根據一條線:
s = "Test abc test test abc test test test abc test test abc";
这似乎只是在上面的行中删除ABC的第一次出现:
s = s.replace('abc', '');
如何替代所有事件?
根據一條線:
s = "Test abc test test abc test test test abc test test abc";
这似乎只是在上面的行中删除ABC的第一次出现:
s = s.replace('abc', '');
如何替代所有事件?
当前回答
把它推到发生的数字达到0,如下:
function replaceAll(find, replace, str) {
while (str.indexOf(find) > -1) {
str = str.replace(find, replace);
}
return str;
}
其他回答
2019年11月,新功能被添加到JavaScript, string.prototype.replaceAll()。
目前它仅支持巴比伦,但也许在未来它可以在所有浏览器中实施。
我建议通过将其附加到原型链上,为线类添加一个全球方法。
String.prototype.replaceAll = function(fromReplace, toReplace, {ignoreCasing} = {}) { return this.replace(new RegExp(fromReplace, ignoreCasing ? 'ig': 'g'), toReplace);}
它可以用作:
'stringwithpattern'.replaceAll('pattern', 'new-pattern')
可以用常见的表达方式实现这一点,有几种可以帮助某人:
var word = "this,\\ .is*a*test, '.and? / only / 'a \ test?";
var stri = "This is a test and only a test";
取代所有非阿尔法字符,
console.log(word.replace(/([^a-z])/g,' ').replace(/ +/g, ' '));
Result: [this is a test and only a test]
用一个空间替换多个连续空间,
console.log(stri.replace(/ +/g,' '));
Result: [This is a test and only a test]
取代所有 * 字符,
console.log(word.replace(/\*/g,''));
Result: [this,\ .isatest, '.and? / only / 'a test?]
取代问题标志(?)
console.log(word.replace(/\?/g,'#'));
Result: [this,\ .is*a*test, '.and# / only / 'a test#]
取代引用标志,
console.log(word.replace(/'/g,'#'));
Result: [this,\ .is*a*test, #.and? / only / #a test?]
要取代所有“字符”,
console.log(word.replace(/,/g,''));
Result: [this\ .is*a*test '.and? / only / 'a test?]
替换一个特定的词,
console.log(word.replace(/test/g,''));
Result: [this,\ .is*a*, '.and? / only / 'a ?]
取代Backslash。
console.log(word.replace(/\\/g,''));
Result: [this, .is*a*test, '.and? / only / 'a test?]
以替代前滑,
console.log(word.replace(/\//g,''));
Result: [this,\ .is*a*test, '.and? only 'a test?]
替换所有空间,
console.log(word.replace(/ /g,'#'));
Result: [this,\#.is*a*test,####'.and?#/#only#/#####'a##test?]
替换点,
console.log(word.replace(/\./g,'#'));
Result: [this,\ #is*a*test, '#and? / only / 'a test?]
String.prototype.replace 所有()
如果你不想处理替代() + RegExp。
但是,如果浏览器在2020年之前?
我推荐的替代All polyfill的选项:
替代All polyfill (与全球旗帜错误) (更多原则版)
if (!String.prototype.replaceAll) { // Check if the native function not exist
Object.defineProperty(String.prototype, 'replaceAll', { // Define replaceAll as a prototype for (Mother/Any) String
configurable: true, writable: true, enumerable: false, // Editable & non-enumerable property (As it should be)
value: function(search, replace) { // Set the function by closest input names (For good info in consoles)
return this.replace( // Using native String.prototype.replace()
Object.prototype.toString.call(search) === '[object RegExp]' // IsRegExp?
? search.global // Is the RegEx global?
? search // So pass it
: function(){throw new TypeError('replaceAll called with a non-global RegExp argument')}() // If not throw an error
: RegExp(String(search).replace(/[.^$*+?()[{|\\]/g, "\\$&"), "g"), // Replace all reserved characters with '\' then make a global 'g' RegExp
replace); // passing second argument
}
});
}
替代All polyfill (With handling global-flag missing by itself) (我的第一个偏好) - 为什么?
if (!String.prototype.replaceAll) { // Check if the native function not exist
Object.defineProperty(String.prototype, 'replaceAll', { // Define replaceAll as a prototype for (Mother/Any) String
configurable: true, writable: true, enumerable: false, // Editable & non-enumerable property (As it should be)
value: function(search, replace) { // Set the function by closest input names (For good info in consoles)
return this.replace( // Using native String.prototype.replace()
Object.prototype.toString.call(search) === '[object RegExp]' // IsRegExp?
? search.global // Is the RegEx global?
? search // So pass it
: RegExp(search.source, /\/([a-z]*)$/.exec(search.toString())[1] + 'g') // If not, make a global clone from the RegEx
: RegExp(String(search).replace(/[.^$*+?()[{|\\]/g, "\\$&"), "g"), // Replace all reserved characters with '\' then make a global 'g' RegExp
replace); // passing second argument
}
});
}
小型(我的第一个偏好):
if(!String.prototype.replaceAll){Object.defineProperty(String.prototype,'replaceAll',{configurable:!0,writable:!0,enumerable:!1,value:function(search,replace){return this.replace(Object.prototype.toString.call(search)==='[object RegExp]'?search.global?search:RegExp(search.source,/\/([a-z]*)$/.exec(search.toString())[1]+'g'):RegExp(String(search).replace(/[.^$*+?()[{|\\]/g,"\\$&"),"g"),replace)}})}
其他方法的聚合物分配
if (!String.prototype.replaceAll) {
String.prototype.replaceAll = function(search, replace) { // <-- Naive method for assignment
// ... (Polyfill code Here)
}
}
for (var k in 'hi') console.log(k);
// 0
// 1
// replaceAll <-- ?
非常可靠,但重
事实上,我提出的选项有点乐观,正如我们信任环境(浏览器和Node.js),它肯定是2012年至2021年左右。
此分類上一篇: HTTPS://polyfill.io
特别是替代:
<script src="https://polyfill.io/v3/polyfill.min.js?features=String.prototype.replaceAll"></script>
试试这:
String.prototype.replaceAll = function (sfind, sreplace) {
var str = this;
while (str.indexOf(sfind) > -1) {
str = str.replace(sfind, sreplace);
}
return str;
};