我正在创造自己的iPhone游戏的免费版本。我想在免费版本中添加一个按钮,引导用户进入应用商店中的付费版本。如果我使用标准链接
http://itunes.apple.com/WebObjects/MZStore.woa/wa/viewSoftware?id=300136119&mt=8
iPhone首先打开Safari,然后打开应用商店。我使用过其他直接打开应用程序商店的应用程序,所以我知道这是可能的。
什么好主意吗?应用商店的URL方案是什么?
我正在创造自己的iPhone游戏的免费版本。我想在免费版本中添加一个按钮,引导用户进入应用商店中的付费版本。如果我使用标准链接
http://itunes.apple.com/WebObjects/MZStore.woa/wa/viewSoftware?id=300136119&mt=8
iPhone首先打开Safari,然后打开应用商店。我使用过其他直接打开应用程序商店的应用程序,所以我知道这是可能的。
什么好主意吗?应用商店的URL方案是什么?
当前回答
试试这个方法
http://itunes.apple.com/lookup?id=“你的应用ID在这里”返回json。从这里,找到键“trackViewUrl”和值是所需的url。使用这个url(只需将https://替换为itms-apps://)。这工作得很好。
例如,如果你的应用ID是xyz,那么就转到这个链接 http://itunes.apple.com/lookup?id=xyz
然后找到“trackViewUrl”键的url。这是你的应用程序在应用商店的url,在xcode中使用这个url试试这个
NSString *iTunesLink = @"itms-apps://itunes.apple.com/us/app/Your app name/id Your app ID?mt=8&uo=4";
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:iTunesLink]];
谢谢
其他回答
苹果刚刚公布了appstore.com的网址。
https://developer.apple.com/library/ios/qa/qa1633/_index.html
There are three types of App Store Short Links, in two forms, one for iOS apps, another for Mac Apps: Company Name iOS: http://appstore.com/ for example, http://appstore.com/apple Mac: http://appstore.com/mac/ for example, http://appstore.com/mac/apple App Name iOS: http://appstore.com/ for example, http://appstore.com/keynote Mac: http://appstore.com/mac/ for example, http://appstore.com/mac/keynote App by Company iOS: http://appstore.com// for example, http://appstore.com/apple/keynote Mac: http://appstore.com/mac// for example, http://appstore.com/mac/apple/keynote Most companies and apps have a canonical App Store Short Link. This canonical URL is created by changing or removing certain characters (many of which are illegal or have special meaning in a URL (for example, "&")). To create an App Store Short Link, apply the following rules to your company or app name: Remove all whitespace Convert all characters to lower-case Remove all copyright (©), trademark (™) and registered mark (®) symbols Replace ampersands ("&") with "and" Remove most punctuation (See Listing 2 for the set) Replace accented and other "decorated" characters (ü, å, etc.) with their elemental character (u, a, etc.) Leave all other characters as-is. Listing 2 Punctuation characters that must be removed. !¡"#$%'()*+,-./:;<=>¿?@[]^_`{|}~ Below are some examples to demonstrate the conversion that takes place. App Store Company Name examples Gameloft => http://appstore.com/gameloft Activision Publishing, Inc. => http://appstore.com/activisionpublishinginc Chen's Photography & Software => http://appstore.com/chensphotographyandsoftware App Name examples Ocarina => http://appstore.com/ocarina Where’s My Perry? => http://appstore.com/wheresmyperry Brain Challenge™ => http://appstore.com/brainchallenge
从ios6开始正确的方法是使用SKStoreProductViewController类。
斯威夫特5. x:
func openStoreProductWithiTunesItemIdentifier(_ identifier: String) {
let storeViewController = SKStoreProductViewController()
storeViewController.delegate = self
let parameters = [ SKStoreProductParameterITunesItemIdentifier : identifier]
storeViewController.loadProduct(withParameters: parameters) { [weak self] (loaded, error) -> Void in
if loaded {
// Parent class of self is UIViewContorller
self?.present(storeViewController, animated: true, completion: nil)
}
}
}
private func productViewControllerDidFinish(viewController: SKStoreProductViewController) {
viewController.dismiss(animated: true, completion: nil)
}
// Usage:
openStoreProductWithiTunesItemIdentifier("1234567")
斯威夫特3. x:
func openStoreProductWithiTunesItemIdentifier(identifier: String) {
let storeViewController = SKStoreProductViewController()
storeViewController.delegate = self
let parameters = [ SKStoreProductParameterITunesItemIdentifier : identifier]
storeViewController.loadProduct(withParameters: parameters) { [weak self] (loaded, error) -> Void in
if loaded {
// Parent class of self is UIViewContorller
self?.present(storeViewController, animated: true, completion: nil)
}
}
}
func productViewControllerDidFinish(_ viewController: SKStoreProductViewController) {
viewController.dismiss(animated: true, completion: nil)
}
// Usage:
openStoreProductWithiTunesItemIdentifier(identifier: "13432")
你可以像这样获得应用的itunes项目标识符(而不是一个静态标识符):
斯威夫特3.2
var appID: String = infoDictionary["CFBundleIdentifier"]
var url = URL(string: "http://itunes.apple.com/lookup?bundleId=\(appID)")
var data = Data(contentsOf: url!)
var lookup = try? JSONSerialization.jsonObject(with: data!, options: []) as? [AnyHashable: Any]
var appITunesItemIdentifier = lookup["results"][0]["trackId"] as? String
openStoreProductViewController(withITunesItemIdentifier: Int(appITunesItemIdentifier!) ?? 0)
斯威夫特2. x:
func openStoreProductWithiTunesItemIdentifier(identifier: String) {
let storeViewController = SKStoreProductViewController()
storeViewController.delegate = self
let parameters = [ SKStoreProductParameterITunesItemIdentifier : identifier]
storeViewController.loadProductWithParameters(parameters) { [weak self] (loaded, error) -> Void in
if loaded {
// Parent class of self is UIViewContorller
self?.presentViewController(storeViewController, animated: true, completion: nil)
}
}
}
func productViewControllerDidFinish(viewController: SKStoreProductViewController) {
viewController.dismissViewControllerAnimated(true, completion: nil)
}
// Usage
openStoreProductWithiTunesItemIdentifier("2321354")
objective - c:
static NSInteger const kAppITunesItemIdentifier = 324684580;
[self openStoreProductViewControllerWithITunesItemIdentifier:kAppITunesItemIdentifier];
- (void)openStoreProductViewControllerWithITunesItemIdentifier:(NSInteger)iTunesItemIdentifier {
SKStoreProductViewController *storeViewController = [[SKStoreProductViewController alloc] init];
storeViewController.delegate = self;
NSNumber *identifier = [NSNumber numberWithInteger:iTunesItemIdentifier];
NSDictionary *parameters = @{ SKStoreProductParameterITunesItemIdentifier:identifier };
UIViewController *viewController = self.window.rootViewController;
[storeViewController loadProductWithParameters:parameters
completionBlock:^(BOOL result, NSError *error) {
if (result)
[viewController presentViewController:storeViewController
animated:YES
completion:nil];
else NSLog(@"SKStoreProductViewController: %@", error);
}];
[storeViewController release];
}
#pragma mark - SKStoreProductViewControllerDelegate
- (void)productViewControllerDidFinish:(SKStoreProductViewController *)viewController {
[viewController dismissViewControllerAnimated:YES completion:nil];
}
你可以像这样获得kAppITunesItemIdentifier(应用的itunes项目标识符):(而不是一个静态的)
NSDictionary* infoDictionary = [[NSBundle mainBundle] infoDictionary];
NSString* appID = infoDictionary[@"CFBundleIdentifier"];
NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"http://itunes.apple.com/lookup?bundleId=%@", appID]];
NSData* data = [NSData dataWithContentsOfURL:url];
NSDictionary* lookup = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil];
NSString * appITunesItemIdentifier = lookup[@"results"][0][@"trackId"];
[self openStoreProductViewControllerWithITunesItemIdentifier:[appITunesItemIdentifier intValue]];
如果你想链接到开发商的应用,而开发商的名字中有标点符号或空格(例如Development Company, LLC),你的URL是这样的:
itms-apps://itunes.com/apps/DevelopmentCompanyLLC
否则它在iOS 4.3.3上返回“此请求不能被处理”
试试这个方法
http://itunes.apple.com/lookup?id=“你的应用ID在这里”返回json。从这里,找到键“trackViewUrl”和值是所需的url。使用这个url(只需将https://替换为itms-apps://)。这工作得很好。
例如,如果你的应用ID是xyz,那么就转到这个链接 http://itunes.apple.com/lookup?id=xyz
然后找到“trackViewUrl”键的url。这是你的应用程序在应用商店的url,在xcode中使用这个url试试这个
NSString *iTunesLink = @"itms-apps://itunes.apple.com/us/app/Your app name/id Your app ID?mt=8&uo=4";
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:iTunesLink]];
谢谢
尽管这里有很多答案,但没有一个链接到开发者应用程序的建议似乎已经不管用了。
当我上次访问时,我能够使用以下格式让它工作:
itms-apps://itunes.apple.com/developer/developer-name/id123456789
这不再有效,但删除开发人员名称可以:
itms-apps://itunes.apple.com/developer/id123456789