有没有办法强制maven(2.0.9)将所有依赖项包含在一个jar文件中?

我有一个项目的构建到一个单一的jar文件。我希望依赖的类也能复制到jar中。

更新:我知道我不能只在jar文件中包含一个jar文件。我正在寻找一种方法来解包指定为依赖项的jar,并将类文件打包到我的jar中。


当前回答

我对月食Luna和m2eclipse的最终解决方案: 自定义类加载器(下载并添加到您的项目,只有5个类) : http://git.eclipse.org/c/jdt/eclipse.jdt.ui.git/plain/org.eclipse.jdt.ui/jar%20in%20jar%20loader/org/eclipse/jdt/internal/jarinjarloader/; 这个类加载器是单jar类加载器中最好的,而且非常快;

< project.mainClass > org.eclipse.jdt.internal.jarinjarloader.JarRsrcLoader < / project.mainClass > < project.realMainClass > my.Class < / project.realMainClass >

编辑JIJConstants“Rsrc-Class-Path”为“Class-Path” MVN清洁依赖:复制依赖包 是创建一个jar与依赖lib文件夹与一个瘦类加载器

<build>
    <resources>
        <resource>
            <directory>src/main/java</directory>
            <includes>
                <include>**/*.java</include>
                <include>**/*.properties</include>
            </includes>
        </resource>
        <resource>
            <directory>src/main/resources</directory>
            <filtering>true</filtering>
            <includes>
                <include>**/*</include>
            </includes>
            <targetPath>META-INF/</targetPath>
        </resource>
        <resource>
            <directory>${project.build.directory}/dependency/</directory>
            <includes>
                <include>*.jar</include>
            </includes>
            <targetPath>lib/</targetPath>
        </resource>
    </resources>
<pluginManagement>
        <plugins>

            <plugin>
                <groupId>org.apache.maven.plugins</groupId>
                <artifactId>maven-jar-plugin</artifactId>
                <configuration>
                    <archive>
                        <manifest>
                            <addClasspath>true</addClasspath>
                            <mainClass>${project.mainClass}</mainClass>
                            <classpathPrefix>lib/</classpathPrefix>
                        </manifest>

                        <manifestEntries>
                            <Rsrc-Main-Class>${project.realMainClass}  </Rsrc-Main-Class>
                            <Class-Path>./</Class-Path>
                        </manifestEntries>

                    </archive>
                </configuration>
            </plugin>
<plugin>
                <groupId>org.apache.maven.plugins</groupId>
                <artifactId>maven-dependency-plugin</artifactId>
                <executions>
                    <execution>
                        <id>copy-dependencies</id>
                        <phase>package</phase>
                        <goals>
                            <goal>copy-dependencies</goal>
                        </goals>
                    </execution>
                </executions>
            </plugin>
        </plugins>
    </pluginManagement>
</build>

其他回答

我发现这是最明确的答案;这里的其他答案是缺少一些对我来说不明显的东西,例如MVN清洁包命令,以及单独添加插件作为依赖项。所有这些对于更习惯的专业用户来说可能是显而易见的。

https://howtodoinjava.com/maven/executable-jar-with-dependencies/

看看这个答案:

I am creating an installer that runs as a Java JAR file and it needs to unpack WAR and JAR files into appropriate places in the installation directory. The dependency plugin can be used in the package phase with the copy goal and it will download any file in the Maven repository (including WAR files) and write them where ever you need them. I changed the output directory to ${project.build.directory}/classes and then end result is that the normal JAR task includes my files just fine. I can then extract them and write them into the installation directory.

<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-dependency-plugin</artifactId>
<executions>
    <execution>
        <id>getWar</id>
        <phase>package</phase>
        <goals>
            <goal>copy</goal>
        </goals>
        <configuration>
            <artifactItems>
                <artifactItem>
                    <groupId>the.group.I.use</groupId>
                    <artifactId>MyServerServer</artifactId>
                    <version>${env.JAVA_SERVER_REL_VER}</version>
                    <type>war</type>
                    <destFileName>myWar.war</destFileName>
                </artifactItem>
            </artifactItems>
            <outputDirectory>${project.build.directory}/classes</outputDirectory>
        </configuration>
    </execution>
</executions>

你可以使用带有"jar-with-dependencies"描述符的maven-assembly插件来做到这一点。下面是我们的pom.xml的相关代码块:

  <build>
    <plugins>
      <!-- any other plugins -->
      <plugin>
        <artifactId>maven-assembly-plugin</artifactId>
        <executions>
          <execution>
            <phase>package</phase>
            <goals>
              <goal>single</goal>
            </goals>
          </execution>
        </executions>
        <configuration>
          <descriptorRefs>
            <descriptorRef>jar-with-dependencies</descriptorRef>
          </descriptorRefs>
        </configuration>
      </plugin>
    </plugins>
  </build>

我试图做一些类似的事情,但我不希望所有的罐子都包括在内。我想从给定的依赖项中包含一些特定的目录。另外,分类器标签已经被占用,所以我不能做:

<dependencies>
    <dependency>
        <groupId>your.group.id</groupId>
        <artifactId>your.artifact.id</artifactId>
        <version>1.0</version>
        <type>jar</type>
        <classifier>jar-with-dependencies</classifier>
    </dependency>
</dependencies>

我使用maven-dependency-plugin和unpack goal 并将我想要的内容解压缩到${project.build。目录}/类,否则将省略 因为它在classes目录中,maven最终将它放在jar中

<plugin>
    <groupId>org.apache.maven.plugins</groupId>
    <artifactId>maven-dependency-plugin</artifactId>
    <executions>
        <execution>
            <id>unpack</id>
            <phase>prepare-package</phase>
            <goals>
                <goal>unpack</goal>
            </goals>
            <configuration>
                <artifactItems>
                    <artifactItem>
                        <groupId>my.group</groupId>
                        <artifactId>my.artifact</artifactId>
                        <classifier>occupied</classifier>
                        <version>1.0</version>
                        <type>jar</type>
                    </artifactItem>
                </artifactItems>
                <outputDirectory>${project.build.directory}/classes</outputDirectory>
                <includes>aaa/**, bbb/**, ccc/**</includes>
            </configuration>
        </execution>
    </executions>
</plugin>

如果你(像我一样)不是特别喜欢上面描述的带依赖的罐子方法, 我更喜欢的maven解决方案是简单地建立一个war项目, 即使你只是在构建一个独立的Java应用程序:

Make a normal maven jar-project, that will build your jar-file (without the dependencies). Also, setup a maven war-project (with only an empty src/main/webapp/WEB-INF/web.xml file, which will avoid a warning/error in the maven-build), that only has your jar-project as a dependency, and make your jar-project a <module> under your war-project. (This war-project is only a simple trick to wrap all your jar-file dependencies into a zip-file.) Build the war-project to produce the war-file. In the deployment-step, simply rename your .war-file to *.zip and unzip it.

你现在应该有一个lib目录(你可以移动到你想要的地方),里面有你的jar和运行应用程序所需的所有依赖项:

java -cp 'path/lib/*' MainClass

(类路径中的通配符在Java-6或更高版本中有效)

我认为这样在maven中设置起来更简单(不需要使用汇编插件),而且可以更清楚地看到应用程序结构(您将在普通视图中看到所有依赖jar的版本号,并避免将所有内容都塞进一个jar文件中)。