如何用Python找出今年6月16日(wk24)的周数?
当前回答
如果你想改变一周的第一天,你可以使用日历模块。
import calendar
import datetime
calendar.setfirstweekday(calendar.WEDNESDAY)
isodate = datetime.datetime.strptime(sweek,"%Y-%m-%d").isocalendar()
week_of_year = isodate[1]
例如,计算从周三开始的一周的冲刺数:
def calculate_sprint(sweek):
calendar.setfirstweekday(calendar.WEDNESDAY)
isodate=datetime.datetime.strptime(sweek,"%Y-%m-%d").isocalendar()
return "{year}-{month}".format(year=isodate[0], month=isodate[1])
calculate_sprint('2021-01-01')
>>>'2020-53'
其他回答
我们也有类似的问题,于是我们想出了这个逻辑 我已经测试了1年的测试用例,并且全部通过
import datetime
def week_of_month(dt):
first_day = dt.replace(day=1)
dom = dt.day
if first_day.weekday() == 6:
adjusted_dom = dom
else:
adjusted_dom = dom + first_day.weekday()
if adjusted_dom % 7 == 0 and first_day.weekday() != 6:
value = adjusted_dom / 7.0 + 1
elif first_day.weekday() == 6 and adjusted_dom % 7 == 0 and adjusted_dom == 7:
value = 1
else:
value = int(ceil(adjusted_dom / 7.0))
return int(value)
year = 2020
month = 01
date = 01
date_value = datetime.datetime(year, month, date).date()
no = week_of_month(date_value)
iscalendar()对于某些日期返回错误的年和周数值:
Python 2.7.3 (default, Feb 27 2014, 19:58:35)
[GCC 4.6.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import datetime as dt
>>> myDateTime = dt.datetime.strptime("20141229T000000.000Z",'%Y%m%dT%H%M%S.%fZ')
>>> yr,weekNumber,weekDay = myDateTime.isocalendar()
>>> print "Year is " + str(yr) + ", weekNumber is " + str(weekNumber)
Year is 2015, weekNumber is 1
与Mark Ransom的方法相比:
>>> yr = myDateTime.year
>>> weekNumber = ((myDateTime - dt.datetime(yr,1,1)).days/7) + 1
>>> print "Year is " + str(yr) + ", weekNumber is " + str(weekNumber)
Year is 2014, weekNumber is 52
有许多周编号系统。下面是最常见的系统代码示例:
ISO: First week starts with Monday and must contain the January 4th (or first Thursday of the year). The ISO calendar is already implemented in Python: >>> from datetime import date >>> date(2014, 12, 29).isocalendar()[:2] (2015, 1) North American: First week starts with Sunday and must contain the January 1st. The following code is my modified version of Python's ISO calendar implementation for the North American system: from datetime import date def week_from_date(date_object): date_ordinal = date_object.toordinal() year = date_object.year week = ((date_ordinal - _week1_start_ordinal(year)) // 7) + 1 if week >= 52: if date_ordinal >= _week1_start_ordinal(year + 1): year += 1 week = 1 return year, week def _week1_start_ordinal(year): jan1 = date(year, 1, 1) jan1_ordinal = jan1.toordinal() jan1_weekday = jan1.weekday() week1_start_ordinal = jan1_ordinal - ((jan1_weekday + 1) % 7) return week1_start_ordinal >>> from datetime import date >>> week_from_date(date(2014, 12, 29)) (2015, 1) MMWR (CDC): First week starts with Sunday and must contain the January 4th (or first Wednesday of the year). I created the epiweeks package specifically for this numbering system (also has support for the ISO system). Here is an example: >>> from datetime import date >>> from epiweeks import Week >>> Week.fromdate(date(2014, 12, 29)) (2014, 53)
一般要获取当前周数(从周日开始):
from datetime import *
today = datetime.today()
print today.strftime("%U")
对于一年中的瞬时周的整数值,尝试:
import datetime
datetime.datetime.utcnow().isocalendar()[1]
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