我有以下JSON文本。我如何解析它以获得pageName, pagePic, post_id等的值?
{
"pageInfo": {
"pageName": "abc",
"pagePic": "http://example.com/content.jpg"
},
"posts": [
{
"post_id": "123456789012_123456789012",
"actor_id": "1234567890",
"picOfPersonWhoPosted": "http://example.com/photo.jpg",
"nameOfPersonWhoPosted": "Jane Doe",
"message": "Sounds cool. Can't wait to see it!",
"likesCount": "2",
"comments": [],
"timeOfPost": "1234567890"
}
]
}
除了其他答案,我推荐这个在线开源服务jsonschema2pojo.org,它可以从json或json模式快速生成Java类,用于GSON, Jackson 1。或者Jackson 2.x。例如,如果你有:
{
"pageInfo": {
"pageName": "abc",
"pagePic": "http://example.com/content.jpg"
}
"posts": [
{
"post_id": "123456789012_123456789012",
"actor_id": 1234567890,
"picOfPersonWhoPosted": "http://example.com/photo.jpg",
"nameOfPersonWhoPosted": "Jane Doe",
"message": "Sounds cool. Can't wait to see it!",
"likesCount": 2,
"comments": [],
"timeOfPost": 1234567890
}
]
}
GSON的jsonschema2pojo.org生成:
@Generated("org.jsonschema2pojo")
public class Container {
@SerializedName("pageInfo")
@Expose
public PageInfo pageInfo;
@SerializedName("posts")
@Expose
public List<Post> posts = new ArrayList<Post>();
}
@Generated("org.jsonschema2pojo")
public class PageInfo {
@SerializedName("pageName")
@Expose
public String pageName;
@SerializedName("pagePic")
@Expose
public String pagePic;
}
@Generated("org.jsonschema2pojo")
public class Post {
@SerializedName("post_id")
@Expose
public String postId;
@SerializedName("actor_id")
@Expose
public long actorId;
@SerializedName("picOfPersonWhoPosted")
@Expose
public String picOfPersonWhoPosted;
@SerializedName("nameOfPersonWhoPosted")
@Expose
public String nameOfPersonWhoPosted;
@SerializedName("message")
@Expose
public String message;
@SerializedName("likesCount")
@Expose
public long likesCount;
@SerializedName("comments")
@Expose
public List<Object> comments = new ArrayList<Object>();
@SerializedName("timeOfPost")
@Expose
public long timeOfPost;
}
JSON是这样的:
{
"pageInfo": {
"pageName": "abc",
"pagePic": "http://example.com/content.jpg"
}
}
Java类
class PageInfo {
private String pageName;
private String pagePic;
// Getters and setters
}
将此JSON转换为Java类的代码。
PageInfo pageInfo = JsonPath.parse(jsonString).read("$.pageInfo", PageInfo.class);
Maven
<dependency>
<groupId>com.jayway.jsonpath</groupId>
<artifactId>json-path</artifactId>
<version>2.2.0</version>
</dependency>
你可以使用Jayway JsonPath。下面是一个GitHub链接,包括源代码、pom细节和良好的文档。
https://github.com/jayway/JsonPath
请按照以下步骤操作。
步骤1:使用Maven在类路径中添加jayway JSON路径依赖项,或者下载JAR文件并手动添加它。
<dependency>
<groupId>com.jayway.jsonpath</groupId>
<artifactId>json-path</artifactId>
<version>2.2.0</version>
</dependency>
步骤2:请将输入的JSON保存为本示例的文件。在我的情况下,我将JSON保存为sampleJson.txt。注意,pageInfo和posts之间没有逗号。
步骤3:使用bufferedReader从上面的文件中读取JSON内容,并将其保存为String。
BufferedReader br = new BufferedReader(new FileReader("D:\\sampleJson.txt"));
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
br.close();
String jsonInput = sb.toString();
步骤4:使用jayway JSON解析器解析JSON字符串。
Object document = Configuration.defaultConfiguration().jsonProvider().parse(jsonInput);
第五步:像下面这样阅读细节。
String pageName = JsonPath.read(document, "$.pageInfo.pageName");
String pagePic = JsonPath.read(document, "$.pageInfo.pagePic");
String post_id = JsonPath.read(document, "$.posts[0].post_id");
System.out.println("$.pageInfo.pageName " + pageName);
System.out.println("$.pageInfo.pagePic " + pagePic);
System.out.println("$.posts[0].post_id " + post_id);
输出将是:
$.pageInfo.pageName = abc
$.pageInfo.pagePic = http://example.com/content.jpg
$.posts[0].post_id = 123456789012_123456789012