我们也有类似的问题，于是我们想出了这个逻辑 我已经测试了1年的测试用例，并且全部通过

import datetime


def week_of_month(dt):

    first_day = dt.replace(day=1)
    dom = dt.day
    if first_day.weekday() == 6:
        adjusted_dom = dom
    else:
        adjusted_dom = dom + first_day.weekday()
    if adjusted_dom % 7 == 0 and first_day.weekday() != 6:
       value = adjusted_dom / 7.0 + 1
    elif first_day.weekday() == 6 and adjusted_dom % 7 == 0 and adjusted_dom == 7:
        value = 1
    else:
        value = int(ceil(adjusted_dom / 7.0))

    return int(value)


year = 2020
month = 01
date = 01

date_value = datetime.datetime(year, month, date).date()
no = week_of_month(date_value)

一般要获取当前周数(从周日开始):

from datetime import *
today = datetime.today()
print today.strftime("%U")

我们也有类似的问题，于是我们想出了这个逻辑 我已经测试了1年的测试用例，并且全部通过

import datetime


def week_of_month(dt):

    first_day = dt.replace(day=1)
    dom = dt.day
    if first_day.weekday() == 6:
        adjusted_dom = dom
    else:
        adjusted_dom = dom + first_day.weekday()
    if adjusted_dom % 7 == 0 and first_day.weekday() != 6:
       value = adjusted_dom / 7.0 + 1
    elif first_day.weekday() == 6 and adjusted_dom % 7 == 0 and adjusted_dom == 7:
        value = 1
    else:
        value = int(ceil(adjusted_dom / 7.0))

    return int(value)


year = 2020
month = 01
date = 01

date_value = datetime.datetime(year, month, date).date()
no = week_of_month(date_value)

有许多周编号系统。下面是最常见的系统代码示例:

ISO: First week starts with Monday and must contain the January 4th (or first Thursday of the year). The ISO calendar is already implemented in Python: >>> from datetime import date >>> date(2014, 12, 29).isocalendar()[:2] (2015, 1) North American: First week starts with Sunday and must contain the January 1st. The following code is my modified version of Python's ISO calendar implementation for the North American system: from datetime import date def week_from_date(date_object): date_ordinal = date_object.toordinal() year = date_object.year week = ((date_ordinal - _week1_start_ordinal(year)) // 7) + 1 if week >= 52: if date_ordinal >= _week1_start_ordinal(year + 1): year += 1 week = 1 return year, week def _week1_start_ordinal(year): jan1 = date(year, 1, 1) jan1_ordinal = jan1.toordinal() jan1_weekday = jan1.weekday() week1_start_ordinal = jan1_ordinal - ((jan1_weekday + 1) % 7) return week1_start_ordinal >>> from datetime import date >>> week_from_date(date(2014, 12, 29)) (2015, 1) MMWR (CDC): First week starts with Sunday and must contain the January 4th (or first Wednesday of the year). I created the epiweeks package specifically for this numbering system (also has support for the ISO system). Here is an example: >>> from datetime import date >>> from epiweeks import Week >>> Week.fromdate(date(2014, 12, 29)) (2014, 53)

假设您需要将一周与当天的年份组合为字符串。

import datetime
year,week = datetime.date.today().isocalendar()[:2]
week_of_the_year = f"{year}-{week}"
print(week_of_the_year)

你可能会在2021-28年

您可以直接从datetime作为字符串获取周数。

>>> import datetime
>>> datetime.date(2010, 6, 16).strftime("%V")
'24'

你也可以得到不同的“类型”的周数的年份改变strftime参数:

%U - Week number of the year (Sunday as the first day of the week) as a zero padded decimal number. All days in a new year preceding the first Sunday are considered to be in week 0. Examples: 00, 01, …, 53 %W - Week number of the year (Monday as the first day of the week) as a decimal number. All days in a new year preceding the first Monday are considered to be in week 0. Examples: 00, 01, …, 53 [...] (Added in Python 3.6, backported to some distribution's Python 2.7's) Several additional directives not required by the C89 standard are included for convenience. These parameters all correspond to ISO 8601 date values. These may not be available on all platforms when used with the strftime() method. [...] %V - ISO 8601 week as a decimal number with Monday as the first day of the week. Week 01 is the week containing Jan 4. Examples: 01, 02, …, 53 from: datetime — Basic date and time types — Python 3.7.3 documentation

我是从这里知道的。它在Python 2.7.6中对我有效