如果我在Bash中有一个这样的数组:
FOO=( a b c )
如何用逗号连接元素?例如,生成a b c。
如果我在Bash中有一个这样的数组:
FOO=( a b c )
如何用逗号连接元素?例如,生成a b c。
当前回答
现在我用的是:
TO_IGNORE=(
E201 # Whitespace after '('
E301 # Expected N blank lines, found M
E303 # Too many blank lines (pep8 gets confused by comments)
)
ARGS="--ignore `echo ${TO_IGNORE[@]} | tr ' ' ','`"
这是可行的,但是(在一般情况下)如果数组元素中有空格,将会严重破坏。
(对于那些感兴趣的人,这是一个围绕pep8.py的包装器脚本)
其他回答
也许迟到了,但这对我来说是可行的:
function joinArray() {
local delimiter="${1}"
local output="${2}"
for param in ${@:3}; do
output="${output}${delimiter}${param}"
done
echo "${output}"
}
$ set a 'b c' d
$ history -p "$@" | paste -sd,
a,b c,d
我相信这是最短的解决方案,正如Benamin W.已经提到的:
(IFS=,; printf %s "${a[*]}")
想要添加,如果你使用zsh,你可以删除子shell:
IFS=, printf %s "${a[*]}"
测试:
a=(1 'a b' 3)
IFS=, printf %s "${a[*]}"
1,a b,3
感谢@gniourf_gniourf对我迄今为止的最佳世界组合的详细评论。很抱歉发布的代码没有完全设计和测试。这是一个更好的尝试。
# join with separator
join_ws() { local d=$1 s=$2; shift 2 && printf %s "$s${@/#/$d}"; }
这种概念上的美是
(still) 100% pure bash ( thanks for explicitly pointing out that printf is a builtin as well. I wasn't aware about this before ... ) works with multi-character delimiters more compact and more complete and this time carefully thought over and long-term stress-tested with random substrings from shell scripts amongst others, covering use of shell special characters or control characters or no characters in both separator and / or parameters, and edge cases, and corner cases and other quibbles like no arguments at all. That doesn't guarantee there is no more bug, but it will be a little harder challenge to find one. BTW, even the currently top voted answers and related suffer from such things like that -e bug ...
附加的例子:
$ join_ws '' a b c
abc
$ join_ws ':' {1,7}{A..C}
1A:1B:1C:7A:7B:7C
$ join_ws -e -e
-e
$ join_ws $'\033[F' $'\n\n\n' 1. 2. 3. $'\n\n\n\n'
3.
2.
1.
$ join_ws $
$
如果你在循环中构建数组,这里有一个简单的方法:
arr=()
for x in $(some_cmd); do
arr+=($x,)
done
arr[-1]=${arr[-1]%,}
echo ${arr[*]}