我需要在控制台应用程序中运行多个异步任务,并在进一步处理之前等待它们全部完成。

有很多文章,但我似乎越读越困惑。我已经阅读并理解了Task库的基本原理,但我显然在某个地方遗漏了一个链接。

我知道可以将任务串联起来,这样它们就可以在另一个任务完成后开始(这几乎是我读过的所有文章的场景),但我希望所有任务同时运行,并且我想知道它们都完成后的情况。

对于这样的场景,最简单的实现是什么?


当前回答

我所见过的最佳选择是以下扩展方法:

public static Task ForEachAsync<T>(this IEnumerable<T> sequence, Func<T, Task> action) {
    return Task.WhenAll(sequence.Select(action));
}

这样叫它:

await sequence.ForEachAsync(item => item.SomethingAsync(blah));

或者使用async lambda:

await sequence.ForEachAsync(async item => {
    var more = await GetMoreAsync(item);
    await more.FrobbleAsync();
});

其他回答

您希望将任务链接起来,还是可以以并行的方式调用它们?

的链接 就像这样

Task.Run(...).ContinueWith(...).ContinueWith(...).ContinueWith(...);
Task.Factory.StartNew(...).ContinueWith(...).ContinueWith(...).ContinueWith(...);

不要忘记检查每个ContinueWith中的前一个Task实例,因为它可能有错误。

对于平行方式 我遇到的最简单的方法是:平行。调用 除此之外还有任务。WaitAll或者你甚至可以使用WaitHandles来做一个倒数到零的动作(等待,有一个新的类:CountdownEvent),或者…

我所见过的最佳选择是以下扩展方法:

public static Task ForEachAsync<T>(this IEnumerable<T> sequence, Func<T, Task> action) {
    return Task.WhenAll(sequence.Select(action));
}

这样叫它:

await sequence.ForEachAsync(item => item.SomethingAsync(blah));

或者使用async lambda:

await sequence.ForEachAsync(async item => {
    var more = await GetMoreAsync(item);
    await more.FrobbleAsync();
});

你可以使用WhenAll,它将返回一个可等待的任务,或者WaitAll,它没有返回类型,将阻止进一步的代码执行,类似于线程。休眠,直到所有任务都完成、取消或出错。

WhenAll WaitAll
Any of the supplied tasks completes in a faulted state A task with the faulted state will be returned. The exceptions will contain the aggregation of the set of unwrapped exceptions from each of the supplied tasks. An AggregateException will be thrown.
None of the supplied tasks faulted but at least one of them was canceled The returned task will end in the TaskStatus.Canceled state An AggregateException will be thrown which contains an OperationCanceledException in its InnerExceptions collection
An empty list was given An ArgumentException will be thrown The returned task will immediately transition to a TaskStatus.RanToCompletion State before it's returned to the caller.
Doesn't block the current thread Blocks the current thread

例子

var tasks = new Task[] {
    TaskOperationOne(),
    TaskOperationTwo()
};

Task.WaitAll(tasks);
// or
await Task.WhenAll(tasks);

如果你想以特定的顺序运行任务,你可以从这个答案中得到灵感。

如果你正在使用async/await模式,你可以像这样并行运行几个任务:

public async Task DoSeveralThings()
{
    // Start all the tasks
    Task first = DoFirstThingAsync();
    Task second = DoSecondThingAsync();

    // Then wait for them to complete
    var firstResult = await first;
    var secondResult = await second;
}

我准备了一段代码,向您展示如何在这些场景中使用该任务。

    // method to run tasks in a parallel 
    public async Task RunMultipleTaskParallel(Task[] tasks) {

        await Task.WhenAll(tasks);
    }
    // methode to run task one by one 
    public async Task RunMultipleTaskOneByOne(Task[] tasks)
    {
        for (int i = 0; i < tasks.Length - 1; i++)
            await tasks[i];
    }
    // method to run i task in parallel 
    public async Task RunMultipleTaskParallel(Task[] tasks, int i)
    {
        var countTask = tasks.Length;
        var remainTasks = 0;
        do
        {
            int toTake = (countTask < i) ? countTask : i;
            var limitedTasks = tasks.Skip(remainTasks)
                                    .Take(toTake);
            remainTasks += toTake;
            await RunMultipleTaskParallel(limitedTasks.ToArray());
        } while (remainTasks < countTask);
    }