMvc.perform(get("/something/login"))
        .andDo(print()).andExpect(status().isOk());
    }

}

2019-04-05 12:46:33

Spring引导——不是托管类型

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