public String getRealPathFromURI（Uri uri） {

    String result;
    Cursor cursor = getContentResolver().query(uri, null, null, null, null);
    if (cursor == null) {
        result = uri.getPath();
        cursor.close();
        return result;
    }
    cursor.moveToFirst();
    int idx = cursor.getColumnIndex(MediaStore.Images.ImageColumns.DATA);
    result = cursor.getString(idx);
    cursor.close();
    return result;
}

然后使用从URI中获取文件:

        File finalFile = newFile(getRealPathFromURI(uri));

——希望能帮到你----

使用这个来写入文件，它为我工作时，gif的uri是由GBoard提供的，我必须在我的应用程序数据复制该gif。

    try {
      String destinationFilePath = getExternalFilesDir("gifs") + "/tempFile.txt";
      InputStream inputStream = getContentResolver().openInputStream(uri);
      OutputStream outputStream = new FileOutputStream(destinationFilePath);

      byte[] buffer = new byte[1024];
      int bytesRead;

      while ((bytesRead = inputStream.read(buffer)) != -1) {
        outputStream.write(buffer, 0, bytesRead);
      }

      inputStream.close();
      outputStream.close();
    }
    catch (Exception e) {
      e.printStackTrace();
    }

你可以使用这个函数从uri中获取文件在新的android和旧的

fun getFileFromUri(context: Context, uri: Uri?): File? {
    uri ?: return null
    uri.path ?: return null

    var newUriString = uri.toString()
    newUriString = newUriString.replace(
        "content://com.android.providers.downloads.documents/",
        "content://com.android.providers.media.documents/"
    )
    newUriString = newUriString.replace(
        "/msf%3A", "/image%3A"
    )
    val newUri = Uri.parse(newUriString)

    var realPath = String()
    val databaseUri: Uri
    val selection: String?
    val selectionArgs: Array<String>?
    if (newUri.path?.contains("/document/image:") == true) {
        databaseUri = MediaStore.Images.Media.EXTERNAL_CONTENT_URI
        selection = "_id=?"
        selectionArgs = arrayOf(DocumentsContract.getDocumentId(newUri).split(":")[1])
    } else {
        databaseUri = newUri
        selection = null
        selectionArgs = null
    }
    try {
        val column = "_data"
        val projection = arrayOf(column)
        val cursor = context.contentResolver.query(
            databaseUri,
            projection,
            selection,
            selectionArgs,
            null
        )
        cursor?.let {
            if (it.moveToFirst()) {
                val columnIndex = cursor.getColumnIndexOrThrow(column)
                realPath = cursor.getString(columnIndex)
            }
            cursor.close()
        }
    } catch (e: Exception) {
        Log.i("GetFileUri Exception:", e.message ?: "")
    }
    val path = realPath.ifEmpty {
        when {
            newUri.path?.contains("/document/raw:") == true -> newUri.path?.replace(
                "/document/raw:",
                ""
            )
            newUri.path?.contains("/document/primary:") == true -> newUri.path?.replace(
                "/document/primary:",
                "/storage/emulated/0/"
            )
            else -> return null
        }
    }
    return if (path.isNullOrEmpty()) null else File(path)
}

扩展基于@Jacek kwiecievik回答转换图像uri文件

fun Uri.toImageFile(context: Context): File? {
    val filePathColumn = arrayOf(MediaStore.Images.Media.DATA)
    val cursor = context.contentResolver.query(this, filePathColumn, null, null, null)
    if (cursor != null) {
        if (cursor.moveToFirst()) {
            val columnIndex = cursor.getColumnIndex(filePathColumn[0])
            val filePath = cursor.getString(columnIndex)
            cursor.close()
            return File(filePath)
        }
        cursor.close()
    }
    return null
}

如果我们使用File(uri.getPath())，它将不起作用

如果我们使用扩展从android-ktx，它仍然不能工作，因为 https://github.com/android/android-ktx/blob/master/src/main/java/androidx/core/net/Uri.kt

科特林 2022

suspend fun Context.createFileFromAsset(assetName: String, fileName: String): File? {
    return withContext(Dispatchers.IO) {
        runCatching {
            val stream = assets.open(assetName)
            val file = File(cacheDir.absolutePath, fileName)
            org.apache.commons.io.FileUtils.copyInputStreamToFile(stream, file)
            file
        }.onFailure { Timber.e(it) }.getOrNull()
    }
}

处理完文件后，请确保对其调用.delete()。向@Mohsent致敬

编辑:对不起，我之前应该测试得更好。这应该可以工作:

new File(new URI(androidURI.toString()));

URI是java.net.URI。